使用MySQL,我可以执行以下操作:
SELECT hobbies FROM peoples_hobbies WHERE person_id = 5;
我的输出:
shopping
fishing
coding
但我只想要1行1列:
预期输出:
shopping, fishing, coding
原因是我从多个表中选择了多个值,在所有的连接之后,我得到了比我想要的多得多的行。
我在MySQL Doc上查找了一个函数,它看起来不像CONCAT或CONCAT_WS函数接受结果集。
这里有人知道怎么做吗?
您可以使用GROUP_CONCAT:
SELECT person_id,
GROUP_CONCAT(hobbies SEPARATOR ', ')
FROM peoples_hobbies
GROUP BY person_id;
正如Ludwig在评论中所说,您可以添加DISTINCT运算符以避免重复:
SELECT person_id,
GROUP_CONCAT(DISTINCT hobbies SEPARATOR ', ')
FROM peoples_hobbies
GROUP BY person_id;
正如Jan在他们的评论中所说,您也可以在使用ORDER BY将值内爆之前对其进行排序:
SELECT person_id,
GROUP_CONCAT(hobbies ORDER BY hobbies ASC SEPARATOR ', ')
FROM peoples_hobbies
GROUP BY person_id;
正如Dag在评论中所说,结果有1024字节的限制。要解决此问题,请在查询之前运行此查询:
SET group_concat_max_len = 2048;
当然,您可以根据需要更改2048。要计算和分配值:
SET group_concat_max_len = CAST(
(SELECT SUM(LENGTH(hobbies)) + COUNT(*) * LENGTH(', ')
FROM peoples_hobbies
GROUP BY person_id) AS UNSIGNED);
现在已经很晚了,但对于那些正在搜索“使用透视表将多个MySQL行连接到一个字段中”的人来说会很有帮助:)
查询:
SELECT pm.id, pm.name, GROUP_CONCAT(c.name) as channel_names
FROM payment_methods pm
LEFT JOIN payment_methods_channels_pivot pmcp ON pmcp.payment_method_id = pm.id
LEFT JOIN channels c ON c.id = pmcp.channel_id
GROUP BY pm.id
桌子
payment_methods
id | name
1 | PayPal
channels
id | name
1 | Google
2 | Faceook
payment_methods_channels_pivot
payment_method_id | channel_id
1 | 1
1 | 2
输出: