当你只想做一个try-except而不处理异常时,你在Python中如何做呢?

下面的方法是正确的吗?

try:
    shutil.rmtree(path)
except:
    pass

当前回答

我通常会这样做:

try:
    doSomething()
except:
    _ = ""

其他回答

当你只想做一个try catch而不处理异常时,你在Python中如何做呢?

这取决于你对“处理”的定义。

如果你想抓住它不采取任何行动,你张贴的代码将工作。

如果你的意思是你想对一个异常采取行动,而不阻止该异常上升到堆栈,那么你想要这样的东西:

try:
    do_something()
except:
    handle_exception()
    raise  #re-raise the exact same exception that was thrown

我需要忽略多个命令和fuckit的错误

import fuckit

@fuckit
def helper():
    print('before')
    1/0
    print('after1')
    1/0
    print('after2')

helper()
try:
    doSomething()
except Exception: 
    pass

or

try:
    doSomething()
except: 
    pass

不同的是第二个也会捕捉KeyboardInterrupt, SystemExit和类似的东西,它们直接从BaseException派生,而不是Exception。

详见文档:

试着声明 异常

然而,捕捉每个错误通常是糟糕的实践——参见为什么“except: pass”是一个糟糕的编程实践?

完整性:

>>> def divide(x, y):
...     try:
...         result = x / y
...     except ZeroDivisionError:
...         print("division by zero!")
...     else:
...         print("result is", result)
...     finally:
...         print("executing finally clause")

还要注意,你可以像这样捕获异常:

>>> try:
...     this_fails()
... except ZeroDivisionError as err:
...     print("Handling run-time error:", err)

...并像这样重新抛出异常:

>>> try:
...     raise NameError('HiThere')
... except NameError:
...     print('An exception flew by!')
...     raise

此外,多种异常类型可以作为圆括号元组来处理:

try:
    i_might_fail()
except (ValueError, TypeError) as ex:
    print('I failed with: ', ex)

...或作为单独的除条款:

try:
    i_might_fail()
except ValueError:
    print('handling a ValueError...')
except TypeError:
    print('handling a TypeError...')

...请参阅python教程。

在Python中,我们处理异常的方式与其他语言类似,但区别在于语法上的不同,例如,

try:
    #Your code in which exception can occur
except <here we can put in a particular exception name>:
    # We can call that exception here also, like ZeroDivisionError()
    # now your code
# We can put in a finally block also
finally:
    # Your code...