我有一个Python命令行程序,需要一段时间才能完成。我想知道完成跑步所需的确切时间。

我看过timeit模块,但它似乎只适用于小代码片段。我想给整个节目计时。


当前回答

要使用metakermit对Python 2.7的更新答案,您需要单调包。

代码如下:

from datetime import timedelta
from monotonic import monotonic

start_time = monotonic()
end_time = monotonic()
print(timedelta(seconds=end_time - start_time))

其他回答

根据这个答案,创建了一个简单但方便的工具。

import time
from datetime import timedelta

def start_time_measure(message=None):
    if message:
        print(message)
    return time.monotonic()

def end_time_measure(start_time, print_prefix=None):
    end_time = time.monotonic()
    if print_prefix:
        print(print_prefix + str(timedelta(seconds=end_time - start_time)))
    return end_time

用法:

total_start_time = start_time_measure()    
start_time = start_time_measure('Doing something...')
# Do something
end_time_measure(start_time, 'Done in: ')
start_time = start_time_measure('Doing something else...')
# Do something else
end_time_measure(start_time, 'Done in: ')
end_time_measure(total_start_time, 'Total time: ')

输出:

Doing something...
Done in: 0:00:01.218000
Doing something else...
Done in: 0:00:01.313000
Total time: 0:00:02.672000
import time

start_time = time.clock()
main()
print(time.clock() - start_time, "seconds")

time.clock()返回处理器时间,它允许我们仅计算此进程使用的时间(无论如何,在Unix上)。文档中说“无论如何,这是用于Python基准测试或计时算法的函数”

我定义了以下Python装饰器:

def profile(fct):
  def wrapper(*args, **kw):
    start_time = time.time()
    ret = fct(*args, **kw)
    print("{} {} {} return {} in {} seconds".format(args[0].__class__.__name__,
                                                    args[0].__class__.__module__,
                                                    fct.__name__,
                                                    ret,
                                                    time.time() - start_time))
    return ret
  return wrapper

并将其用于函数或类/方法:

@profile
def main()
   ...

我在很多地方都遇到了同样的问题,所以我创建了一个方便的套装占星术。你可以用pip安装钟表,然后以优雅的方式安装:

from horology import Timing

with Timing(name='Important calculations: '):
    prepare()
    do_your_stuff()
    finish_sth()

将输出:

Important calculations: 12.43 ms

或者更简单(如果你有一个功能):

from horology import timed

@timed
def main():
    ...

将输出:

main: 7.12 h

它负责单位和舍入。它适用于python 3.6或更高版本。

Python中最简单的方法:

import time
start_time = time.time()
main()
print("--- %s seconds ---" % (time.time() - start_time))

这假设程序运行至少需要十分之一秒。

打印:

--- 0.764891862869 seconds ---