与Intersect()相反

Intersect可以用来查找两个集合之间的匹配，如下所示:

// Assign two arrays.
int[] array1 = { 1, 2, 3 };
int[] array2 = { 2, 3, 4 };
// Call Intersect extension method.
var intersect = array1.Intersect(array2);
// Write intersection to screen.
foreach (int value in intersect)
{
    Console.WriteLine(value); // Output: 2, 3
}

然而，我想实现的是相反的，我想从一个集合中列出从另一个集合中缺失的项目:

// Assign two arrays.
int[] array1 = { 1, 2, 3 };
int[] array2 = { 2, 3, 4 };
// Call "NonIntersect" extension method.
var intersect = array1.NonIntersect(array2); // I've made up the NonIntersect method
// Write intersection to screen.
foreach (int value in intersect)
{
    Console.WriteLine(value); // Output: 4
}

当前回答

string left = "411329_SOFT_MAC_GREEN";
string right= "SOFT_MAC_GREEN";

string[] l = left.Split('_');
string[] r = right.Split('_');

string[] distinctLeft = l.Distinct().ToArray();
string[] distinctRight = r.Distinct().ToArray();

var commonWord = l.Except(r, StringComparer.OrdinalIgnoreCase)
string result = String.Join("_",commonWord);
result = "411329"

2017-06-09 16:18:27

其他回答

我想你可能在找除了:

Except操作符生成集合两个序列之间的差异。它只返回第一个中的元素中未出现的序列第二。您可以选择提供你自己的相等比较函数。

查看这个链接，这个链接，或者谷歌，获取更多信息。

2011-04-11 10:57:04

/// <summary>
/// Given two list, compare and extract differences
/// http://stackoverflow.com/questions/5620266/the-opposite-of-intersect
/// </summary>
public class CompareList
{
    /// <summary>
    /// Returns list of items that are in initial but not in final list.
    /// </summary>
    /// <param name="listA"></param>
    /// <param name="listB"></param>
    /// <returns></returns>
    public static IEnumerable<string> NonIntersect(
        List<string> initial, List<string> final)
    {
        //subtracts the content of initial from final
        //assumes that final.length < initial.length
        return initial.Except(final);
    }

    /// <summary>
    /// Returns the symmetric difference between the two list.
    /// http://en.wikipedia.org/wiki/Symmetric_difference
    /// </summary>
    /// <param name="initial"></param>
    /// <param name="final"></param>
    /// <returns></returns>
    public static IEnumerable<string> SymmetricDifference(
        List<string> initial, List<string> final)
    {
        IEnumerable<string> setA = NonIntersect(final, initial);
        IEnumerable<string> setB = NonIntersect(initial, final);
        // sum and return the two set.
        return setA.Concat(setB);
    }
}

2012-12-03 10:43:00

如上所述，如果你想要得到4作为结果，你可以这样做:

var nonintersect = array2.Except(array1);

如果你想要真正的非交集(也是1和4)，那么这个应该可以做到:

var nonintersect = array1.Except(array2).Union( array2.Except(array1));

这不是性能最好的解决方案，但对于小列表来说，它应该工作得很好。

2011-04-11 10:56:20

string left = "411329_SOFT_MAC_GREEN";
string right= "SOFT_MAC_GREEN";

string[] l = left.Split('_');
string[] r = right.Split('_');

string[] distinctLeft = l.Distinct().ToArray();
string[] distinctRight = r.Distinct().ToArray();

var commonWord = l.Except(r, StringComparer.OrdinalIgnoreCase)
string result = String.Join("_",commonWord);
result = "411329"

2017-06-09 16:18:27

我不是100%确定你的非相交方法应该做什么(关于集合论)-是吗 B \ A(所有来自B而不在A中出现的东西)? 如果是，那么您应该能够使用Except操作(B.Except(A))。

2011-04-11 11:01:24

与Intersect()相反

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