最近我一直在iPhone上玩一款名为《Scramble》的游戏。有些人可能知道这个游戏叫拼字游戏。从本质上讲,当游戏开始时,你会得到一个字母矩阵:

F X I E
A M L O
E W B X
A S T U

The goal of the game is to find as many words as you can that can be formed by chaining letters together. You can start with any letter, and all the letters that surround it are fair game, and then once you move on to the next letter, all the letters that surround that letter are fair game, except for any previously used letters. So in the grid above, for example, I could come up with the words LOB, TUX, SEA, FAME, etc. Words must be at least 3 characters, and no more than NxN characters, which would be 16 in this game but can vary in some implementations. While this game is fun and addictive, I am apparently not very good at it and I wanted to cheat a little bit by making a program that would give me the best possible words (the longer the word the more points you get).

(来源:boggled.org)

不幸的是,我不太擅长算法或它们的效率等等。我的第一次尝试使用一个像这样的字典(约2.3MB),并进行线性搜索,试图匹配字典条目的组合。这需要花费很长时间来找到可能的单词,因为你每轮只有2分钟的时间,这是不够的。

我很有兴趣看看是否有任何Stackoverflowers可以提出更有效的解决方案。我主要是在寻找使用三大p的解决方案:Python、PHP和Perl,尽管任何使用Java或c++的东西也很酷,因为速度是至关重要的。

目前的解决方案:

Adam Rosenfield, Python, ~20岁 John Fouhy, Python, ~3秒 Kent Fredric, Perl, ~1s Darius Bacon, Python, ~1s rvarcher, VB。净,~ 1 s Paolo Bergantino, PHP(实时链接),~5s(本地~2s)


当前回答

我也用Java解决了这个问题。我的实现有269行,非常容易使用。首先,您需要创建Boggler类的一个新实例,然后用网格作为参数调用solve函数。在我的电脑上加载5万个单词的字典大约需要100毫秒,它在大约10-20毫秒内找到单词。找到的单词存储在一个数组列表中,即foundWords。

import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URISyntaxException;
import java.net.URL;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Comparator;

public class Boggler {
    private ArrayList<String> words = new ArrayList<String>();      
    private ArrayList<String> roundWords = new ArrayList<String>(); 
    private ArrayList<Word> foundWords = new ArrayList<Word>();     
    private char[][] letterGrid = new char[4][4];                   
    private String letters;                                         

    public Boggler() throws FileNotFoundException, IOException, URISyntaxException {
        long startTime = System.currentTimeMillis();

        URL path = GUI.class.getResource("words.txt");
        BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(new File(path.toURI()).getAbsolutePath()), "iso-8859-1"));
        String line;
        while((line = br.readLine()) != null) {
            if(line.length() < 3 || line.length() > 10) {
                continue;
            }

            this.words.add(line);
        }
    }

    public ArrayList<Word> getWords() {
        return this.foundWords;
    }

    public void solve(String letters) {
        this.letters = "";
        this.foundWords = new ArrayList<Word>();

        for(int i = 0; i < letters.length(); i++) {
            if(!this.letters.contains(letters.substring(i, i + 1))) {
                this.letters += letters.substring(i, i + 1);
            }
        }

        for(int i = 0; i < 4; i++) {
            for(int j = 0; j < 4; j++) {
                this.letterGrid[i][j] = letters.charAt(i * 4 + j);
            }
        }

        System.out.println(Arrays.deepToString(this.letterGrid));               

        this.roundWords = new ArrayList<String>();      
        String pattern = "[" + this.letters + "]+";     

        for(int i = 0; i < this.words.size(); i++) {

            if(this.words.get(i).matches(pattern)) {
                this.roundWords.add(this.words.get(i));
            }
        }

        for(int i = 0; i < this.roundWords.size(); i++) {
            Word word = checkForWord(this.roundWords.get(i));

            if(word != null) {
                System.out.println(word);
                this.foundWords.add(word);
            }
        }       
    }

    private Word checkForWord(String word) {
        char initial = word.charAt(0);
        ArrayList<LetterCoord> startPoints = new ArrayList<LetterCoord>();

        int x = 0;  
        int y = 0;
        for(char[] row: this.letterGrid) {
            x = 0;

            for(char letter: row) {
                if(initial == letter) {
                    startPoints.add(new LetterCoord(x, y));
                }

                x++;
            }

            y++;
        }

        ArrayList<LetterCoord> letterCoords = null;
        for(int initialTry = 0; initialTry < startPoints.size(); initialTry++) {
            letterCoords = new ArrayList<LetterCoord>();    

            x = startPoints.get(initialTry).getX(); 
            y = startPoints.get(initialTry).getY();

