我想拿一根绳子

var a = "http://example.com/aa/bb/"

然后把它加工成一个物体

a.hostname == "example.com"

and

a.pathname == "/aa/bb"

当前回答

js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:

var some_uri = new URI("http://www.example.com/foo/bar");

alert(some_uri.authority); // www.example.com
alert(some_uri);           // http://www.example.com/foo/bar

var blah      = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full);         // http://www.example.com/foo/blah

其他回答

试试这个:

函数getUrlPath (str) { //fakepath当url没有路径 var fakepath = "/FakPath"; Var url = str+fakepath; Var reg = /.+?\:\/\/.+?(\/.+?)(?:#|\?|$)/; Var output = reg.exec(url); //检查"output" != null 返回(输出)?输出[1].replace(fakepath,""): fakepath; } Var myurl = "https://stackoverflow.com/questions/736513/"; const path = getUrlPath(myurl); Console.log (path); //output: /questions/736513/

为什么不用呢?

        $scope.get_location=function(url_str){
        var parser = document.createElement('a');
        parser.href =url_str;//"http://example.com:3000/pathname/?search=test#hash";
        var info={
            protocol:parser.protocol,   
            hostname:parser.hostname, // => "example.com"
            port:parser.port,     // => "3000"
            pathname:parser.pathname, // => "/pathname/"
            search:parser.search,   // => "?search=test"
            hash:parser.hash,     // => "#hash"
            host:parser.host, // => "example.com:3000"      
        }
        return info;
    }
    alert( JSON.stringify( $scope.get_location("http://localhost:257/index.php/deploy/?asd=asd#asd"),null,4 ) );

当然,在>2016年,正确的答案是使用URL API 对于页面URL window.location And for <a href="…""> html lanchorelement API

也支持旧浏览器,使用polyfill:

<script crossorigin="anonymous" src="https://polyfill.io/v3/polyfill.min.js?features=URL"></script>

但作为另一种选择,它可以通过RegEx模式简单而准确地处理:

function URIinfo(s) { s=s.match(/^(([^/]*?:)\/*((?:([^:]+):([^@]+)@)?([^/:]{2,}|\[[\w:]+])(:\d*)?(?=\/|$))?)?((.*?\/)?(([^/]*?)(\.[^/.]+?)?))(\?.*?)?(#.*)?$/); return {origin:s[1],protocol:s[2],host:s[3],username:s[4],password:s[5],hostname:s[6],port:s[7],path:s[8],folders:s[9],file:s[10],filename:s[11],fileext:s[12],search:s[13],hash:s[14]}; } var sample='http://user:password@my.site.com:8080/onefolder/folder.name/file.min.js?query=http://my.site.com:8080/file.exe#hash-root:/file/1.txt'; console.log (URIinfo(sample)); /* { "origin": "http://user:password@my.site.com:8080", "protocol": "http:", "host": "user:password@my.site.com:8080", "username": "user", "password": "password", "hostname": "my.site.com", "port": ":8080", "path": "/onefolder/folder.name/file.min.js", "folders": "/onefolder/folder.name/", "file": "file.min.js", "filename": "file.min", "fileext": ".js", "search": "?query=http://my.site.com:8080/file.exe", "hash": "#hash-root:/file/1.txt" } */

使用正则表达式

任何形式的

绝对/相对路径 IPv4 / IPv6 网络协议/本地文件 查询/散列

返回所有URL选项,但不返回searchParams

(+)也将返回文件信息,如PHP pathInfo

AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/

<!DOCTYPE html>
<html>
<head>
    <title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">

<h3>Parse URL using AngularJS</h3>

url: <input type="text" ng-model="url" value="" style="width:780px;">

<ul>
    <li>href = {{parser.href}}</li>
    <li>protocol = {{parser.protocol}}</li>
    <li>host = {{parser.host}}</li>
    <li>hostname = {{parser.hostname}}</li>
    <li>port = {{parser.port}}</li>
    <li>pathname = {{parser.pathname}}</li>
    <li>hash = {{parser.hash}}</li>
    <li>search = {{parser.search}}</li>
</ul>

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>

<script>
function AppCtrl($scope) {

    $scope.$watch('url', function() {
        $scope.parser.href = $scope.url;
    });

    $scope.init = function() {
        $scope.parser = document.createElement('a');
        $scope.url = window.location;
    }

}
</script>

</body>
</html>

以下是我从https://gist.github.com/1847816复制的一个版本,但经过重写,以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长,因此将有限数量的值复制到结果将有助于简化结果。

/**
 * See: https://gist.github.com/1847816
 * Parse a URI, returning an object similar to Location
 * Usage: var uri = parseUri("hello?search#hash")
 */
function parseUri(url) {

  var result = {};

  var anchor = document.createElement('a');
  anchor.href = url;

  var keys = 'protocol hostname host pathname port search hash href'.split(' ');
  for (var keyIndex in keys) {
    var currentKey = keys[keyIndex]; 
    result[currentKey] = anchor[currentKey];
  }

  result.toString = function() { return anchor.href; };
  result.requestUri = result.pathname + result.search;  
  return result;

}