这是因为%llu不能在Windows下正常工作，而%d不能处理64位整数。我建议使用PRIu64，你会发现它也可以移植到Linux上。

试试这个吧:

#include <stdio.h>
#include <inttypes.h>

int main() {
    unsigned long long int num = 285212672; //FYI: fits in 29 bits
    int normalInt = 5;
    /* NOTE: PRIu64 is a preprocessor macro and thus should go outside the quoted string. */
    printf("My number is %d bytes wide and its value is %" PRIu64 ". A normal number is %d.\n", sizeof(num), num, normalInt);
    return 0;
}

输出

My number is 8 bytes wide and its value is 285212672. A normal number is 5.

这是因为%llu不能在Windows下正常工作，而%d不能处理64位整数。我建议使用PRIu64，你会发现它也可以移植到Linux上。

试试这个吧:

#include <stdio.h>
#include <inttypes.h>

int main() {
    unsigned long long int num = 285212672; //FYI: fits in 29 bits
    int normalInt = 5;
    /* NOTE: PRIu64 is a preprocessor macro and thus should go outside the quoted string. */
    printf("My number is %d bytes wide and its value is %" PRIu64 ". A normal number is %d.\n", sizeof(num), num, normalInt);
    return 0;
}

输出

My number is 8 bytes wide and its value is 285212672. A normal number is 5.

如何使用printf格式化unsigned long long int ?

由于C99在转换说明符o,u,x, x之前使用了“ll”(ell-ell)。

很多答案中除了10进制选项外，还有16进制和8进制选项:

选择包括

unsigned long long num = 285212672;
printf("Base 10: %llu\n", num);
num += 0xFFF; // For more interesting hex/octal output.
printf("Base 16: %llX\n", num); // Use uppercase A-F
printf("Base 16: %llx\n", num); // Use lowercase a-f
printf("Base  8: %llo\n", num);
puts("or 0x,0X prefix");
printf("Base 16: %#llX %#llX\n", num, 0ull); // When non-zero, print leading 0X
printf("Base 16: %#llx %#llx\n", num, 0ull); // When non-zero, print leading 0x
printf("Base 16: 0x%llX\n", num); // My hex fave: lower case prefix, with A-F

输出

Base 10: 285212672
Base 16: 11000FFF
Base 16: 11000fff
Base  8: 2100007777
or 0x,0X prefix
Base 16: 0X11000FFF 0
Base 16: 0x11000fff 0
Base 16: 0x11000FFF

对于使用MSVS的long long(或__int64)，您应该使用%I64d:

__int64 a;
time_t b;
...
fprintf(outFile,"%I64d,%I64d\n",a,b);    //I is capital i

Hex:

printf("64bit: %llp", 0xffffffffffffffff);

输出:

64bit: FFFFFFFFFFFFFFFF

格式化unsigned long long的一种可能是使用uintmax_t。该类型自C99以来就可用，与stdint.h中发现的其他一些可选的精确宽度类型不同，uintmax_t是标准所要求的(它的带符号的对应对象intmax_t也是如此)。

根据标准，uintmax_t类型可以表示任何无符号整数类型的任何值。

你可以使用%ju转换说明符打印uintmax_t值(并且intmax_t可以使用%jd打印)。要打印一个不是uintmax_t的值，你必须先转换为uintmax_t以避免未定义的行为:

#include <stdio.h>
#include <stdint.h>

int main(void) {
    unsigned long long num = 285212672;
    printf("%ju\n", (uintmax_t)num);

    return 0;
}