            LetterCoord initialCoord = new LetterCoord(x, y);
            letterCoords.add(initialCoord);

            letterLoop: for(int letterIndex = 1; letterIndex < word.length(); letterIndex++) {
                LetterCoord lastCoord = letterCoords.get(letterCoords.size() - 1);  
                char currentChar = word.charAt(letterIndex);                        

                ArrayList<LetterCoord> letterLocations = getNeighbours(currentChar, lastCoord.getX(), lastCoord.getY());

                if(letterLocations == null) {
                    return null;    
                }       

                for(int foundIndex = 0; foundIndex < letterLocations.size(); foundIndex++) {
                    if(letterIndex != word.length() - 1 && true == false) {
                        char nextChar = word.charAt(letterIndex + 1);
                        int lastX = letterCoords.get(letterCoords.size() - 1).getX();
                        int lastY = letterCoords.get(letterCoords.size() - 1).getY();

                        ArrayList<LetterCoord> possibleIndex = getNeighbours(nextChar, lastX, lastY);
                        if(possibleIndex != null) {
                            if(!letterCoords.contains(letterLocations.get(foundIndex))) {
                                letterCoords.add(letterLocations.get(foundIndex));
                            }
                            continue letterLoop;
                        } else {
                            return null;
                        }
                    } else {
                        if(!letterCoords.contains(letterLocations.get(foundIndex))) {
                            letterCoords.add(letterLocations.get(foundIndex));

                            continue letterLoop;
                        }
                    }
                }
            }

            if(letterCoords != null) {
                if(letterCoords.size() == word.length()) {
                    Word w = new Word(word);
                    w.addList(letterCoords);
                    return w;
                } else {
                    return null;
                }
            }
        }

        if(letterCoords != null) {
            Word foundWord = new Word(word);
            foundWord.addList(letterCoords);

            return foundWord;
        }

        return null;
    }

    public ArrayList<LetterCoord> getNeighbours(char letterToSearch, int x, int y) {
        ArrayList<LetterCoord> neighbours = new ArrayList<LetterCoord>();

        for(int _y = y - 1; _y <= y + 1; _y++) {
            for(int _x = x - 1; _x <= x + 1; _x++) {
                if(_x < 0 || _y < 0 || (_x == x && _y == y) || _y > 3 || _x > 3) {
                    continue;
                }

                if(this.letterGrid[_y][_x] == letterToSearch && !neighbours.contains(new LetterCoord(_x, _y))) {
                    neighbours.add(new LetterCoord(_x, _y));
                }
            }
        }

        if(neighbours.isEmpty()) {
            return null;
        } else {
            return neighbours;
        }
    }
}

class Word {
    private String word;    
    private ArrayList<LetterCoord> letterCoords = new ArrayList<LetterCoord>();

    public Word(String word) {
        this.word = word;
    }

    public boolean addCoords(int x, int y) {
        LetterCoord lc = new LetterCoord(x, y);

        if(!this.letterCoords.contains(lc)) {
            this.letterCoords.add(lc);

            return true;
        }

        return false;
    }

    public void addList(ArrayList<LetterCoord> letterCoords) {
        this.letterCoords = letterCoords;
    } 

    @Override
    public String toString() {
        String outputString = this.word + " ";
        for(int i = 0; i < letterCoords.size(); i++) {
            outputString += "(" + letterCoords.get(i).getX() + ", " + letterCoords.get(i).getY() + ") ";
        }

        return outputString;
    }

    public String getWord() {
        return this.word;
    }

    public ArrayList<LetterCoord> getList() {
        return this.letterCoords;
    }
}

class LetterCoord extends ArrayList {
    private int x;          
    private int y;          

    public LetterCoord(int x, int y) {
        this.x = x;
        this.y = y;
    }

    public int getX() {
        return this.x;
    }

    public int getY() {
        return this.y;
    }

    @Override
    public boolean equals(Object o) {
        if(!(o instanceof LetterCoord)) {
            return false;
        }

