我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
当前回答
js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:
var some_uri = new URI("http://www.example.com/foo/bar");
alert(some_uri.authority); // www.example.com
alert(some_uri); // http://www.example.com/foo/bar
var blah = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full); // http://www.example.com/foo/blah
其他回答
今天我遇到了这个问题,我发现:URL - MDN Web api
var url = new URL("http://test.example.com/dir/subdir/file.html#hash");
这返回:
{ hash:"#hash", host:"test.example.com", hostname:"test.example.com", href:"http://test.example.com/dir/subdir/file.html#hash", origin:"http://test.example.com", password:"", pathname:"/dir/subdir/file.html", port:"", protocol:"http:", search: "", username: "" }
希望我的第一篇文章能帮助到你!
在这里找到:https://gist.github.com/jlong/2428561
var parser = document.createElement('a');
parser.href = "http://example.com:3000/pathname/?search=test#hash";
parser.protocol; // => "http:"
parser.host; // => "example.com:3000"
parser.hostname; // => "example.com"
parser.port; // => "3000"
parser.pathname; // => "/pathname/"
parser.hash; // => "#hash"
parser.search; // => "?search=test"
parser.origin; // => "http://example.com:3000"
那么简单的正则表达式呢?
url = "http://www.example.com/path/to/somwhere";
urlParts = /^(?:\w+\:\/\/)?([^\/]+)(.*)$/.exec(url);
hostname = urlParts[1]; // www.example.com
path = urlParts[2]; // /path/to/somwhere
为什么不用呢?
$scope.get_location=function(url_str){
var parser = document.createElement('a');
parser.href =url_str;//"http://example.com:3000/pathname/?search=test#hash";
var info={
protocol:parser.protocol,
hostname:parser.hostname, // => "example.com"
port:parser.port, // => "3000"
pathname:parser.pathname, // => "/pathname/"
search:parser.search, // => "?search=test"
hash:parser.hash, // => "#hash"
host:parser.host, // => "example.com:3000"
}
return info;
}
alert( JSON.stringify( $scope.get_location("http://localhost:257/index.php/deploy/?asd=asd#asd"),null,4 ) );
AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/
<!DOCTYPE html>
<html>
<head>
<title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">
<h3>Parse URL using AngularJS</h3>
url: <input type="text" ng-model="url" value="" style="width:780px;">
<ul>
<li>href = {{parser.href}}</li>
<li>protocol = {{parser.protocol}}</li>
<li>host = {{parser.host}}</li>
<li>hostname = {{parser.hostname}}</li>
<li>port = {{parser.port}}</li>
<li>pathname = {{parser.pathname}}</li>
<li>hash = {{parser.hash}}</li>
<li>search = {{parser.search}}</li>
</ul>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>
<script>
function AppCtrl($scope) {
$scope.$watch('url', function() {
$scope.parser.href = $scope.url;
});
$scope.init = function() {
$scope.parser = document.createElement('a');
$scope.url = window.location;
}
}
</script>
</body>
</html>