我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
我想拿一根绳子
var a = "http://example.com/aa/bb/"
然后把它加工成一个物体
a.hostname == "example.com"
and
a.pathname == "/aa/bb"
当前回答
js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:
var some_uri = new URI("http://www.example.com/foo/bar");
alert(some_uri.authority); // www.example.com
alert(some_uri); // http://www.example.com/foo/bar
var blah = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full); // http://www.example.com/foo/blah
其他回答
试试这个:
函数getUrlPath (str) { //fakepath当url没有路径 var fakepath = "/FakPath"; Var url = str+fakepath; Var reg = /.+?\:\/\/.+?(\/.+?)(?:#|\?|$)/; Var output = reg.exec(url); //检查"output" != null 返回(输出)?输出[1].replace(fakepath,""): fakepath; } Var myurl = "https://stackoverflow.com/questions/736513/"; const path = getUrlPath(myurl); Console.log (path); //output: /questions/736513/
为什么不用呢?
$scope.get_location=function(url_str){
var parser = document.createElement('a');
parser.href =url_str;//"http://example.com:3000/pathname/?search=test#hash";
var info={
protocol:parser.protocol,
hostname:parser.hostname, // => "example.com"
port:parser.port, // => "3000"
pathname:parser.pathname, // => "/pathname/"
search:parser.search, // => "?search=test"
hash:parser.hash, // => "#hash"
host:parser.host, // => "example.com:3000"
}
return info;
}
alert( JSON.stringify( $scope.get_location("http://localhost:257/index.php/deploy/?asd=asd#asd"),null,4 ) );
当然,在>2016年,正确的答案是使用URL API 对于页面URL window.location And for <a href="…""> html lanchorelement API
也支持旧浏览器,使用polyfill:
<script crossorigin="anonymous" src="https://polyfill.io/v3/polyfill.min.js?features=URL"></script>
但作为另一种选择,它可以通过RegEx模式简单而准确地处理:
function URIinfo(s) { s=s.match(/^(([^/]*?:)\/*((?:([^:]+):([^@]+)@)?([^/:]{2,}|\[[\w:]+])(:\d*)?(?=\/|$))?)?((.*?\/)?(([^/]*?)(\.[^/.]+?)?))(\?.*?)?(#.*)?$/); return {origin:s[1],protocol:s[2],host:s[3],username:s[4],password:s[5],hostname:s[6],port:s[7],path:s[8],folders:s[9],file:s[10],filename:s[11],fileext:s[12],search:s[13],hash:s[14]}; } var sample='http://user:password@my.site.com:8080/onefolder/folder.name/file.min.js?query=http://my.site.com:8080/file.exe#hash-root:/file/1.txt'; console.log (URIinfo(sample)); /* { "origin": "http://user:password@my.site.com:8080", "protocol": "http:", "host": "user:password@my.site.com:8080", "username": "user", "password": "password", "hostname": "my.site.com", "port": ":8080", "path": "/onefolder/folder.name/file.min.js", "folders": "/onefolder/folder.name/", "file": "file.min.js", "filename": "file.min", "fileext": ".js", "search": "?query=http://my.site.com:8080/file.exe", "hash": "#hash-root:/file/1.txt" } */
使用正则表达式
任何形式的
绝对/相对路径 IPv4 / IPv6 网络协议/本地文件 查询/散列
返回所有URL选项,但不返回searchParams
(+)也将返回文件信息,如PHP pathInfo
AngularJS的方法在这里:http://jsfiddle.net/PT5BG/4/
<!DOCTYPE html>
<html>
<head>
<title>Parse URL using AngularJS</title>
</head>
<body ng-app ng-controller="AppCtrl" ng-init="init()">
<h3>Parse URL using AngularJS</h3>
url: <input type="text" ng-model="url" value="" style="width:780px;">
<ul>
<li>href = {{parser.href}}</li>
<li>protocol = {{parser.protocol}}</li>
<li>host = {{parser.host}}</li>
<li>hostname = {{parser.hostname}}</li>
<li>port = {{parser.port}}</li>
<li>pathname = {{parser.pathname}}</li>
<li>hash = {{parser.hash}}</li>
<li>search = {{parser.search}}</li>
</ul>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.6/angular.min.js"></script>
<script>
function AppCtrl($scope) {
$scope.$watch('url', function() {
$scope.parser.href = $scope.url;
});
$scope.init = function() {
$scope.parser = document.createElement('a');
$scope.url = window.location;
}
}
</script>
</body>
</html>
以下是我从https://gist.github.com/1847816复制的一个版本,但经过重写,以便于阅读和调试。将锚数据的值复制到另一个名为“result”的变量的目的是因为锚数据相当长,因此将有限数量的值复制到结果将有助于简化结果。
/**
* See: https://gist.github.com/1847816
* Parse a URI, returning an object similar to Location
* Usage: var uri = parseUri("hello?search#hash")
*/
function parseUri(url) {
var result = {};
var anchor = document.createElement('a');
anchor.href = url;
var keys = 'protocol hostname host pathname port search hash href'.split(' ');
for (var keyIndex in keys) {
var currentKey = keys[keyIndex];
result[currentKey] = anchor[currentKey];
}
result.toString = function() { return anchor.href; };
result.requestUri = result.pathname + result.search;
return result;
}