我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
当前回答
freddiefujiwara的答案很好,但我也需要在ie中支持相对url。我想出了以下解决方案:
function getLocation(href) {
var location = document.createElement("a");
location.href = href;
// IE doesn't populate all link properties when setting .href with a relative URL,
// however .href will return an absolute URL which then can be used on itself
// to populate these additional fields.
if (location.host == "") {
location.href = location.href;
}
return location;
};
现在使用它来获得所需的属性:
var a = getLocation('http://example.com/aa/bb/');
document.write(a.hostname);
document.write(a.pathname);
例子:
function getLocation(href) { var location = document.createElement("a"); location.href = href; // IE doesn't populate all link properties when setting .href with a relative URL, // however .href will return an absolute URL which then can be used on itself // to populate these additional fields. if (location.host == "") { location.href = location.href; } return location; }; var urlToParse = 'http://example.com/aa/bb/', a = getLocation(urlToParse); document.write('Absolute URL: ' + urlToParse); document.write('<br />'); document.write('Hostname: ' + a.hostname); document.write('<br />'); document.write('Pathname: ' + a.pathname);
其他回答
今天我遇到了这个问题,我发现:URL - MDN Web api
var url = new URL("http://test.example.com/dir/subdir/file.html#hash");
这返回:
{ hash:"#hash", host:"test.example.com", hostname:"test.example.com", href:"http://test.example.com/dir/subdir/file.html#hash", origin:"http://test.example.com", password:"", pathname:"/dir/subdir/file.html", port:"", protocol:"http:", search: "", username: "" }
希望我的第一篇文章能帮助到你!
AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/
<!DOCTYPE html>
<html>
<head>
<title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">
<h3>Parse URL using AngularJS</h3>
url: <input type="text" ng-model="url" value="" style="width:780px;">
<ul>
<li>href = {{parser.href}}</li>
<li>protocol = {{parser.protocol}}</li>
<li>host = {{parser.host}}</li>
<li>hostname = {{parser.hostname}}</li>
<li>port = {{parser.port}}</li>
<li>pathname = {{parser.pathname}}</li>
<li>hash = {{parser.hash}}</li>
<li>search = {{parser.search}}</li>
</ul>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>
<script>
function AppCtrl($scope) {
$scope.$watch('url', function() {
$scope.parser.href = $scope.url;
});
$scope.init = function() {
$scope.parser = document.createElement('a');
$scope.url = window.location;
}
}
</script>
</body>
</html>
对于那些正在寻找在IE, Firefox和Chrome中工作的现代解决方案的人:
这些使用超链接元素的解决方案都不会在chrome中起同样的作用。如果你传递一个无效(或空白)的url给chrome,它总是会返回脚本被调用的主机。所以在IE中你会得到空白,而在Chrome中你会得到localhost(或其他什么)。
如果你试图看着推荐人,这是骗人的。你需要确保你返回的主机在原始url中,以处理这个问题:
function getHostNameFromUrl(url) {
// <summary>Parses the domain/host from a given url.</summary>
var a = document.createElement("a");
a.href = url;
// Handle chrome which will default to domain where script is called from if invalid
return url.indexOf(a.hostname) != -1 ? a.hostname : '';
}
你也可以使用来自Locutus项目(前php.js)的parse_url()函数。
代码:
parse_url('http://username:password@hostname/path?arg=value#anchor');
结果:
{
scheme: 'http',
host: 'hostname',
user: 'username',
pass: 'password',
path: '/path',
query: 'arg=value',
fragment: 'anchor'
}
以下是我从https://gist.github.com/1847816复制的一个版本,但经过重写,以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长,因此将有限数量的值复制到结果将有助于简化结果。
/**
* See: https://gist.github.com/1847816
* Parse a URI, returning an object similar to Location
* Usage: var uri = parseUri("hello?search#hash")
*/
function parseUri(url) {
var result = {};
var anchor = document.createElement('a');
anchor.href = url;
var keys = 'protocol hostname host pathname port search hash href'.split(' ');
for (var keyIndex in keys) {
var currentKey = keys[keyIndex];
result[currentKey] = anchor[currentKey];
}
result.toString = function() { return anchor.href; };
result.requestUri = result.pathname + result.search;
return result;
}