        LetterCoord lc = (LetterCoord) o;

        if(this.x == lc.getX() &&
                this.y == lc.getY()) {
            return true;
        }

        return false;
    }

    @Override
    public int hashCode() {
        int hash = 7;
        hash = 29 * hash + this.x;
        hash = 24 * hash + this.y;
        return hash;
    }
}

其他回答

我在Java上的尝试。读取文件和构建trie大约需要2秒,解决谜题大约需要50毫秒。我用了问题中链接的字典(里面有几个我不知道在英语中存在的单词,比如fae, ima)

0 [main] INFO gineer.bogglesolver.util.Util  - Reading the dictionary
2234 [main] INFO gineer.bogglesolver.util.Util  - Finish reading the dictionary
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAM
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAME
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAMBLE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: FAE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: IMA
2234 [main] INFO gineer.bogglesolver.Solver  - Found: ELI
2234 [main] INFO gineer.bogglesolver.Solver  - Found: ELM
2234 [main] INFO gineer.bogglesolver.Solver  - Found: ELB
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AXIL
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AXILE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AXLE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMI
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMIL
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMLI
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AME
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMBLE
2234 [main] INFO gineer.bogglesolver.Solver  - Found: AMBO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWEST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MIX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MILE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MILO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MAW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MEW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MEWL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MESA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: MWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIME
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMBO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LIMBU
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LEI
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LEO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LOB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: LOX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OIME
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: OLM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EMIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EMBOLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EMBOX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: EAST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAF
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAME
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAMBLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEAM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WEST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAS
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WASE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: WAST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BLEO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BLO
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BOIL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BOLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: BUT
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AES
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWL
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AWEST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: ASE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: ASEM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: AST
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEAX
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEAM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEMI
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEMBLE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SEA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWAM
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWAMI
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SAW
2250 [main] INFO gineer.bogglesolver.Solver  - Found: SAWT
2250 [main] INFO gineer.bogglesolver.Solver  - Found: STU
2250 [main] INFO gineer.bogglesolver.Solver  - Found: STUB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWA
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWAE
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TWAS
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TUB
2250 [main] INFO gineer.bogglesolver.Solver  - Found: TUX

源代码由6个类组成。我将把它们贴在下面(如果这不是StackOverflow的正确做法,请告诉我)。

gineer.bogglesolver.Main

package gineer.bogglesolver;

import org.apache.log4j.BasicConfigurator;
import org.apache.log4j.Logger;

public class Main
{
    private final static Logger logger = Logger.getLogger(Main.class);

    public static void main(String[] args)
    {
        BasicConfigurator.configure();

        Solver solver = new Solver(4,
                        "FXIE" +
                        "AMLO" +
                        "EWBX" +
                        "ASTU");
        solver.solve();

    }
}

gineer.bogglesolver.Solver

package gineer.bogglesolver;

import gineer.bogglesolver.trie.Trie;
import gineer.bogglesolver.util.Constants;
import gineer.bogglesolver.util.Util;
import org.apache.log4j.Logger;

public class Solver
{
    private char[] puzzle;
    private int maxSize;

    private boolean[] used;
    private StringBuilder stringSoFar;

    private boolean[][] matrix;
    private Trie trie;

    private final static Logger logger = Logger.getLogger(Solver.class);

    public Solver(int size, String puzzle)
    {
        trie = Util.getTrie(size);
        matrix = Util.connectivityMatrix(size);

        maxSize = size * size;
        stringSoFar = new StringBuilder(maxSize);
        used = new boolean[maxSize];

        if (puzzle.length() == maxSize)
        {
            this.puzzle = puzzle.toCharArray();
        }
        else
        {
            logger.error("The puzzle size does not match the size specified: " + puzzle.length());
            this.puzzle = puzzle.substring(0, maxSize).toCharArray();
        }
    }

    public void solve()
    {
        for (int i = 0; i < maxSize; i++)
        {
            traverseAt(i);
        }
    }

    private void traverseAt(int origin)
    {
        stringSoFar.append(puzzle[origin]);
        used[origin] = true;

        //Check if we have a valid word
        if ((stringSoFar.length() >= Constants.MINIMUM_WORD_LENGTH) && (trie.containKey(stringSoFar.toString())))
        {
            logger.info("Found: " + stringSoFar.toString());
        }

