下面的代码段应该可以做到这一点(你可以忽略大部分序列化属性):

public class Car
{
  public string StockNumber { get; set; }
  public string Make { get; set; }
  public string Model { get; set; }
}

[XmlRootAttribute("Cars")]
public class CarCollection
{
  [XmlElement("Car")]
  public Car[] Cars { get; set; }
}

...

using (TextReader reader = new StreamReader(path))
{
  XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));
  return (CarCollection) serializer.Deserialize(reader);
}

如果使用xsd.exe创建xsd文件时出现错误，请使用msdn上提到的XmlSchemaInference类。下面是一个要演示的单元测试:

using System.Xml;
using System.Xml.Schema;

[TestMethod]
public void GenerateXsdFromXmlTest()
{
    string folder = @"C:\mydir\mydata\xmlToCSharp";
    XmlReader reader = XmlReader.Create(folder + "\some_xml.xml");
    XmlSchemaSet schemaSet = new XmlSchemaSet();
    XmlSchemaInference schema = new XmlSchemaInference();

    schemaSet = schema.InferSchema(reader);


    foreach (XmlSchema s in schemaSet.Schemas())
    {
        XmlWriter xsdFile = new XmlTextWriter(folder + "\some_xsd.xsd", System.Text.Encoding.UTF8);
        s.Write(xsdFile);
        xsdFile.Close();
    }
}

// now from the visual studio command line type: xsd some_xsd.xsd /classes

您是否可以直接将xml保存到一个文件中，然后使用xsd生成c#类?

将文件写入磁盘(我将其命名为foo.xml) 生成xsd: xsd foo.xml 生成c#: xsd foo。xsd /类

等等，瞧——c#代码文件应该能够通过XmlSerializer读取数据:

    XmlSerializer ser = new XmlSerializer(typeof(Cars));
    Cars cars;
    using (XmlReader reader = XmlReader.Create(path))
    {
        cars = (Cars) ser.Deserialize(reader);
    }

(将生成的foo.cs包含在项目中)

有两种可能。

方法1。XSD的工具

假设XML文件位于C:\path\to\ XML \file. XML

打开开发人员命令提示符 你可以在开始菜单>程序> Microsoft Visual Studio 2012 > Visual Studio工具中找到它 或者如果你有Windows 8，可以在开始屏幕中输入开发人员命令提示符 输入cd /D "C:\path\to\ XML " 通过输入XSD file.xml从xml文件创建XSD文件 通过输入xsd / C file.xsd创建c#类

就是这样!您已经从C:\path\到\xml\file.cs中的xml文件生成了c#类

方法2 -粘贴特殊

要求Visual Studio 2012+

将XML文件的内容复制到剪贴板 向您的解决方案添加新的空类文件(Shift+Alt+C) 打开该文件，在菜单中单击编辑>粘贴特殊>粘贴XML作为类

就是这样!

使用

这个helper类的用法非常简单:

using System;
using System.IO;
using System.Web.Script.Serialization; // Add reference: System.Web.Extensions
using System.Xml;
using System.Xml.Serialization;

namespace Helpers
{
    internal static class ParseHelpers
    {
        private static JavaScriptSerializer json;
        private static JavaScriptSerializer JSON { get { return json ?? (json = new JavaScriptSerializer()); } }

        public static Stream ToStream(this string @this)
        {
            var stream = new MemoryStream();
            var writer = new StreamWriter(stream);
            writer.Write(@this);
            writer.Flush();
            stream.Position = 0;
            return stream;
        }


        public static T ParseXML<T>(this string @this) where T : class
        {
            var reader = XmlReader.Create(@this.Trim().ToStream(), new XmlReaderSettings() { ConformanceLevel = ConformanceLevel.Document });
            return new XmlSerializer(typeof(T)).Deserialize(reader) as T;
        }

        public static T ParseJSON<T>(this string @this) where T : class
        {
            return JSON.Deserialize<T>(@this.Trim());
        }
    }
}

你现在要做的就是:

    public class JSONRoot
    {
        public catalog catalog { get; set; }
    }
    // ...

    string xml = File.ReadAllText(@"D:\file.xml");
    var catalog1 = xml.ParseXML<catalog>();

    string json = File.ReadAllText(@"D:\file.json");
    var catalog2 = json.ParseJSON<JSONRoot>();

您只需将Cars汽车属性的一个属性从XmlArrayItem更改为xmlelement。也就是说，从

[System.Xml.Serialization.XmlRootAttribute("Cars", Namespace = "", IsNullable = false)]
public class Cars
{
    [XmlArrayItem(typeof(Car))]
    public Car[] Car { get; set; }
}

to

[System.Xml.Serialization.XmlRootAttribute("Cars", Namespace = "", IsNullable = false)]
public class Cars
{
    [XmlElement("Car")]
    public Car[] Car { get; set; }
}

这是一个工作版本。我将XmlElementAttribute标签更改为XmlElement，因为在xml中，StockNumber、Make和Model值是元素，而不是属性。我还删除了reader.ReadToEnd();(该函数读取整个流并返回一个字符串，因此Deserialize()函数不能再使用阅读器了…位置在小溪的尽头)。我在命名上也做了一些改动:)。

下面是这些类:

[Serializable()]
public class Car
{
    [System.Xml.Serialization.XmlElement("StockNumber")]
    public string StockNumber { get; set; }

    [System.Xml.Serialization.XmlElement("Make")]
    public string Make { get; set; }

    [System.Xml.Serialization.XmlElement("Model")]
    public string Model { get; set; }
}


[Serializable()]
[System.Xml.Serialization.XmlRoot("CarCollection")]
public class CarCollection
{
    [XmlArray("Cars")]
    [XmlArrayItem("Car", typeof(Car))]
    public Car[] Car { get; set; }
}

反序列化函数:

CarCollection cars = null;
string path = "cars.xml";

XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));

StreamReader reader = new StreamReader(path);
cars = (CarCollection)serializer.Deserialize(reader);
reader.Close();

和稍微调整的xml(我需要添加一个新元素来包装<Cars>…Net对反序列化数组很挑剔):

<?xml version="1.0" encoding="utf-8"?>
<CarCollection>
<Cars>
  <Car>
    <StockNumber>1020</StockNumber>
    <Make>Nissan</Make>
    <Model>Sentra</Model>
  </Car>
  <Car>
    <StockNumber>1010</StockNumber>
    <Make>Toyota</Make>
    <Model>Corolla</Model>
  </Car>
  <Car>
    <StockNumber>1111</StockNumber>
    <Make>Honda</Make>
    <Model>Accord</Model>
  </Car>
</Cars>
</CarCollection>