除了迈克尔安德森的回答，我在我的项目中有其他两种编码方式。

第一:

你可以把所有变量白到一个类。 创建一个名为Const的kotlin文件

object Const {
    const val FIRST_NAME_1 = "just"
    const val LAST_NAME_1 = "YuMu"
}

您可以在kotlin和java代码中使用它

 Log.d("stackoverflow", Const.FIRST_NAME_1)

第二:

您可以使用Kotlin的扩展函数 创建了一个名为Ext的kotlin文件，下面的代码是Ext文件中的所有代码

package pro.just.yumu

/**
 * Created by lpf on 2020-03-18.
 */

const val FIRST_NAME = "just"
const val LAST_NAME = "YuMu"

你可以在kotlin代码中使用它

 Log.d("stackoverflow", FIRST_NAME)

您可以在java代码中使用它

 Log.d("stackoverflow", ExtKt.FIRST_NAME);

除了迈克尔安德森的回答，我在我的项目中有其他两种编码方式。

第一:

你可以把所有变量白到一个类。 创建一个名为Const的kotlin文件

object Const {
    const val FIRST_NAME_1 = "just"
    const val LAST_NAME_1 = "YuMu"
}

您可以在kotlin和java代码中使用它

 Log.d("stackoverflow", Const.FIRST_NAME_1)

第二:

您可以使用Kotlin的扩展函数 创建了一个名为Ext的kotlin文件，下面的代码是Ext文件中的所有代码

package pro.just.yumu

/**
 * Created by lpf on 2020-03-18.
 */

const val FIRST_NAME = "just"
const val LAST_NAME = "YuMu"

你可以在kotlin代码中使用它

 Log.d("stackoverflow", FIRST_NAME)

您可以在java代码中使用它

 Log.d("stackoverflow", ExtKt.FIRST_NAME);

你需要为静态方法传递同伴对象，因为kotlin没有静态关键字——同伴对象的成员可以通过简单地使用类名作为限定符来调用:

package xxx
    class ClassName {
              companion object {
                       fun helloWord(str: String): String {
                            return stringValue
                      }
              }
    }

尽管这是2年多一点的现在，并有很多伟大的答案，我看到一些其他的方法得到“静态”Kotlin字段的缺失。下面是Kotlin-Java静态互操作的示例指南:

Scenario 1: Creating a static method in Kotlin for Java Kotlin @file:JvmName("KotlinClass") //This provides a name for this file, so it's not defaulted as [KotlinClassKt] in Java package com.frybits class KotlinClass { companion object { //This annotation tells Java classes to treat this method as if it was a static to [KotlinClass] @JvmStatic fun foo(): Int = 1 //Without it, you would have to use [KotlinClass.Companion.bar()] to use this method. fun bar(): Int = 2 } } Java package com.frybits; class JavaClass { void someFunction() { println(KotlinClass.foo()); //Prints "1" println(KotlinClass.Companion.bar()); //Prints "2". This is the only way to use [bar()] in Java. println(KotlinClass.Companion.foo()); //To show that [Companion] is still the holder of the function [foo()] } //Because I'm way to lazy to keep typing [System.out], but I still want this to be compilable. void println(Object o) { System.out.println(o); } }

Michael Anderson的回答提供了更多的深度，在这种情况下绝对应该参考。

下一个场景处理在Kotlin中创建静态字段，这样Java就不必在不需要静态函数的情况下一直调用KotlinClass.foo()。

Scenario 2: Creating a static variable in Kotlin for Java Kotlin @file:JvmName("KotlinClass") //This provides a name for this file, so it's not defaulted as [KotlinClassKt] in Java package com.frybits class KotlinClass { companion object { //This annotation tells Kotlin to not generate the getter/setter functions in Java. Instead, this variable should be accessed directly //Also, this is similar to [@JvmStatic], in which it tells Java to treat this as a static variable to [KotlinClass]. @JvmField var foo: Int = 1 //If you want something akin to [final static], and the value is a primitive or a String, you can use the keyword [const] instead //No annotation is needed to make this a field of [KotlinClass]. If the declaration is a non-primitive/non-String, use @JvmField instead const val dog: Int = 1 //This will be treated as a member of the [Companion] object only. It generates the getter/setters for it. var bar: Int = 2 //We can still use [@JvmStatic] for 'var' variables, but it generates getter/setters as functions of KotlinClass //If we use 'val' instead, it only generates a getter function @JvmStatic var cat: Int = 9 } } Java package com.frybits; class JavaClass { void someFunction() { //Example using @JvmField println(KotlinClass.foo); //Prints "1" KotlinClass.foo = 3; //Example using 'const val' println(KotlinClass.dog); //Prints "1". Notice the lack of a getter function //Example of not using either @JvmField, @JvmStatic, or 'const val' println(KotlinClass.Companion.getBar()); //Prints "2" KotlinClass.Companion.setBar(3); //The setter for [bar] //Example of using @JvmStatic instead of @JvmField println(KotlinClass.getCat()); KotlinClass.setCat(0); } void println(Object o) { System.out.println(o); } }

