这对我来说很管用:

class MyClass {
    static MyEnum: { Value1; Value2; Value3; }
    = {
        Value1: "Value1",
        Value2: "Value2",
        Value3: "Value3"
    };
}

or

module MyModule {
    export var MyEnum: { Value1; Value2; Value3; }
    = {
        Value1: "Value1",
        Value2: "Value2",
        Value3: "Value3"
    };
}

8)

更新:在发布这篇文章后不久，我发现了另一种方法，但忘记发布更新(然而，上面已经有人提到过了):

enum MyEnum {
    value1 = <any>"value1 ", 
    value2 = <any>"value2 ", 
    value3 = <any>"value3 " 
}

这对我来说很管用:

class MyClass {
    static MyEnum: { Value1; Value2; Value3; }
    = {
        Value1: "Value1",
        Value2: "Value2",
        Value3: "Value3"
    };
}

or

module MyModule {
    export var MyEnum: { Value1; Value2; Value3; }
    = {
        Value1: "Value1",
        Value2: "Value2",
        Value3: "Value3"
    };
}

8)

更新:在发布这篇文章后不久，我发现了另一种方法，但忘记发布更新(然而，上面已经有人提到过了):

enum MyEnum {
    value1 = <any>"value1 ", 
    value2 = <any>"value2 ", 
    value3 = <any>"value3 " 
}

在最新版本(1.0RC)的TypeScript中，你可以像这样使用枚举:

enum States {
    New,
    Active,
    Disabled
} 

// this will show message '0' which is number representation of enum member
alert(States.Active); 

// this will show message 'Disabled' as string representation of enum member
alert(States[States.Disabled]);

更新1

要从string value中获取enum成员的number值，你可以使用这个:

var str = "Active";
// this will show message '1'
alert(States[str]);

更新2

在最新的TypeScript 2.4中，引入了字符串enum，如下所示:

enum ActionType {
    AddUser = "ADD_USER",
    DeleteUser = "DELETE_USER",
    RenameUser = "RENAME_USER",

    // Aliases
    RemoveUser = DeleteUser,
}

有关TypeScript 2.4的更多信息，请阅读MSDN上的博客。

TypeScript 2 + 4。

你现在可以直接将字符串值分配给enum成员:

enum Season {
    Winter = "winter",
    Spring = "spring",
    Summer = "summer",
    Fall = "fall"
}

更多信息见#15486。

打印稿1.8 +

在TypeScript 1.8+中，你可以创建一个字符串文字类型来定义类型，并为值列表创建一个同名的对象。它模仿字符串enum的预期行为。

这里有一个例子:

type MyStringEnum = "member1" | "member2";

const MyStringEnum = {
    Member1: "member1" as MyStringEnum,
    Member2: "member2" as MyStringEnum
};

它将像字符串enum一样工作:

// implicit typing example
let myVariable = MyStringEnum.Member1; // ok
myVariable = "member2";                // ok
myVariable = "some other value";       // error, desired

// explict typing example
let myExplicitlyTypedVariable: MyStringEnum;
myExplicitlyTypedVariable = MyStringEnum.Member1; // ok
myExplicitlyTypedVariable = "member2";            // ok
myExplicitlyTypedVariable = "some other value";   // error, desired

确保输入对象中的所有字符串!如果不这样做，那么在上面的第一个例子中，变量将不会隐式地类型化为MyStringEnum。

最近在使用TypeScript 1.0.1时遇到了这个问题，并以这种方式解决了:

enum IEvents {
        /** A click on a product or product link for one or more products. */
        CLICK,
        /** A view of product details. */
        DETAIL,
        /** Adding one or more products to a shopping cart. */
        ADD,
        /** Remove one or more products from a shopping cart. */
        REMOVE,
        /** Initiating the checkout process for one or more products. */
        CHECKOUT,
        /** Sending the option value for a given checkout step. */
        CHECKOUT_OPTION,
        /** The sale of one or more products. */
        PURCHASE,
        /** The refund of one or more products. */
        REFUND,
        /** A click on an internal promotion. */
        PROMO_CLICK
}

var Events = [
        'click',
        'detail',
        'add',
        'remove',
        'checkout',
        'checkout_option',
        'purchase',
        'refund',
        'promo_click'
];

function stuff(event: IEvents):boolean {
        // event can now be only IEvents constants
        Events[event]; // event is actually a number that matches the index of the array
}
// stuff('click') won't work, it needs to be called using stuff(IEvents.CLICK)

更新:TypeScript 3.4

你可以简单地使用const:

const AwesomeType = {
   Foo: "foo",
   Bar: "bar"
} as const;

打字稿2.1

这也可以用这种方式完成。希望它能帮助到一些人。

const AwesomeType = {
    Foo: "foo" as "foo",
    Bar: "bar" as "bar"
};

type AwesomeType = (typeof AwesomeType)[keyof typeof AwesomeType];

console.log(AwesomeType.Bar); // returns bar
console.log(AwesomeType.Foo); // returns foo

function doSth(awesometype: AwesomeType) {
    console.log(awesometype);
}

doSth("foo") // return foo
doSth("bar") // returns bar
doSth(AwesomeType.Bar) // returns bar
doSth(AwesomeType.Foo) // returns foo
doSth('error') // does not compile