你可以用:

if (!!variable) {}

它等于写作

it (variable != null && variable != undefined) {}

All,

得票最多的答案，如果你在研究一个对象，就不适用了。在这种情况下，如果属性不存在，检查将不起作用。这就是我们案例中的问题:请看这个例子:

var x =
{ name: "Homer", LastName: "Simpson" };

var y =
{ name: "Marge"} ;

var z =
{ name: "Bart" , LastName: undefined} ;

var a =
{ name: "Lisa" , LastName: ""} ;

var hasLastNameX = x.LastName != null;
var hasLastNameY = y.LastName != null;
var hasLastNameZ = z.LastName != null;
var hasLastNameA = a.LastName != null;



alert (hasLastNameX + ' ' + hasLastNameY + ' ' + hasLastNameZ + ' ' + hasLastNameA);

var hasLastNameXX = x.LastName !== null;
var hasLastNameYY = y.LastName !== null;
var hasLastNameZZ = z.LastName !== null;
var hasLastNameAA = a.LastName !== null;

alert (hasLastNameXX + ' ' + hasLastNameYY + ' ' + hasLastNameZZ + ' ' + hasLastNameAA);

结果:

true , false, false , true (in case of !=)
true , true, true, true (in case of !==) => so in this sample not the correct answer

plunkr链接:https://plnkr.co/edit/BJpVHD95FhKlpHp1skUE

你可以使用

if(x === undefined)

我有这个问题，一些答案工作只是很好的JS，但不是TS这里的原因。

//JS
let couldBeNullOrUndefined;
if(couldBeNullOrUndefined == null) {
  console.log('null OR undefined', couldBeNullOrUndefined);
} else {
  console.log('Has some value', couldBeNullOrUndefined);
}

这很好，因为JS没有类型

//TS
let couldBeNullOrUndefined?: string | null; // THIS NEEDS TO BE TYPED AS undefined || null || Type(string)

if(couldBeNullOrUndefined === null) { // TS should always use strict-check
  console.log('null OR undefined', couldBeNullOrUndefined);
} else {
  console.log('Has some value', couldBeNullOrUndefined);
}

在TS中，如果变量未定义为null，当您试图检查该null时，tslint |编译器将报错。

//tslint.json
...
"triple-equals":[true],
...

 let couldBeNullOrUndefined?: string; // to fix it add | null

 Types of property 'couldBeNullOrUndefined' are incompatible.
      Type 'string | null' is not assignable to type 'string | undefined'.
        Type 'null' is not assignable to type 'string | undefined'.

最简单的方法是使用:

import {isNullOrUndefined} from 'util';

比:

如果isNullOrUndefined (foo (!)

我在typescript操场上做了不同的测试:

http://www.typescriptlang.org/play/

let a;
let b = null;
let c = "";
var output = "";

if (a == null) output += "a is null or undefined\n";
if (b == null) output += "b is null or undefined\n";
if (c == null) output += "c is null or undefined\n";
if (a != null) output += "a is defined\n";
if (b != null) output += "b is defined\n";
if (c != null) output += "c is defined\n";
if (a) output += "a is defined (2nd method)\n";
if (b) output += "b is defined (2nd method)\n";
if (c) output += "c is defined (2nd method)\n";

console.log(output);

给:

a is null or undefined
b is null or undefined
c is defined

so:

检查(a == null)是否正确，以知道a是否为空或未定义 检查(a != null)是否正确，以知道是否定义了a 检查(a)是否错误，以知道a是否被定义