SELECT Dividend / ISNULL(NULLIF(Divisor,0), 1) AS Result from table

通过使用nullif()捕获零，然后使用isnull()捕获结果为零，可以避免除零错误。

使用NULLIF(exp,0)，但以这种方式- NULLIF(ISNULL(exp,0)，0)

如果exp为空，NULLIF(exp,0)将中断，但NULLIF(ISNULL(exp,0)，0)将不会中断

CREATE FUNCTION dbo.Divide(@Numerator Real, @Denominator Real)
RETURNS Real AS
/*
Purpose:      Handle Division by Zero errors
Description:  User Defined Scalar Function
Parameter(s): @Numerator and @Denominator

Test it:

SELECT 'Numerator = 0' Division, dbo.fn_CORP_Divide(0,16) Results
UNION ALL
SELECT 'Denominator = 0', dbo.fn_CORP_Divide(16,0)
UNION ALL
SELECT 'Numerator is NULL', dbo.fn_CORP_Divide(NULL,16)
UNION ALL
SELECT 'Denominator is NULL', dbo.fn_CORP_Divide(16,NULL)
UNION ALL
SELECT 'Numerator & Denominator is NULL', dbo.fn_CORP_Divide(NULL,NULL)
UNION ALL
SELECT 'Numerator & Denominator = 0', dbo.fn_CORP_Divide(0,0)
UNION ALL
SELECT '16 / 4', dbo.fn_CORP_Divide(16,4)
UNION ALL
SELECT '16 / 3', dbo.fn_CORP_Divide(16,3)

*/
BEGIN
    RETURN
        CASE WHEN @Denominator = 0 THEN
            NULL
        ELSE
            @Numerator / @Denominator
        END
END
GO

如果你想返回零，如果发生零分割，你可以使用:

SELECT COALESCE(dividend / NULLIF(divisor,0), 0) FROM sometable

对于每一个为0的除数，结果集中都会得到一个0。

在这种情况下，你可以除以0。商业规则是计算库存周转，你用一段时间内的销售成本，按年计算。在你得到年化数字之后，你要除以该时期的平均库存。

I'm looking at calculating the number of inventory turns that occur in a three month period. I have calculated that I have Cost of Goods sold during the three month period of $1,000. The annual rate of sales is $4,000 ($1,000/3)*12. The beginning inventory is 0. The ending inventory is 0. My average inventory is now 0. I have sales of $4000 per year, and no inventory. This yields an infinite number of turns. This means that all my inventory is being converted and purchased by customers.

这是关于如何计算库存周转的业务规则。

用零代替“除零”是有争议的，但这也不是唯一的选择。在某些情况下，用1代替是(合理的)合适的。我经常发现自己吸毒

 ISNULL(Numerator/NULLIF(Divisor,0),1)

当我在看分数/计数的变化，并希望默认为1，如果我没有数据。例如

NewScore = OldScore *  ISNULL(NewSampleScore/NULLIF(OldSampleScore,0),1) 

通常情况下，我实际上在其他地方计算过这个比率(尤其是因为它可以为低分母提供一些非常大的调整因素)。在这种情况下，我通常控制OldSampleScore大于阈值;这就排除了零的可能性。但有时“hack”是合适的。