是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
当前回答
function diffArray(newArr, oldArr) {
var newSet = new Set(newArr)
var diff = []
oldArr.forEach((a) => {
if(!newSet.delete(a))diff.push(a)
})
return diff.concat(Array.from(newSet))
}
其他回答
类似于Ian Grainger的解决方案(但在打字稿中):
function findDiffs(arrayOne: string[], arrayTwo: string[]) {
let onlyInArrayOne = []
let onlyInArrayTwo = []
let share = []
let [arrayOneCopy, arrayTwoCopy] = [[...arrayOne], [...arrayTwo]]
arrayOneCopy.sort(); arrayTwoCopy.sort()
while (arrayOneCopy.length !== 0 && arrayTwoCopy.length !== 0) {
if (arrayOneCopy[0] == arrayTwoCopy[0]) {
share.push(arrayOneCopy[0])
arrayOneCopy.splice(0, 1)
arrayTwoCopy.splice(0, 1)
}
if (arrayOneCopy[0] < arrayTwoCopy[0]) {
onlyInArrayOne.push(arrayOneCopy[0])
arrayOneCopy.splice(0, 1)
}
if (arrayOneCopy[0] > arrayTwoCopy[0]) {
onlyInArrayTwo.push(arrayTwoCopy[0])
arrayTwoCopy.splice(0, 1)
}
}
onlyInArrayTwo = onlyInArrayTwo.concat(arrayTwoCopy)
onlyInArrayOne = onlyInArrayOne.concat(arrayOneCopy)
return {
onlyInArrayOne,
onlyInArrayTwo,
share,
diff: onlyInArrayOne.concat(onlyInArrayTwo)
}
}
// arrayOne: [ 'a', 'b', 'c', 'm', 'y' ]
// arrayTwo: [ 'c', 'b', 'f', 'h' ]
//
// Results:
// {
// onlyInArrayOne: [ 'a', 'm', 'y' ],
// onlyInArrayTwo: [ 'f', 'h' ],
// share: [ 'b', 'c' ],
// diff: [ 'a', 'm', 'y', 'f', 'h' ]
// }
下面是一个稍微修改的版本,它使用Object来存储哈希,可以处理数组中的数字和字符串。
function arrDiff(a, b) {
const hash = {};
a.forEach(n => { hash[n] = n; });
b.forEach(n => {
if (hash[n]) {
delete hash[n];
} else {
hash[n] = n;
}
});
return Object.values(hash);
}
我就遇到了这个问题,就是求两个简单数组的差值
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
我不明白为什么不使用基本的for循环:
for(var i=0; i < a1.length; i++) {
for(var j=0; j < a2.length; j++) {
if(a1[i] == a2[j]) {
a2.splice(j, 1);
}
}
}
这将返回所需的["c", "d"]
[编辑]提议正上方,看到晚了。
不管怎样,有什么好的理由来避免这个简单的解决方案吗?
我同意@luis-sieira的解决方案
我创建了位自解释函数,便于初学者一步一步理解:
function difference(oneArr, twoArr){
var newArr = [];
newArr = oneArr.filter((item)=>{
return !twoArr.includes(item)
});
console.log(newArr)
let arr = twoArr.filter((item)=>{
return !oneArr.includes(item)
});
newArr = newArr.concat(arr);
console.log(newArr)
}
difference([1, 2, 3, 5], [1, 2, 3, 4, 5])
使用http://phrogz.net/JS/ArraySetMath.js你可以:
var array1 = ["test1", "test2","test3", "test4"];
var array2 = ["test1", "test2","test3","test4", "test5", "test6"];
var array3 = array2.subtract( array1 );
// ["test5", "test6"]
var array4 = array1.exclusion( array2 );
// ["test5", "test6"]