当你只想做一个try-except而不处理异常时,你在Python中如何做呢?

下面的方法是正确的吗?

try:
    shutil.rmtree(path)
except:
    pass

当前回答

我通常会这样做:

try:
    doSomething()
except:
    _ = ""

其他回答

当你只想做一个try catch而不处理异常时, 用Python怎么做?

这将帮助你打印异常是什么:(即尝试catch而不处理异常并打印异常。)

import sys
try:
    doSomething()
except:
    print "Unexpected error:", sys.exc_info()[0]

我需要忽略多个命令和fuckit的错误

import fuckit

@fuckit
def helper():
    print('before')
    1/0
    print('after1')
    1/0
    print('after2')

helper()

完整性:

>>> def divide(x, y):
...     try:
...         result = x / y
...     except ZeroDivisionError:
...         print("division by zero!")
...     else:
...         print("result is", result)
...     finally:
...         print("executing finally clause")

还要注意,你可以像这样捕获异常:

>>> try:
...     this_fails()
... except ZeroDivisionError as err:
...     print("Handling run-time error:", err)

...并像这样重新抛出异常:

>>> try:
...     raise NameError('HiThere')
... except NameError:
...     print('An exception flew by!')
...     raise

此外,多种异常类型可以作为圆括号元组来处理:

try:
    i_might_fail()
except (ValueError, TypeError) as ex:
    print('I failed with: ', ex)

...或作为单独的除条款:

try:
    i_might_fail()
except ValueError:
    print('handling a ValueError...')
except TypeError:
    print('handling a TypeError...')

...请参阅python教程。

我通常会这样做:

try:
    doSomething()
except:
    _ = ""
try:
      doSomething()
except Exception: 
    pass
else:
      stuffDoneIf()
      TryClauseSucceeds()

供您参考,else子句可以放在所有异常之后,只有在try中的代码没有导致异常时才会运行。