为什么这个组件在这个简单的砰砰声中
@Component({
selector: 'my-app',
template: `<div>I'm {{message}} </div>`,
})
export class App {
message:string = 'loading :(';
ngAfterViewInit() {
this.updateMessage();
}
updateMessage(){
this.message = 'all done loading :)'
}
}
扔:
例外:表达式'I'm {{message}} in App@0:5'在被检查后发生了变化。之前的值:'I'm loading:('。当前值:'I'm all done loading:)' in [I'm {{message}} in App@0:5]
当我所做的一切都是更新一个简单的绑定时，我的视图被启动?
当前回答
简单:首先在你的组件结构中分离/移除变更检测，然后在ngAfterViewInit()方法中启用detectChanges()
constructor(private cdr: ChangeDetectorRef) {
this.cdr.detach() // detach/remove the change detection here in constructor
}
ngAfterViewInit(): void {
// do load objects or other logics here
// at the end of this method, call detectChanges() method.
this.cdr.detectChanges(); // enable detectChanges here and you're done.
}
其他回答
只需将代码移动到要更改共享服务主题的组件的构造函数中
我认为最简单的解决方法如下:
Make one implementation of assigning a value to some variable i.e. via function or setter. Create a class variable (static working: boolean) in the class where this function exists and every time you call the function, simply make it true whichever you like. Within the function, if the value of working is true, then simply return right away without doing anything. else, perform the task you want. Make sure to change this variable to false once the task is completed i.e. at the end of the line of codes or within the subscribe method when you are done assigning values!
正如drewmoore所说，在这种情况下，正确的解决方案是手动触发当前组件的变更检测。这是使用ChangeDetectorRef对象(从angular2/core导入)的detectChanges()方法完成的，或者它的markForCheck()方法，该方法也会更新任何父组件。相关例子:
import { Component, ChangeDetectorRef, AfterViewInit } from 'angular2/core'
@Component({
selector: 'my-app',
template: `<div>I'm {{message}} </div>`,
})
export class App implements AfterViewInit {
message: string = 'loading :(';
constructor(private cdr: ChangeDetectorRef) {}
ngAfterViewInit() {
this.message = 'all done loading :)'
this.cdr.detectChanges();
}
}
这里还有Plunkers演示了ngOnInit, setTimeout和enableProdMode方法以防万一。
我有几乎相同的案例，我有一系列的产品。我不得不让用户删除产品根据他们的选择。最后，如果数组中没有产品，那么我需要显示取消按钮而不是返回按钮，无需重新加载页面。
我通过检查ngAfterViewChecked()生命周期钩子中的空数组来完成。 这就是我是如何做到的，希望它有帮助:)
import { ChangeDetectorRef } from '@angular/core';
products: Product[];
someCondition: boolean;
constructor(private cdr: ChangeDetectorRef) {}
ngAfterViewChecked() {
if(!this.someCondition) {
this.emptyArray();
}
}
emptyArray() {
this.someCondition = this.products.length === 0 ? true : false;
// run change detection explicitly
this.cdr.detectChanges();
}
removeProduct(productId: number) {
// your logic for removing product.
}
你也可以试着把this.updateMessage();在ngOnInit下，像这样:
ngOnInit(): void {
this.updateMessage();
}