        //Find where to go next
        for (int destination = 0; destination < maxSize; destination++)
        {
            if (matrix[origin][destination] && !used[destination] && trie.containPrefix(stringSoFar.toString() + puzzle[destination]))
            {
                traverseAt(destination);
            }
        }

        used[origin] = false;
        stringSoFar.deleteCharAt(stringSoFar.length() - 1);
    }

}

gineer.bogglesolver.trie.Node

package gineer.bogglesolver.trie;

import gineer.bogglesolver.util.Constants;

class Node
{
    Node[] children;
    boolean isKey;

    public Node()
    {
        isKey = false;
        children = new Node[Constants.NUMBER_LETTERS_IN_ALPHABET];
    }

    public Node(boolean key)
    {
        isKey = key;
        children = new Node[Constants.NUMBER_LETTERS_IN_ALPHABET];
    }

    /**
     Method to insert a string to Node and its children

     @param key the string to insert (the string is assumed to be uppercase)
     @return true if the node or one of its children is changed, false otherwise
     */
    public boolean insert(String key)
    {
        //If the key is empty, this node is a key
        if (key.length() == 0)
        {
            if (isKey)
                return false;
            else
            {
                isKey = true;
                return true;
            }
        }
        else
        {//otherwise, insert in one of its child

            int childNodePosition = key.charAt(0) - Constants.LETTER_A;
            if (children[childNodePosition] == null)
            {
                children[childNodePosition] = new Node();
                children[childNodePosition].insert(key.substring(1));
                return true;
            }
            else
            {
                return children[childNodePosition].insert(key.substring(1));
            }
        }
    }

    /**
     Returns whether key is a valid prefix for certain key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell", "hello" return true

     @param prefix the prefix to check
     @return true if the prefix is valid, false otherwise
     */
    public boolean containPrefix(String prefix)
    {
        //If the prefix is empty, return true
        if (prefix.length() == 0)
        {
            return true;
        }
        else
        {//otherwise, check in one of its child
            int childNodePosition = prefix.charAt(0) - Constants.LETTER_A;
            return children[childNodePosition] != null && children[childNodePosition].containPrefix(prefix.substring(1));
        }
    }

    /**
     Returns whether key is a valid key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell" return false

     @param key the key to check
     @return true if the key is valid, false otherwise
     */
    public boolean containKey(String key)
    {
        //If the prefix is empty, return true
        if (key.length() == 0)
        {
            return isKey;
        }
        else
        {//otherwise, check in one of its child
            int childNodePosition = key.charAt(0) - Constants.LETTER_A;
            return children[childNodePosition] != null && children[childNodePosition].containKey(key.substring(1));
        }
    }

    public boolean isKey()
    {
        return isKey;
    }

    public void setKey(boolean key)
    {
        isKey = key;
    }
}

gineer.bogglesolver.trie.Trie

package gineer.bogglesolver.trie;

public class Trie
{
    Node root;

    public Trie()
    {
        this.root = new Node();
    }

    /**
     Method to insert a string to Node and its children

     @param key the string to insert (the string is assumed to be uppercase)
     @return true if the node or one of its children is changed, false otherwise
     */
    public boolean insert(String key)
    {
        return root.insert(key.toUpperCase());
    }

    /**
     Returns whether key is a valid prefix for certain key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell", "hello" return true

     @param prefix the prefix to check
     @return true if the prefix is valid, false otherwise
     */
    public boolean containPrefix(String prefix)
    {
        return root.containPrefix(prefix.toUpperCase());
    }

    /**
     Returns whether key is a valid key in this trie.
     For example: if key "hello" is in this trie, tests with all prefixes "hel", "hell" return false

     @param key the key to check
     @return true if the key is valid, false otherwise
     */
    public boolean containKey(String key)
    {
        return root.containKey(key.toUpperCase());
    }


}

gineer.bogglesolver.util.Constants

package gineer.bogglesolver.util;

public class Constants
{

    public static final int NUMBER_LETTERS_IN_ALPHABET = 26;
    public static final char LETTER_A = 'A';
    public static final int MINIMUM_WORD_LENGTH = 3;
    public static final int DEFAULT_PUZZLE_SIZE = 4;
}

gineer.bogglesolver.util.Util

package gineer.bogglesolver.util;

import gineer.bogglesolver.trie.Trie;
import org.apache.log4j.Logger;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class Util
{
    private final static Logger logger = Logger.getLogger(Util.class);
    private static Trie trie;
    private static int size = Constants.DEFAULT_PUZZLE_SIZE;

    /**
     Returns the trie built from the dictionary.  The size is used to eliminate words that are too long.