Kotlin的一个伟大特性是您可以创建顶级函数和变量。这使得创建常量字段和函数的“无类”列表变得非常好，而这些列表又可以用作Java中的静态函数/字段。

Scenario 3: Accessing top level fields and functions in Kotlin from Java Kotlin //In this example, the file name is "KSample.kt". If this annotation wasn't provided, all functions and fields would have to accessed //using the name [KSampleKt.foo()] to utilize them in Java. Make life easier for yourself, and name this something more simple @file:JvmName("KotlinUtils") package com.frybits //This can be called from Java as [KotlinUtils.TAG]. This is a final static variable const val TAG = "You're it!" //Since this is a top level variable and not part of a companion object, there's no need to annotate this as "static" to access in Java. //However, this can only be utilized using getter/setter functions var foo = 1 //This lets us use direct access now @JvmField var bar = 2 //Since this is calculated at runtime, it can't be a constant, but it is still a final static variable. Can't use "const" here. val GENERATED_VAL:Long = "123".toLong() //Again, no need for @JvmStatic, since this is not part of a companion object fun doSomethingAwesome() { println("Everything is awesome!") } Java package com.frybits; class JavaClass { void someFunction() { println(KotlinUtils.TAG); //Example of printing [TAG] //Example of not using @JvmField. println(KotlinUtils.getFoo()); //Prints "1" KotlinUtils.setFoo(3); //Example using @JvmField println(KotlinUtils.bar); //Prints "2". Notice the lack of a getter function KotlinUtils.bar = 3; //Since this is a top level variable, no need for annotations to use this //But it looks awkward without the @JvmField println(KotlinUtils.getGENERATED_VAL()); //This is how accessing a top level function looks like KotlinUtils.doSomethingAwesome(); } void println(Object o) { System.out.println(o); } }

另一个值得注意的可以在Java中作为“静态”字段使用的是Kotlin对象类。这些是在第一次使用时惰性实例化的零参数单例类。更多信息可以在这里找到:https://kotlinlang.org/docs/reference/object-declarations.html#object-declarations

但是，要访问单例对象，需要创建一个特殊的INSTANCE对象，处理它和处理Companion一样麻烦。下面是如何在Java中使用注释来给它一种干净的静态感觉:

Scenario 4: Using object classes Kotlin @file:JvmName("KotlinClass") //This provides a name for this file, so it's not defaulted as [KotlinClassKt] in Java package com.frybits object KotlinClass { //No need for the 'class' keyword here. //Direct access to this variable const val foo: Int = 1 //Tells Java this can be accessed directly from [KotlinClass] @JvmStatic var cat: Int = 9 //Just a function that returns the class name @JvmStatic fun getCustomClassName(): String = this::class.java.simpleName + "boo!" //Getter/Setter access to this variable, but isn't accessible directly from [KotlinClass] var bar: Int = 2 fun someOtherFunction() = "What is 'INSTANCE'?" } Java package com.frybits; class JavaClass { void someFunction() { println(KotlinClass.foo); //Direct read of [foo] in [KotlinClass] singleton println(KotlinClass.getCat()); //Getter of [cat] KotlinClass.setCat(0); //Setter of [cat] println(KotlinClass.getCustomClassName()); //Example of using a function of this 'object' class println(KotlinClass.INSTANCE.getBar()); //This is what the singleton would look like without using annotations KotlinClass.INSTANCE.setBar(23); println(KotlinClass.INSTANCE.someOtherFunction()); //Accessing a function in the object class without using annotations } void println(Object o) { System.out.println(o); } }

所有静态成员和函数都应该在伴生块中

  companion object {
    @JvmStatic
    fun main(args: Array<String>) {
    }

    fun staticMethod() {
    }
  }

object objectName {
    fun funName() {

    }
}