import pandas as pd

import numpy as np

array=np.random.random((2,4))

df=pd.DataFrame(array, columns=('Test1', 'toto', 'test2', 'riri'))

print df

      Test1      toto     test2      riri
0  0.923249  0.572528  0.845464  0.144891
1  0.020438  0.332540  0.144455  0.741412

cols = [c for c in df.columns if c.lower()[:4] != 'test']

df=df[cols]

print df
       toto      riri
0  0.572528  0.144891
1  0.332540  0.741412

这里有一种方法:

df = df[df.columns.drop(list(df.filter(regex='Test')))]

你可以使用'filter'过滤掉你想要的列

import pandas as pd
import numpy as np

data2 = [{'test2': 1, 'result1': 2}, {'test': 5, 'result34': 10, 'c': 20}]

df = pd.DataFrame(data2)

df

    c   result1     result34    test    test2
0   NaN     2.0     NaN     NaN     1.0
1   20.0    NaN     10.0    5.0     NaN

现在过滤器

df.filter(like='result',axis=1)

得到. .

   result1  result34
0   2.0     NaN
1   NaN     10.0

你可以用df。过滤器获取匹配字符串的列列表，然后使用df.drop

resdf = df.drop(df.filter(like='Test',axis=1).columns.to_list(), axis=1)

这可以在一行中完成:

df = df.drop(df.filter(regex='Test').columns, axis=1)

问题声明“我想删除名称包含单词“Test”的所有列。”

test_columns = [col for col in df if 'Test' in col]
df.drop(columns=test_columns, inplace=True)