是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。
当前回答
#import <sys/utsname.h>
NSString *iPhone = [self iPhoneVersion];
-(NSString*)iPhoneVersion
{
NSString *platform;
struct utsname systemInfo;
uname(&systemInfo);
platform = [NSString stringWithCString:systemInfo.machine encoding:NSUTF8StringEncoding];
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,3"]) return @"VerizoniPhone 4";
if ([platform isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
if ([platform isEqualToString:@"iPhone5,1"]) return @"iPhone 5 (GSM)";
if ([platform isEqualToString:@"iPhone5,2"]) return @"iPhone 5 (GSM+CDMA)";
if ([platform isEqualToString:@"iPhone5,3"]) return @"iPhone 5c (GSM)";
if ([platform isEqualToString:@"iPhone5,4"]) return @"iPhone 5c (GSM+CDMA)";
if ([platform isEqualToString:@"iPhone6,1"]) return @"iPhone 5s (GSM)";
if ([platform isEqualToString:@"iPhone6,2"]) return @"iPhone 5s (GSM+CDMA)";
if ([platform isEqualToString:@"iPhone7,2"]) return @"iPhone 6";
if ([platform isEqualToString:@"iPhone7,1"]) return @"iPhone 6 Plus";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";
if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch 4G";
if ([platform isEqualToString:@"iPod5,1"]) return @"iPod Touch 5G";
if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2 (GSM)";
if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";
if ([platform isEqualToString:@"iPad2,4"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,5"]) return @"iPad Mini (WiFi)";
if ([platform isEqualToString:@"iPad2,6"]) return @"iPad Mini (GSM)";
if ([platform isEqualToString:@"iPad2,7"]) return @"iPad Mini (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,1"]) return @"iPad 3 (WiFi)";
if ([platform isEqualToString:@"iPad3,2"]) return @"iPad 3 (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,3"]) return @"iPad 3 (GSM)";
if ([platform isEqualToString:@"iPad3,4"]) return @"iPad 4 (WiFi)";
if ([platform isEqualToString:@"iPad3,5"]) return @"iPad 4 (GSM)";
if ([platform isEqualToString:@"iPad3,6"]) return @"iPad 4 (GSM+CDMA)";
if ([platform isEqualToString:@"iPad4,1"]) return @"iPad Air (WiFi)";
if ([platform isEqualToString:@"iPad4,2"]) return @"iPad Air (Cellular)";
if ([platform isEqualToString:@"iPad4,3"]) return @"iPad Air";
if ([platform isEqualToString:@"iPad4,4"]) return @"iPad Mini 2G (WiFi)";
if ([platform isEqualToString:@"iPad4,5"]) return @"iPad Mini 2G (Cellular)";
if ([platform isEqualToString:@"iPad4,6"]) return @"iPad Mini 2G";
if ([platform isEqualToString:@"iPad4,7"]) return @"iPad Mini 3 (WiFi)";
if ([platform isEqualToString:@"iPad4,8"]) return @"iPad Mini 3 (Cellular)";
if ([platform isEqualToString:@"iPad4,9"]) return @"iPad Mini 3 (China)";
if ([platform isEqualToString:@"iPad5,3"]) return @"iPad Air 2 (WiFi)";
if ([platform isEqualToString:@"iPad5,4"]) return @"iPad Air 2 (Cellular)";
if ([platform isEqualToString:@"AppleTV2,1"]) return @"Apple TV 2G";
if ([platform isEqualToString:@"AppleTV3,1"]) return @"Apple TV 3";
if ([platform isEqualToString:@"AppleTV3,2"]) return @"Apple TV 3 (2013)";
if ([platform isEqualToString:@"i386"]) return @"Simulator";
if ([platform isEqualToString:@"x86_64"]) return @"Simulator";
return platform;
}
其他回答
NSString *deviceType = [UIDevice currentDevice].model;
更有用
#include <sys/types.h>
#include <sys/sysctl.h>
@interface UIDevice(Hardware)
- (NSString *) platform;
- (BOOL)hasRetinaDisplay;
- (BOOL)hasMultitasking;
- (BOOL)hasCamera;
@end
@implementation UIDevice(Hardware)
- (NSString *) platform{
int mib[2];
size_t len;
char *machine;
mib[0] = CTL_HW;
mib[1] = HW_MACHINE;
sysctl(mib, 2, NULL, &len, NULL, 0);
machine = malloc(len);
sysctl(mib, 2, machine, &len, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSASCIIStringEncoding];
free(machine);
return platform;
}
- (BOOL)hasRetinaDisplay {
NSString *platform = [self platform];
BOOL ret = YES;
if ([platform isEqualToString:@"iPhone1,1"]) {
ret = NO;
}
else
if ([platform isEqualToString:@"iPhone1,2"]) ret = NO;
else
if ([platform isEqualToString:@"iPhone2,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod1,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod2,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod3,1"]) ret = NO;
return ret;
}
- (BOOL)hasMultitasking {
if ([self respondsToSelector:@selector(isMultitaskingSupported)]) {
return [self isMultitaskingSupported];
}
return NO;
}
- (BOOL)hasCamera {
BOOL ret = NO;
// check camera availability
return ret;
}
@end
您可以读取属性
NSLog(@"platform %@, retita %@, multitasking %@", [[UIDevice currentDevice] platform], [[UIDevice currentDevice] hasRetinaDisplay] ? @"YES" : @"NO" , [[UIDevice currentDevice] hasMultitasking] ? @"YES" : @"NO");
只是将iPhone 4S设备代码添加到这个线程…
iPhone 4S将返回字符串@"iPhone4,1"。
if([UIDevice currentDevice].userInterfaceIdiom==UIUserInterfaceIdiomPad) {
//Device is ipad
}else{
//Device is iphone
}
下面提到的代码片段应该有帮助:
if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
// iPhone device
}
else if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPad) {
// iPad device
}
else {
// Other device i.e. iPod
}
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