是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。
当前回答
这个代码怎么样,如果新版本发布,你将标识与最后知道的设备
- (NSString *)getModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *sDeviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
if ([sDeviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([sDeviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([sDeviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([sDeviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([sDeviceModel isEqual:@"iPhone3,1"]) return @"iPhone3GS"; //iPhone 4 - AT&T
if ([sDeviceModel isEqual:@"iPhone3,2"]) return @"iPhone3GS"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([sDeviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([sDeviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([sDeviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([sDeviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([sDeviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([sDeviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([sDeviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([sDeviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([sDeviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[sDeviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exist
if ([aux rangeOfString:@"iPhone"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4"
if (version >= 4) return @"iPhone4s";
}
if ([aux rangeOfString:@"iPod"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version >=4) return @"iPod4thGen";
}
if ([aux rangeOfString:@"iPad"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version ==1) return @"iPad3G";
if (version >=2) return @"iPad2";
}
//If none was found, send the original string
return sDeviceModel;
}
其他回答
- (BOOL)deviceiPhoneOriPod
{
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType rangeOfString:@"iPhone"].location!=NSNotFound)
return YES;
else
return NO;
}
if([UIDevice currentDevice].userInterfaceIdiom==UIUserInterfaceIdiomPad) {
//Device is ipad
}else{
//Device is iphone
}
你可以在GitHub上查看GBDeviceInfo,也可以通过CocoaPods获得。它提供了简单的API来检测各种属性,支持所有最新的设备:
设备的家庭
[GBDeviceInfo deviceDetails]。family == GBDeviceFamilyiPhone;
设备模型
[GBDeviceInfo deviceDetails]。model == GBDeviceModeliPhone6。
欲了解更多,请参阅Readme。
你可以像这样使用UIDevice类:
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType isEqualToString:@"iPhone"])
// it's an iPhone
下面提到的代码片段应该有帮助:
if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
// iPhone device
}
else if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPad) {
// iPad device
}
else {
// Other device i.e. iPod
}
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