我想在某个点暂停我的应用程序。换句话说,我希望我的应用程序执行代码,但在某一点上,暂停4秒,然后继续执行其余的代码。我该怎么做呢?
我用的是Swift。
我想在某个点暂停我的应用程序。换句话说,我希望我的应用程序执行代码,但在某一点上,暂停4秒,然后继续执行其余的代码。我该怎么做呢?
我用的是Swift。
当前回答
要创建一个简单的时间延迟,您可以导入Darwin,然后使用sleep(秒)来执行延迟。不过,这只需要几秒钟的时间,所以为了更精确的测量,你可以导入Darwin并使用usleep(百万分之一秒)进行非常精确的测量。为了验证这一点,我写道:
import Darwin
print("This is one.")
sleep(1)
print("This is two.")
usleep(400000)
print("This is three.")
打印,然后等待1秒打印,然后等待0.4秒打印。一切都如预期般顺利。
其他回答
Using a dispatch_after block is in most cases better than using sleep(time) as the thread on which the sleep is performed is blocked from doing other work. when using dispatch_after the thread which is worked on does not get blocked so it can do other work in the meantime. If you are working on the main thread of your application, using sleep(time) is bad for the user experience of your app as the UI is unresponsive during that time. Dispatch after schedules the execution of a block of code instead of freezing the thread:
斯威夫特≥ 3.0
let seconds = 4.0
DispatchQueue.main.asyncAfter(deadline: .now() + seconds) {
// Put your code which should be executed with a delay here
}
Swift≥5.5(异步):
func foo() async {
try await Task.sleep(nanoseconds: UInt64(seconds * Double(NSEC_PER_SEC)))
// Put your code which should be executed with a delay here
}
Swift < 3.0
let time = dispatch_time(dispatch_time_t(DISPATCH_TIME_NOW), 4 * Int64(NSEC_PER_SEC))
dispatch_after(time, dispatch_get_main_queue()) {
// Put your code which should be executed with a delay here
}
DispatchQueue.global(qos: .background).async {
sleep(4)
print("Active after 4 sec, and doesn't block main")
DispatchQueue.main.async{
//do stuff in the main thread here
}
}
你可以创建扩展来轻松使用延迟函数(语法:Swift 4.2+)
extension UIViewController {
func delay(_ delay:Double, closure:@escaping ()->()) {
DispatchQueue.main.asyncAfter(
deadline: DispatchTime.now() + Double(Int64(delay * Double(NSEC_PER_SEC))) / Double(NSEC_PER_SEC), execute: closure)
}
}
如何在UIViewController中使用
self.delay(0.1, closure: {
//execute code
})
你也可以用Swift 3这样做。
像这样执行延迟后的功能。
override func viewDidLoad() {
super.viewDidLoad()
self.perform(#selector(ClassName.performAction), with: nil, afterDelay: 2.0)
}
@objc func performAction() {
//This function will perform after 2 seconds
print("Delayed")
}
如果你的代码已经在后台线程中运行,在Foundation: thread .sleep(forTimeInterval:)中使用这个方法暂停线程。
例如:
DispatchQueue.global(qos: .userInitiated).async {
// Code is running in a background thread already so it is safe to sleep
Thread.sleep(forTimeInterval: 4.0)
}
(当代码在主线程上运行时,请参阅其他答案以获得建议。)