[1,2,3].forEach(function(el) {
if(el === 1) break;
});
如何在JavaScript中使用新的forEach方法实现这一点?我尝试过返回;,return false;和断裂。break崩溃,return只会继续迭代。
[1,2,3].forEach(function(el) {
if(el === 1) break;
});
如何在JavaScript中使用新的forEach方法实现这一点?我尝试过返回;,return false;和断裂。break崩溃,return只会继续迭代。
当前回答
从您的代码示例中,它看起来像Array.prototype.find,这就是您要查找的:Array.prototy.find()和Array.prototype.findIndex()
[1, 2, 3].find(function(el) {
return el === 2;
}); // returns 2
其他回答
在其他网站上找到此解决方案。您可以在try/catch场景中包装forEach。
if(typeof StopIteration == "undefined") {
StopIteration = new Error("StopIteration");
}
try {
[1,2,3].forEach(function(el){
alert(el);
if(el === 1) throw StopIteration;
});
} catch(error) { if(error != StopIteration) throw error; }
此处提供更多详细信息:http://dean.edwards.name/weblog/2006/07/enum/
这不是最有效的,因为你仍然循环所有元素,但我认为这可能值得考虑非常简单的:
let keepGoing = true;
things.forEach( (thing) => {
if (noMore) keepGoing = false;
if (keepGoing) {
// do things with thing
}
});
使用array.prototype.every函数,它为您提供了中断循环的实用程序。请参阅Mozilla开发者网络上的Javascript文档示例
您可以创建forEach的变体,该变体允许break、continue、return甚至async/await:(用TypeScript编写的示例)
export type LoopControlOp = "break" | "continue" | ["return", any];
export type LoopFunc<T> = (value: T, index: number, array: T[])=>LoopControlOp;
Array.prototype.ForEach = function ForEach<T>(this: T[], func: LoopFunc<T>) {
for (let i = 0; i < this.length; i++) {
const controlOp = func(this[i], i, this);
if (controlOp == "break") break;
if (controlOp == "continue") continue;
if (controlOp instanceof Array) return controlOp[1];
}
};
// this variant lets you use async/await in the loop-func, with the loop "awaiting" for each entry
Array.prototype.ForEachAsync = async function ForEachAsync<T>(this: T[], func: LoopFunc<T>) {
for (let i = 0; i < this.length; i++) {
const controlOp = await func(this[i], i, this);
if (controlOp == "break") break;
if (controlOp == "continue") continue;
if (controlOp instanceof Array) return controlOp[1];
}
};
用法:
function GetCoffee() {
const cancelReason = peopleOnStreet.ForEach((person, index)=> {
if (index == 0) return "continue";
if (person.type == "friend") return "break";
if (person.type == "boss") return ["return", "nevermind"];
});
if (cancelReason) console.log("Coffee canceled because: " + cancelReason);
}
const Book = {"Titles":[
{"Book3" : "BULLETIN 3"},
{"Book1" : "BULLETIN 1"},
{"Book2" : "BULLETIN 2"}
]}
const findbystr = function(str) {
Book.Titles.forEach(function(data) {
if (typeof data[str] != 'undefined') {
return data[str];
}
}, str)
}
book = findbystr('Book1');
console.log(book);