我有这个错误信息:
Msg 8134,级别16,状态1,第1行,除以零错误。
写SQL代码的最好方法是什么,这样我就再也不会看到这个错误消息了?
我可以做以下任何一件事:
添加where子句,使除数永远不为零
Or
我可以添加一个case语句,这样就可以对0进行特殊处理。
使用NULLIF子句是最好的方法吗?
有没有更好的办法,或者如何实施?
我有这个错误信息:
Msg 8134,级别16,状态1,第1行,除以零错误。
写SQL代码的最好方法是什么,这样我就再也不会看到这个错误消息了?
我可以做以下任何一件事:
添加where子句,使除数永远不为零
Or
我可以添加一个case语句,这样就可以对0进行特殊处理。
使用NULLIF子句是最好的方法吗?
有没有更好的办法,或者如何实施?
当前回答
如果你想返回零,如果发生零分割,你可以使用:
SELECT COALESCE(dividend / NULLIF(divisor,0), 0) FROM sometable
对于每一个为0的除数,结果集中都会得到一个0。
其他回答
如果你想返回零,如果发生零分割,你可以使用:
SELECT COALESCE(dividend / NULLIF(divisor,0), 0) FROM sometable
对于每一个为0的除数,结果集中都会得到一个0。
在这种情况下,你可以除以0。商业规则是计算库存周转,你用一段时间内的销售成本,按年计算。在你得到年化数字之后,你要除以该时期的平均库存。
I'm looking at calculating the number of inventory turns that occur in a three month period. I have calculated that I have Cost of Goods sold during the three month period of $1,000. The annual rate of sales is $4,000 ($1,000/3)*12. The beginning inventory is 0. The ending inventory is 0. My average inventory is now 0. I have sales of $4000 per year, and no inventory. This yields an infinite number of turns. This means that all my inventory is being converted and purchased by customers.
这是关于如何计算库存周转的业务规则。
我是这样解决的:
IIF(ValueA != 0, Total / ValueA, 0)
它可以被包装在一个更新中:
SET Pct = IIF(ValueA != 0, Total / ValueA, 0)
或者在选择中:
SELECT IIF(ValueA != 0, Total / ValueA, 0) AS Pct FROM Tablename;
想法吗?
There is no magic global setting 'turn division by 0 exceptions off'. The operation has to to throw, since the mathematical meaning of x/0 is different from the NULL meaning, so it cannot return NULL. I assume you are taking care of the obvious and your queries have conditions that should eliminate the records with the 0 divisor and never evaluate the division. The usual 'gotcha' is than most developers expect SQL to behave like procedural languages and offer logical operator short-circuit, but it does NOT. I recommend you read this article: http://www.sqlmag.com/Articles/ArticleID/9148/pg/2/2.html
用零代替“除零”是有争议的,但这也不是唯一的选择。在某些情况下,用1代替是(合理的)合适的。我经常发现自己吸毒
ISNULL(Numerator/NULLIF(Divisor,0),1)
当我在看分数/计数的变化,并希望默认为1,如果我没有数据。例如
NewScore = OldScore * ISNULL(NewSampleScore/NULLIF(OldSampleScore,0),1)
通常情况下,我实际上在其他地方计算过这个比率(尤其是因为它可以为低分母提供一些非常大的调整因素)。在这种情况下,我通常控制OldSampleScore大于阈值;这就排除了零的可能性。但有时“hack”是合适的。