我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
当前回答
function parseUrl(url) {
var m = url.match(/^((?:([^:\/?#]+:)(?:\/\/))?((?:([^\/?#:]*):([^\/?#:]*)@)?([^\/?#:]*)(?::([^\/?#:]*))?))?([^?#]*)(\?[^#]*)?(#.*)?$/),
r = {
hash: m[10] || "", // #asd
host: m[3] || "", // localhost:257
hostname: m[6] || "", // localhost
href: m[0] || "", // http://username:password@localhost:257/deploy/?asd=asd#asd
origin: m[1] || "", // http://username:password@localhost:257
pathname: m[8] || (m[1] ? "/" : ""), // /deploy/
port: m[7] || "", // 257
protocol: m[2] || "", // http:
search: m[9] || "", // ?asd=asd
username: m[4] || "", // username
password: m[5] || "" // password
};
if (r.protocol.length == 2) {
r.protocol = "file:///" + r.protocol.toUpperCase();
r.origin = r.protocol + "//" + r.host;
}
r.href = r.origin + r.pathname + r.search + r.hash;
return r;
};
parseUrl("http://username:password@localhost:257/deploy/?asd=asd#asd");
它既适用于绝对url,也适用于相对url
其他回答
js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:
var some_uri = new URI("http://www.example.com/foo/bar");
alert(some_uri.authority); // www.example.com
alert(some_uri); // http://www.example.com/foo/bar
var blah = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full); // http://www.example.com/foo/blah
怎么样?
'https://stackoverflow.com/questions/736513/how-do-i-parse-a-url-into-hostname-and-path-in-javascript'.split('//').pop() .split('/')[0]
结果:
“stackoverflow.com”
var getLocation = function(href) {
var l = document.createElement("a");
l.href = href;
return l;
};
var l = getLocation("http://example.com/path");
console.debug(l.hostname)
>> "example.com"
console.debug(l.pathname)
>> "/path"
这不会解析查询和散列,但除此之外它工作得很好。
const getURIParts = (url) => { const matches = url.match(/^(\w+?:\/\/)?([\w-\.]+(?=\/?))?:?(\d*)?([^:]*)/) return { scheme: matches ? matches[1] : undefined, host: matches ? matches[2] : '', port: matches ? matches[3] : undefined, pathname: matches ? matches[4] : '' } } console.log(getURIParts("")) console.log(getURIParts("http://localhost/bla")) console.log(getURIParts("https://api.spotify.com/")) console.log(getURIParts("https://api.spotify.com")) console.log(getURIParts("wss://wss.slack.com/link/?ticket=1234-5678")) console.log(getURIParts("localhost")) console.log(getURIParts("localhost/bla")) console.log(getURIParts("localhost/")) console.log(getURIParts("api.spotify.com/bla/two")) console.log(getURIParts("api.spotify.com:8000/bla/two")) console.log(getURIParts("https://api.spotify.com:8800/")) console.log(getURIParts("/mp3-preview/f504e6b8e037771318656394f532dede4f9bcaea"))
以下是我从https://gist.github.com/1847816复制的一个版本,但经过重写,以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长,因此将有限数量的值复制到结果将有助于简化结果。
/**
* See: https://gist.github.com/1847816
* Parse a URI, returning an object similar to Location
* Usage: var uri = parseUri("hello?search#hash")
*/
function parseUri(url) {
var result = {};
var anchor = document.createElement('a');
anchor.href = url;
var keys = 'protocol hostname host pathname port search hash href'.split(' ');
for (var keyIndex in keys) {
var currentKey = keys[keyIndex];
result[currentKey] = anchor[currentKey];
}
result.toString = function() { return anchor.href; };
result.requestUri = result.pathname + result.search;
return result;
}