当你只想做一个try-except而不处理异常时,你在Python中如何做呢?
下面的方法是正确的吗?
try:
shutil.rmtree(path)
except:
pass
当你只想做一个try-except而不处理异常时,你在Python中如何做呢?
下面的方法是正确的吗?
try:
shutil.rmtree(path)
except:
pass
当前回答
我通常会这样做:
try:
doSomething()
except:
_ = ""
其他回答
当你只想做一个try catch而不处理异常时, 用Python怎么做?
这将帮助你打印异常是什么:(即尝试catch而不处理异常并打印异常。)
import sys
try:
doSomething()
except:
print "Unexpected error:", sys.exc_info()[0]
我需要忽略多个命令和fuckit的错误
import fuckit
@fuckit
def helper():
print('before')
1/0
print('after1')
1/0
print('after2')
helper()
完整性:
>>> def divide(x, y):
... try:
... result = x / y
... except ZeroDivisionError:
... print("division by zero!")
... else:
... print("result is", result)
... finally:
... print("executing finally clause")
还要注意,你可以像这样捕获异常:
>>> try:
... this_fails()
... except ZeroDivisionError as err:
... print("Handling run-time error:", err)
...并像这样重新抛出异常:
>>> try:
... raise NameError('HiThere')
... except NameError:
... print('An exception flew by!')
... raise
此外,多种异常类型可以作为圆括号元组来处理:
try:
i_might_fail()
except (ValueError, TypeError) as ex:
print('I failed with: ', ex)
...或作为单独的除条款:
try:
i_might_fail()
except ValueError:
print('handling a ValueError...')
except TypeError:
print('handling a TypeError...')
...请参阅python教程。
我通常会这样做:
try:
doSomething()
except:
_ = ""
try:
doSomething()
except Exception:
pass
else:
stuffDoneIf()
TryClauseSucceeds()
供您参考,else子句可以放在所有异常之后,只有在try中的代码没有导致异常时才会运行。