     @param size the size of puzzle.  The maximum lenght of words in the returned trie is (size * size)
     @return the trie that can be used for puzzle of that size
     */
    public static Trie getTrie(int size)
    {
        if ((trie != null) && size == Util.size)
            return trie;

        trie = new Trie();
        Util.size = size;

        logger.info("Reading the dictionary");
        final File file = new File("dictionary.txt");
        try
        {
            Scanner scanner = new Scanner(file);
            final int maxSize = size * size;
            while (scanner.hasNext())
            {
                String line = scanner.nextLine().replaceAll("[^\\p{Alpha}]", "");

                if (line.length() <= maxSize)
                    trie.insert(line);
            }
        }
        catch (FileNotFoundException e)
        {
            logger.error("Cannot open file", e);
        }

        logger.info("Finish reading the dictionary");
        return trie;
    }

    static boolean[] connectivityRow(int x, int y, int size)
    {
        boolean[] squares = new boolean[size * size];
        for (int offsetX = -1; offsetX <= 1; offsetX++)
        {
            for (int offsetY = -1; offsetY <= 1; offsetY++)
            {
                final int calX = x + offsetX;
                final int calY = y + offsetY;
                if ((calX >= 0) && (calX < size) && (calY >= 0) && (calY < size))
                    squares[calY * size + calX] = true;
            }
        }

        squares[y * size + x] = false;//the current x, y is false

        return squares;
    }

    /**
     Returns the matrix of connectivity between two points.  Point i can go to point j iff matrix[i][j] is true
     Square (x, y) is equivalent to point (size * y + x).  For example, square (1,1) is point 5 in a puzzle of size 4

     @param size the size of the puzzle
     @return the connectivity matrix
     */
    public static boolean[][] connectivityMatrix(int size)
    {
        boolean[][] matrix = new boolean[size * size][];
        for (int x = 0; x < size; x++)
        {
            for (int y = 0; y < size; y++)
            {
                matrix[y * size + x] = connectivityRow(x, y, size);
            }
        }
        return matrix;
    }
}

首先,阅读c#语言设计师如何解决一个相关问题: http://blogs.msdn.com/ericlippert/archive/2009/02/04/a-nasality-talisman-for-the-sultana-analyst.aspx。

像他一样,您可以从字典开始,并通过从字母排序的字母数组到可以根据这些字母拼写的单词列表创建字典来规范化单词。

接下来,开始从黑板上创建可能的单词并查找它们。我怀疑这将让你走得很远,但肯定有更多的技巧可以加快速度。

我花了3个月的时间致力于解决10个最佳点密集的5x5 Boggle板问题。

这个问题现在已经解决了,并在5个网页上进行了全面披露。有问题请联系我。

该棋盘分析算法使用显式堆栈,通过具有直接子信息的有向无环词图伪递归遍历棋盘方格,并使用时间戳跟踪机制。这很可能是世界上最先进的词汇数据结构。

该方案在四核上每秒评估大约10,000块非常好的电路板。(9500 +分)

父网页:

DeepSearch.c - http://www.pathcom.com/~vadco/deep.html

组件网页:

最佳记分牌- http://www.pathcom.com/~vadco/binary.html

高级词汇结构- http://www.pathcom.com/~vadco/adtdawg.html

板分析算法- http://www.pathcom.com/~vadco/guns.html

并行批处理- http://www.pathcom.com/~vadco/parallel.html

- 只有追求最好的人才会对这本全面的著作感兴趣。

我也用Java解决了这个问题。我的实现有269行,非常容易使用。首先,您需要创建Boggler类的一个新实例,然后用网格作为参数调用solve函数。在我的电脑上加载5万个单词的字典大约需要100毫秒,它在大约10-20毫秒内找到单词。找到的单词存储在一个数组列表中,即foundWords。

import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URISyntaxException;
import java.net.URL;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Comparator;

public class Boggler {
    private ArrayList<String> words = new ArrayList<String>();      
    private ArrayList<String> roundWords = new ArrayList<String>(); 
    private ArrayList<Word> foundWords = new ArrayList<Word>();     
    private char[][] letterGrid = new char[4][4];                   
    private String letters;                                         

    public Boggler() throws FileNotFoundException, IOException, URISyntaxException {
        long startTime = System.currentTimeMillis();

