我如何在javascript中解析URL到主机名和路径?

我想拿一根绳子

var a = "http://example.com/aa/bb/"

然后把它加工成一个物体

a.hostname == "example.com"

and

a.pathname == "/aa/bb"

当前回答

function parseUrl(url) {
    var m = url.match(/^((?:([^:\/?#]+:)(?:\/\/))?((?:([^\/?#:]*):([^\/?#:]*)@)?([^\/?#:]*)(?::([^\/?#:]*))?))?([^?#]*)(\?[^#]*)?(#.*)?$/),
        r = {
            hash: m[10] || "",                   // #asd
            host: m[3] || "",                    // localhost:257
            hostname: m[6] || "",                // localhost
            href: m[0] || "",                    // http://username:password@localhost:257/deploy/?asd=asd#asd
            origin: m[1] || "",                  // http://username:password@localhost:257
            pathname: m[8] || (m[1] ? "/" : ""), // /deploy/
            port: m[7] || "",                    // 257
            protocol: m[2] || "",                // http:
            search: m[9] || "",                  // ?asd=asd
            username: m[4] || "",                // username
            password: m[5] || ""                 // password
        };
    if (r.protocol.length == 2) {
        r.protocol = "file:///" + r.protocol.toUpperCase();
        r.origin = r.protocol + "//" + r.host;
    }
    r.href = r.origin + r.pathname + r.search + r.hash;
    return r;
};
parseUrl("http://username:password@localhost:257/deploy/?asd=asd#asd");

它既适用于绝对url，也适用于相对url

2016-09-03 14:30:10

其他回答

为什么不用呢?

        $scope.get_location=function(url_str){
        var parser = document.createElement('a');
        parser.href =url_str;//"http://example.com:3000/pathname/?search=test#hash";
        var info={
            protocol:parser.protocol,   
            hostname:parser.hostname, // => "example.com"
            port:parser.port,     // => "3000"
            pathname:parser.pathname, // => "/pathname/"
            search:parser.search,   // => "?search=test"
            hash:parser.hash,     // => "#hash"
            host:parser.host, // => "example.com:3000"      
        }
        return info;
    }
    alert( JSON.stringify( $scope.get_location("http://localhost:257/index.php/deploy/?asd=asd#asd"),null,4 ) );

2017-06-12 06:26:05

var getLocation = function(href) {
    var l = document.createElement("a");
    l.href = href;
    return l;
};
var l = getLocation("http://example.com/path");
console.debug(l.hostname)
>> "example.com"
console.debug(l.pathname)
>> "/path"

2009-04-10 07:33:31

使用模块模式的简单而健壮的解决方案。这包括修复IE的路径名不总是有前导正斜杠(/)。

我已经创建了一个Gist和一个JSFiddle，它提供了一个更动态的解析器。我建议你检查一下并提供反馈。

var URLParser = (function (document) {
    var PROPS = 'protocol hostname host pathname port search hash href'.split(' ');
    var self = function (url) {
        this.aEl = document.createElement('a');
        this.parse(url);
    };
    self.prototype.parse = function (url) {
        this.aEl.href = url;
        if (this.aEl.host == "") {
           this.aEl.href = this.aEl.href;
        }
        PROPS.forEach(function (prop) {
            switch (prop) {
                case 'hash':
                    this[prop] = this.aEl[prop].substr(1);
                    break;
                default:
                    this[prop] = this.aEl[prop];
            }
        }, this);
        if (this.pathname.indexOf('/') !== 0) {
            this.pathname = '/' + this.pathname;
        }
        this.requestUri = this.pathname + this.search;
    };
    self.prototype.toObj = function () {
        var obj = {};
        PROPS.forEach(function (prop) {
            obj[prop] = this[prop];
        }, this);
        obj.requestUri = this.requestUri;
        return obj;
    };
    self.prototype.toString = function () {
        return this.href;
    };
    return self;
})(document);

Demo

输出

{
 "protocol": "https:",
 "hostname": "www.example.org",
 "host": "www.example.org:5887",
 "pathname": "/foo/bar",
 "port": "5887",
 "search": "?a=1&b=2",
 "hash": "section-1",
 "href": "https://www.example.org:5887/foo/bar?a=1&b=2#section-1",
 "requestUri": "/foo/bar?a=1&b=2"
}
{
 "protocol": "ftp:",
 "hostname": "www.files.com",
 "host": "www.files.com:22",
 "pathname": "/folder",
 "port": "22",
 "search": "?id=7",
 "hash": "",
 "href": "ftp://www.files.com:22/folder?id=7",
 "requestUri": "/folder?id=7"
}

2015-01-15 13:37:22

freddiefujiwara的答案很好，但我也需要在ie中支持相对url。我想出了以下解决方案:

function getLocation(href) {
    var location = document.createElement("a");
    location.href = href;
    // IE doesn't populate all link properties when setting .href with a relative URL,
    // however .href will return an absolute URL which then can be used on itself
    // to populate these additional fields.
    if (location.host == "") {
      location.href = location.href;
    }
    return location;
};

现在使用它来获得所需的属性:

var a = getLocation('http://example.com/aa/bb/');
document.write(a.hostname);
document.write(a.pathname);

例子:

function getLocation(href) { var location = document.createElement("a"); location.href = href; // IE doesn't populate all link properties when setting .href with a relative URL, // however .href will return an absolute URL which then can be used on itself // to populate these additional fields. if (location.host == "") { location.href = location.href; } return location; }; var urlToParse = 'http://example.com/aa/bb/', a = getLocation(urlToParse); document.write('Absolute URL: ' + urlToParse); document.write('<br />'); document.write('Hostname: ' + a.hostname); document.write('<br />'); document.write('Pathname: ' + a.pathname);

2012-11-15 20:48:21

以下是我从https://gist.github.com/1847816复制的一个版本，但经过重写，以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长，因此将有限数量的值复制到结果将有助于简化结果。

/**
 * See: https://gist.github.com/1847816
 * Parse a URI, returning an object similar to Location
 * Usage: var uri = parseUri("hello?search#hash")
 */
function parseUri(url) {

  var result = {};

  var anchor = document.createElement('a');
  anchor.href = url;

  var keys = 'protocol hostname host pathname port search hash href'.split(' ');
  for (var keyIndex in keys) {
    var currentKey = keys[keyIndex]; 
    result[currentKey] = anchor[currentKey];
  }

  result.toString = function() { return anchor.href; };
  result.requestUri = result.pathname + result.search;  
  return result;

}

2012-03-19 20:16:52

我如何在javascript中解析URL到主机名和路径?

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