我如何能使一个HTTP POST请求和发送数据的主体?


当前回答

在. net Core中,你可以用下面的代码进行POST调用。在这里,我为这段代码添加了一些额外的特性,这样您就可以让您的代码在代理后工作,如果有网络凭据的话。

在这里我还提到,您可以更改消息的编码。

HttpClient client = GetHttpClient(_config);

if (headers != null)
{
    foreach (var header in headers)
    {
        client.DefaultRequestHeaders.TryAddWithoutValidation(header.Key, header.Value);
    }
}

client.BaseAddress = new Uri(baseAddress);

Encoding encoding = Encoding.UTF8;

var result = await client.PostAsync(url, new StringContent(body, encoding, "application/json")).ConfigureAwait(false);
if (result.IsSuccessStatusCode)
{
    return new RequestResponse { severity = "Success", httpResponse = result.Content.ReadAsStringAsync().Result, StatusCode = result.StatusCode };
}
else
{
    return new RequestResponse { severity = "failure", httpResponse = result.Content.ReadAsStringAsync().Result, StatusCode = result.StatusCode };
}


public HttpClient GetHttpClient(IConfiguration _config)
{
    bool ProxyEnable = Convert.ToBoolean(_config["GlobalSettings:ProxyEnable"]);

    HttpClient client = null;
    if (!ProxyEnable)
    {
        client = new HttpClient();
    }
    else
    {
        string ProxyURL = _config["GlobalSettings:ProxyURL"];
        string ProxyUserName = _config["GlobalSettings:ProxyUserName"];
        string ProxyPassword = _config["GlobalSettings:ProxyPassword"];
        string[] ExceptionURL = _config["GlobalSettings:ExceptionURL"].Split(';');
        bool BypassProxyOnLocal = Convert.ToBoolean(_config["GlobalSettings:BypassProxyOnLocal"]);
        bool UseDefaultCredentials = Convert.ToBoolean(_config["GlobalSettings:UseDefaultCredentials"]);

        WebProxy proxy = new WebProxy
        {
            Address = new Uri(ProxyURL),
            BypassProxyOnLocal = BypassProxyOnLocal,
            UseDefaultCredentials = UseDefaultCredentials,
            BypassList = ExceptionURL,
            Credentials = new NetworkCredential(ProxyUserName, ProxyPassword)
        };

        HttpClientHandler handler = new HttpClientHandler { Proxy = proxy };
        client = new HttpClient(handler, true);
    }
    return client;
}

其他回答

当使用Windows.Web.Http命名空间时,对于POST而不是FormUrlEncodedContent,我们编写HttpFormUrlEncodedContent。同样,响应类型为HttpResponseMessage。其余的就像Evan Mulawski写的那样。

到目前为止,我找到了简单的解决方案(一行程序,没有错误检查,没有等待响应):

(new WebClient()).UploadStringAsync(new Uri(Address), dataString);‏

请谨慎使用!

这是一个HTTPS web请求的例子。可以在PHP脚本中回显任何结果。最后,PHP回显字符串将在c#客户端显示为警报。

string url = "https://mydomain.ir/test1.php";
StringBuilder postData = new StringBuilder();
postData.Append(String.Format("{0}={1}&", HttpUtility.HtmlEncode("username"), HttpUtility.HtmlEncode("ali")));
postData.Append(String.Format("{0}={1}", HttpUtility.HtmlEncode("password"), HttpUtility.HtmlEncode("123456789")));
StringContent myStringContent = new StringContent(postData.ToString(), Encoding.UTF8, "application/x-www-form-urlencoded");
HttpClient client = new HttpClient();
HttpResponseMessage message = client.PostAsync(url, myStringContent).GetAwaiter().GetResult();
string responseContent = message.Content.ReadAsStringAsync().GetAwaiter().GetResult();

DisplayAlert("Your Feedback", responseContent, "OK");

PHP服务器端:

<?php
  if (isset($_POST["username"]) && $_POST["username"] == "ali") {
    echo "Yes, hi Ali";
  }
  else {
    echo "No, where is Ali?";
  }
?>

结果将是“Yes, hi Ali”。

这是为Xamarin形式。对于一个c# .NET应用程序,将DisplayAlert替换为:

MessageBox.show(responseContent);

简单的GET请求

using System.Net;

...

using (var wb = new WebClient())
{
    var response = wb.DownloadString(url);
}

简单的POST请求

using System.Net;
using System.Collections.Specialized;

...

using (var wb = new WebClient())
{
    var data = new NameValueCollection();
    data["username"] = "myUser";
    data["password"] = "myPassword";

    var response = wb.UploadValues(url, "POST", data);
    string responseInString = Encoding.UTF8.GetString(response);
}

c# . net

    using System.Net.Http;
    
    private static readonly HttpClient httpClient = new HttpClient();

//POST    
    var values = new Object();
    values[0] = "Value1";
    values[2] = "Value2";
    values[n] = "ValueN";

    var content = new FormUrlEncodedContent(values);
    var response = await httpClient.PostAsync("URL", content);
    var responseString = await response.Content.ReadAsStringAsync();

    

//GET
 var response = await httpClient.GetStringAsync("URL");