        URL path = GUI.class.getResource("words.txt");
        BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(new File(path.toURI()).getAbsolutePath()), "iso-8859-1"));
        String line;
        while((line = br.readLine()) != null) {
            if(line.length() < 3 || line.length() > 10) {
                continue;
            }

            this.words.add(line);
        }
    }

    public ArrayList<Word> getWords() {
        return this.foundWords;
    }

    public void solve(String letters) {
        this.letters = "";
        this.foundWords = new ArrayList<Word>();

        for(int i = 0; i < letters.length(); i++) {
            if(!this.letters.contains(letters.substring(i, i + 1))) {
                this.letters += letters.substring(i, i + 1);
            }
        }

        for(int i = 0; i < 4; i++) {
            for(int j = 0; j < 4; j++) {
                this.letterGrid[i][j] = letters.charAt(i * 4 + j);
            }
        }

        System.out.println(Arrays.deepToString(this.letterGrid));               

        this.roundWords = new ArrayList<String>();      
        String pattern = "[" + this.letters + "]+";     

        for(int i = 0; i < this.words.size(); i++) {

            if(this.words.get(i).matches(pattern)) {
                this.roundWords.add(this.words.get(i));
            }
        }

        for(int i = 0; i < this.roundWords.size(); i++) {
            Word word = checkForWord(this.roundWords.get(i));

            if(word != null) {
                System.out.println(word);
                this.foundWords.add(word);
            }
        }       
    }

    private Word checkForWord(String word) {
        char initial = word.charAt(0);
        ArrayList<LetterCoord> startPoints = new ArrayList<LetterCoord>();

        int x = 0;  
        int y = 0;
        for(char[] row: this.letterGrid) {
            x = 0;

            for(char letter: row) {
                if(initial == letter) {
                    startPoints.add(new LetterCoord(x, y));
                }

                x++;
            }

            y++;
        }

        ArrayList<LetterCoord> letterCoords = null;
        for(int initialTry = 0; initialTry < startPoints.size(); initialTry++) {
            letterCoords = new ArrayList<LetterCoord>();    

            x = startPoints.get(initialTry).getX(); 
            y = startPoints.get(initialTry).getY();

            LetterCoord initialCoord = new LetterCoord(x, y);
            letterCoords.add(initialCoord);

            letterLoop: for(int letterIndex = 1; letterIndex < word.length(); letterIndex++) {
                LetterCoord lastCoord = letterCoords.get(letterCoords.size() - 1);  
                char currentChar = word.charAt(letterIndex);                        

                ArrayList<LetterCoord> letterLocations = getNeighbours(currentChar, lastCoord.getX(), lastCoord.getY());

                if(letterLocations == null) {
                    return null;    
                }       

                for(int foundIndex = 0; foundIndex < letterLocations.size(); foundIndex++) {
                    if(letterIndex != word.length() - 1 && true == false) {
                        char nextChar = word.charAt(letterIndex + 1);
                        int lastX = letterCoords.get(letterCoords.size() - 1).getX();
                        int lastY = letterCoords.get(letterCoords.size() - 1).getY();

                        ArrayList<LetterCoord> possibleIndex = getNeighbours(nextChar, lastX, lastY);
                        if(possibleIndex != null) {
                            if(!letterCoords.contains(letterLocations.get(foundIndex))) {
                                letterCoords.add(letterLocations.get(foundIndex));
                            }
                            continue letterLoop;
                        } else {
                            return null;
                        }
                    } else {
                        if(!letterCoords.contains(letterLocations.get(foundIndex))) {
                            letterCoords.add(letterLocations.get(foundIndex));

