使用MySQL，我可以执行以下操作：
SELECT hobbies FROM peoples_hobbies WHERE person_id = 5;
我的输出：
shopping
fishing
coding
但我只想要1行1列：
预期输出：
shopping, fishing, coding
原因是我从多个表中选择了多个值，在所有的连接之后，我得到了比我想要的多得多的行。
我在MySQL Doc上查找了一个函数，它看起来不像CONCAT或CONCAT_WS函数接受结果集。
这里有人知道怎么做吗？
当前回答
使用GROUP_NCAT：
SELECT GROUP_CONCAT(hobbies) FROM peoples_hobbies WHERE person_id = 5;
其他回答
在sql server中，使用string_agg将行字段值透视为列：
select string_agg(field1, ', ') a FROM mytable
or
select string_agg(field1, ', ') within group (order by field1 dsc) a FROM mytable group by field2
本例中另一个有趣的例子-
下面是people_hobbies示例表的结构-
DESCRIBE people_hobbies;
+---------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------+--------------+------+-----+---------+----------------+
| id | int unsigned | NO | PRI | NULL | auto_increment |
| ppl_id | int unsigned | YES | MUL | NULL | |
| name | varchar(200) | YES | | NULL | |
| hby_id | int unsigned | YES | MUL | NULL | |
| hobbies | varchar(50) | YES | | NULL | |
+---------+--------------+------+-----+---------+----------------+
该表的填充方式如下-
SELECT * FROM people_hobbies;
+----+--------+-----------------+--------+-----------+
| id | ppl_id | name | hby_id | hobbies |
+----+--------+-----------------+--------+-----------+
| 1 | 1 | Shriya Jain | 1 | reading |
| 2 | 4 | Shirley Setia | 4 | coding |
| 3 | 2 | Varsha Tripathi | 7 | gardening |
| 4 | 3 | Diya Ghosh | 2 | fishing |
| 5 | 4 | Shirley Setia | 3 | gaming |
| 6 | 1 | Shriya Jain | 6 | cycling |
| 7 | 2 | Varsha Tripathi | 1 | reading |
| 8 | 3 | Diya Ghosh | 5 | shopping |
| 9 | 3 | Diya Ghosh | 4 | coding |
| 10 | 4 | Shirley Setia | 1 | reading |
| 11 | 1 | Shriya Jain | 4 | coding |
| 12 | 1 | Shriya Jain | 3 | gaming |
| 13 | 4 | Shirley Setia | 2 | fishing |
| 14 | 4 | Shirley Setia | 7 | gardening |
| 15 | 2 | Varsha Tripathi | 3 | gaming |
| 16 | 2 | Varsha Tripathi | 2 | fishing |
| 17 | 1 | Shriya Jain | 5 | shopping |
| 18 | 1 | Shriya Jain | 7 | gardening |
| 19 | 3 | Diya Ghosh | 1 | reading |
| 20 | 4 | Shirley Setia | 5 | shopping |
+----+--------+-----------------+--------+-----------+
现在，生成了一个表hobby_list，其中包含所有人的列表和每个人的爱好列表，每个爱好在一行中-
CREATE TABLE hobby_list AS
-> SELECT ppl_id, name,
-> GROUP_CONCAT(hobbies ORDER BY hby_id SEPARATOR "\n")
-> AS hobbies
-> FROM people_hobbies
-> GROUP BY ppl_id
-> ORDER BY ppl_id;
SELECT * FROM hobby_list;
使用GROUP_NCAT：
SELECT GROUP_CONCAT(hobbies) FROM peoples_hobbies WHERE person_id = 5;
如果您的MySQL版本（4.1）支持GROUP_CONCAT，请查看GROUP_CONNAT。有关详细信息，请参阅文档。
它看起来像：
SELECT GROUP_CONCAT(hobbies SEPARATOR ', ')
FROM peoples_hobbies
WHERE person_id = 5
GROUP BY 'all';
连接多个单独行的替代语法
警告：这篇文章会让你饿。
鉴于：
我发现自己想要选择多个单独的行，而不是一个组，并在某个字段上进行连接。
假设您有一个产品ID及其名称和价格表：
+------------+--------------------+-------+
| product_id | name | price |
+------------+--------------------+-------+
| 13 | Double Double | 5 |
| 14 | Neapolitan Shake | 2 |
| 15 | Animal Style Fries | 3 |
| 16 | Root Beer | 2 |
| 17 | Lame T-Shirt | 15 |
+------------+--------------------+-------+
然后，你有一些花哨的聊天ajax，将这些小狗列为复选框。
饥饿的河马用户选择13、15、16。她今天没有甜点。。。
查找：
一种用纯mysql在一行中总结用户订单的方法。
解决方案：
将GROUP_NCAT和IN子句一起使用：
mysql> SELECT GROUP_CONCAT(name SEPARATOR ' + ') AS order_summary FROM product WHERE product_id IN (13, 15, 16);
哪些输出：
+------------------------------------------------+
| order_summary |
+------------------------------------------------+
| Double Double + Animal Style Fries + Root Beer |
+------------------------------------------------+
奖金解决方案：
如果您也想要总价，请输入SUM（）：
mysql> SELECT GROUP_CONCAT(name SEPARATOR ' + ') AS order_summary, SUM(price) AS total FROM product WHERE product_id IN (13, 15, 16);
+------------------------------------------------+-------+
| order_summary | total |
+------------------------------------------------+-------+
| Double Double + Animal Style Fries + Root Beer | 10 |
+------------------------------------------------+-------+
