是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。
当前回答
的可能值
[[UIDevice currentDevice] model];
是iPod touch, iPhone, iPhone模拟器,iPad, iPad模拟器
如果你想知道iOS正在破坏哪些硬件,比如iPhone3, iPhone4, iPhone5等,下面是代码
注意:下面的代码可能不包含所有设备的字符串,我和其他人在GitHub上维护相同的代码,所以请从那里获取最新的代码
Objective-C: GitHub/DeviceUtil
吉hub /恶魔大师
#include <sys/types.h>
#include <sys/sysctl.h>
- (NSString*)hardwareDescription {
NSString *hardware = [self hardwareString];
if ([hardware isEqualToString:@"iPhone1,1"]) return @"iPhone 2G";
if ([hardware isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([hardware isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([hardware isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
if ([hardware isEqualToString:@"iPhone5,1"]) return @"iPhone 5";
if ([hardware isEqualToString:@"iPod1,1"]) return @"iPodTouch 1G";
if ([hardware isEqualToString:@"iPod2,1"]) return @"iPodTouch 2G";
if ([hardware isEqualToString:@"iPad1,1"]) return @"iPad";
if ([hardware isEqualToString:@"iPad2,6"]) return @"iPad Mini";
if ([hardware isEqualToString:@"iPad4,1"]) return @"iPad Air WIFI";
//there are lots of other strings too, checkout the github repo
//link is given at the top of this answer
if ([hardware isEqualToString:@"i386"]) return @"Simulator";
if ([hardware isEqualToString:@"x86_64"]) return @"Simulator";
return nil;
}
- (NSString*)hardwareString {
size_t size = 100;
char *hw_machine = malloc(size);
int name[] = {CTL_HW,HW_MACHINE};
sysctl(name, 2, hw_machine, &size, NULL, 0);
NSString *hardware = [NSString stringWithUTF8String:hw_machine];
free(hw_machine);
return hardware;
}
其他回答
为了简单的比较,我总是喜欢宏观:
#define IS_IPOD [[UIDevice currentDevice].model containsString:@"iPod"]
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
它简单易用。
我进一步将大的“isEqualToString”块转换为设备类型、生成和逗号后的其他限定符(我称之为子生成)的位掩码分类。它被包装在一个类中,带有一个单例调用SGPlatform,避免了大量重复的字符串操作。代码可用https://github.com/danloughney/spookyGroup
这个类允许你做这样的事情:
if ([SGPlatform iPad] && [SGPlatform generation] > 3) {
// set for high performance
}
and
switch ([SGPlatform deviceMask]) {
case DEVICE_IPHONE:
break;
case DEVICE_IPAD:
break;
case DEVICE_IPAD_MINI:
break;
}
设备的分类在platformBits方法中。这个方法对于本文的读者来说应该非常熟悉。我根据设备的类型和年代对其进行了分类,因为我最感兴趣的是整体性能,但源代码可以调整以提供您感兴趣的任何分类,如视网膜屏幕、网络功能等。
下面提到的代码片段应该有帮助:
if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
// iPhone device
}
else if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPad) {
// iPad device
}
else {
// Other device i.e. iPod
}
的可能值
[[UIDevice currentDevice] model];
是iPod touch, iPhone, iPhone模拟器,iPad, iPad模拟器
如果你想知道iOS正在破坏哪些硬件,比如iPhone3, iPhone4, iPhone5等,下面是代码
注意:下面的代码可能不包含所有设备的字符串,我和其他人在GitHub上维护相同的代码,所以请从那里获取最新的代码
Objective-C: GitHub/DeviceUtil
吉hub /恶魔大师
#include <sys/types.h>
#include <sys/sysctl.h>
- (NSString*)hardwareDescription {
NSString *hardware = [self hardwareString];
if ([hardware isEqualToString:@"iPhone1,1"]) return @"iPhone 2G";
if ([hardware isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([hardware isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([hardware isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
if ([hardware isEqualToString:@"iPhone5,1"]) return @"iPhone 5";
if ([hardware isEqualToString:@"iPod1,1"]) return @"iPodTouch 1G";
if ([hardware isEqualToString:@"iPod2,1"]) return @"iPodTouch 2G";
if ([hardware isEqualToString:@"iPad1,1"]) return @"iPad";
if ([hardware isEqualToString:@"iPad2,6"]) return @"iPad Mini";
if ([hardware isEqualToString:@"iPad4,1"]) return @"iPad Air WIFI";
//there are lots of other strings too, checkout the github repo
//link is given at the top of this answer
if ([hardware isEqualToString:@"i386"]) return @"Simulator";
if ([hardware isEqualToString:@"x86_64"]) return @"Simulator";
return nil;
}
- (NSString*)hardwareString {
size_t size = 100;
char *hw_machine = malloc(size);
int name[] = {CTL_HW,HW_MACHINE};
sysctl(name, 2, hw_machine, &size, NULL, 0);
NSString *hardware = [NSString stringWithUTF8String:hw_machine];
free(hw_machine);
return hardware;
}
你可以像这样使用UIDevice类:
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType isEqualToString:@"iPhone"])
// it's an iPhone
推荐文章
- Objective-C中方法混合的危险是什么?
- 如何使用接口生成器创建的nib文件加载UIView
- iOS如何设置应用程序图标和启动图像
- 更改UITextField和UITextView光标/插入符颜色
- 'Project Name'是通过优化编译的——步进可能会表现得很奇怪;变量可能不可用
- 如何设置回退按钮文本在Swift
- 模拟器慢动作动画现在打开了吗?
- 如何为TableView创建NSIndexPath
- 滑动删除和“更多”按钮(就像iOS 7的邮件应用程序)
- 如何比较两个nsdate:哪个是最近的?
- 使UINavigationBar透明
- 如何改变推和弹出动画在一个基于导航的应用程序
- 删除/重置核心数据中的所有条目?
- Swift to Objective-C头未在Xcode 6中创建
- setNeedsLayout vs. setNeedsUpdateConstraints和layoutIfNeeded vs. updateConstraintsIfNeeded