                            continue letterLoop;
                        }
                    }
                }
            }

            if(letterCoords != null) {
                if(letterCoords.size() == word.length()) {
                    Word w = new Word(word);
                    w.addList(letterCoords);
                    return w;
                } else {
                    return null;
                }
            }
        }

        if(letterCoords != null) {
            Word foundWord = new Word(word);
            foundWord.addList(letterCoords);

            return foundWord;
        }

        return null;
    }

    public ArrayList<LetterCoord> getNeighbours(char letterToSearch, int x, int y) {
        ArrayList<LetterCoord> neighbours = new ArrayList<LetterCoord>();

        for(int _y = y - 1; _y <= y + 1; _y++) {
            for(int _x = x - 1; _x <= x + 1; _x++) {
                if(_x < 0 || _y < 0 || (_x == x && _y == y) || _y > 3 || _x > 3) {
                    continue;
                }

                if(this.letterGrid[_y][_x] == letterToSearch && !neighbours.contains(new LetterCoord(_x, _y))) {
                    neighbours.add(new LetterCoord(_x, _y));
                }
            }
        }

        if(neighbours.isEmpty()) {
            return null;
        } else {
            return neighbours;
        }
    }
}

class Word {
    private String word;    
    private ArrayList<LetterCoord> letterCoords = new ArrayList<LetterCoord>();

    public Word(String word) {
        this.word = word;
    }

    public boolean addCoords(int x, int y) {
        LetterCoord lc = new LetterCoord(x, y);

        if(!this.letterCoords.contains(lc)) {
            this.letterCoords.add(lc);

            return true;
        }

        return false;
    }

    public void addList(ArrayList<LetterCoord> letterCoords) {
        this.letterCoords = letterCoords;
    } 

    @Override
    public String toString() {
        String outputString = this.word + " ";
        for(int i = 0; i < letterCoords.size(); i++) {
            outputString += "(" + letterCoords.get(i).getX() + ", " + letterCoords.get(i).getY() + ") ";
        }

        return outputString;
    }

    public String getWord() {
        return this.word;
    }

    public ArrayList<LetterCoord> getList() {
        return this.letterCoords;
    }
}

class LetterCoord extends ArrayList {
    private int x;          
    private int y;          

    public LetterCoord(int x, int y) {
        this.x = x;
        this.y = y;
    }

    public int getX() {
        return this.x;
    }

    public int getY() {
        return this.y;
    }

    @Override
    public boolean equals(Object o) {
        if(!(o instanceof LetterCoord)) {
            return false;
        }

        LetterCoord lc = (LetterCoord) o;

        if(this.x == lc.getX() &&
                this.y == lc.getY()) {
            return true;
        }

        return false;
    }

    @Override
    public int hashCode() {
        int hash = 7;
        hash = 29 * hash + this.x;
        hash = 24 * hash + this.y;
        return hash;
    }
}

我的答案和这里的其他答案一样,但我把它贴出来是因为它看起来比其他Python解决方案快一些,因为设置字典更快。(我对比了John Fouhy的解决方案。)设置后,解决的时间在噪声中下降。

grid = "fxie amlo ewbx astu".split()
nrows, ncols = len(grid), len(grid[0])

# A dictionary word that could be a solution must use only the grid's
# letters and have length >= 3. (With a case-insensitive match.)
import re
alphabet = ''.join(set(''.join(grid)))
bogglable = re.compile('[' + alphabet + ']{3,}$', re.I).match

words = set(word.rstrip('\n') for word in open('words') if bogglable(word))
prefixes = set(word[:i] for word in words
               for i in range(2, len(word)+1))

def solve():
    for y, row in enumerate(grid):
        for x, letter in enumerate(row):
            for result in extending(letter, ((x, y),)):
                yield result

def extending(prefix, path):
    if prefix in words:
        yield (prefix, path)
    for (nx, ny) in neighbors(path[-1]):
        if (nx, ny) not in path:
            prefix1 = prefix + grid[ny][nx]
            if prefix1 in prefixes:
                for result in extending(prefix1, path + ((nx, ny),)):
                    yield result

def neighbors((x, y)):
    for nx in range(max(0, x-1), min(x+2, ncols)):
        for ny in range(max(0, y-1), min(y+2, nrows)):
            yield (nx, ny)

示例用法:

# Print a maximal-length word and its path:
print max(solve(), key=lambda (word, path): len(word))

编辑:过滤掉长度小于3个字母的单词。

编辑2:我很好奇为什么Kent Fredric的Perl解决方案更快;它使用正则表达式匹配,而不是一组字符。在Python中做同样的事情,速度大约会翻倍。