Dir.new('/home/user/foldername').each { |file| puts file }

您还有快捷方式选项

Dir["/path/to/search/*"]

如果你想在任何文件夹或子文件夹中找到所有Ruby文件:

Dir["/path/to/search/**/*.rb"]

Dir.entries(folder)

例子:

Dir.entries(".")

来源:http://ruby-doc.org/core/classes/Dir.html method-c-entries

这段代码只返回带扩展名的文件名(没有全局路径)

Dir.children("/path/to/search/")

= > [file_1。Rb, file_2.html, file_3.js]

这对我来说很管用:

如果你不想要隐藏文件[1]，使用Dir[]:

# With a relative path, Dir[] will return relative paths 
# as `[ './myfile', ... ]`
#
Dir[ './*' ].select{ |f| File.file? f } 

# Want just the filename?
# as: [ 'myfile', ... ]
#
Dir[ '../*' ].select{ |f| File.file? f }.map{ |f| File.basename f }

# Turn them into absolute paths?
# [ '/path/to/myfile', ... ]
#
Dir[ '../*' ].select{ |f| File.file? f }.map{ |f| File.absolute_path f }

# With an absolute path, Dir[] will return absolute paths:
# as: [ '/home/../home/test/myfile', ... ]
#
Dir[ '/home/../home/test/*' ].select{ |f| File.file? f }

# Need the paths to be canonical?
# as: [ '/home/test/myfile', ... ]
#
Dir[ '/home/../home/test/*' ].select{ |f| File.file? f }.map{ |f| File.expand_path f }

现在,Dir。条目将返回隐藏的文件，并且您不需要通配符asterix(您可以直接将目录名传递给变量)，但它将直接返回basename，因此File. xml将返回文件。XXX函数不能工作。

# In the current working dir:
#
Dir.entries( '.' ).select{ |f| File.file? f }

# In another directory, relative or otherwise, you need to transform the path 
# so it is either absolute, or relative to the current working dir to call File.xxx functions:
#
home = "/home/test"
Dir.entries( home ).select{ |f| File.file? File.join( home, f ) }

[1] .dotfile在unix上，我不知道Windows上

下面的代码片段精确地显示了目录内的文件名称，跳过子目录和“。”，“..”带点的文件夹:

Dir.entries("your/folder").select { |f| File.file? File.join("your/folder", f) }