我想拿一根绳子

var a = "http://example.com/aa/bb/"

然后把它加工成一个物体

a.hostname == "example.com"

and

a.pathname == "/aa/bb"

当前回答

为什么不用呢?

        $scope.get_location=function(url_str){
        var parser = document.createElement('a');
        parser.href =url_str;//"http://example.com:3000/pathname/?search=test#hash";
        var info={
            protocol:parser.protocol,   
            hostname:parser.hostname, // => "example.com"
            port:parser.port,     // => "3000"
            pathname:parser.pathname, // => "/pathname/"
            search:parser.search,   // => "?search=test"
            hash:parser.hash,     // => "#hash"
            host:parser.host, // => "example.com:3000"      
        }
        return info;
    }
    alert( JSON.stringify( $scope.get_location("http://localhost:257/index.php/deploy/?asd=asd#asd"),null,4 ) );

其他回答

对于那些正在寻找在IE, Firefox和Chrome中工作的现代解决方案的人:

这些使用超链接元素的解决方案都不会在chrome中起同样的作用。如果你传递一个无效(或空白)的url给chrome,它总是会返回脚本被调用的主机。所以在IE中你会得到空白,而在Chrome中你会得到localhost(或其他什么)。

如果你试图看着推荐人,这是骗人的。你需要确保你返回的主机在原始url中,以处理这个问题:

    function getHostNameFromUrl(url) {
        // <summary>Parses the domain/host from a given url.</summary>
        var a = document.createElement("a");
        a.href = url;

        // Handle chrome which will default to domain where script is called from if invalid
        return url.indexOf(a.hostname) != -1 ? a.hostname : '';
    }

这不会解析查询和散列,但除此之外它工作得很好。

const getURIParts = (url) => { const matches = url.match(/^(\w+?:\/\/)?([\w-\.]+(?=\/?))?:?(\d*)?([^:]*)/) return { scheme: matches ? matches[1] : undefined, host: matches ? matches[2] : '', port: matches ? matches[3] : undefined, pathname: matches ? matches[4] : '' } } console.log(getURIParts("")) console.log(getURIParts("http://localhost/bla")) console.log(getURIParts("https://api.spotify.com/")) console.log(getURIParts("https://api.spotify.com")) console.log(getURIParts("wss://wss.slack.com/link/?ticket=1234-5678")) console.log(getURIParts("localhost")) console.log(getURIParts("localhost/bla")) console.log(getURIParts("localhost/")) console.log(getURIParts("api.spotify.com/bla/two")) console.log(getURIParts("api.spotify.com:8000/bla/two")) console.log(getURIParts("https://api.spotify.com:8800/")) console.log(getURIParts("/mp3-preview/f504e6b8e037771318656394f532dede4f9bcaea"))

当然,在>2016年,正确的答案是使用URL API 对于页面URL window.location And for <a href="…""> html lanchorelement API

也支持旧浏览器,使用polyfill:

<script crossorigin="anonymous" src="https://polyfill.io/v3/polyfill.min.js?features=URL"></script>

但作为另一种选择,它可以通过RegEx模式简单而准确地处理:

function URIinfo(s) { s=s.match(/^(([^/]*?:)\/*((?:([^:]+):([^@]+)@)?([^/:]{2,}|\[[\w:]+])(:\d*)?(?=\/|$))?)?((.*?\/)?(([^/]*?)(\.[^/.]+?)?))(\?.*?)?(#.*)?$/); return {origin:s[1],protocol:s[2],host:s[3],username:s[4],password:s[5],hostname:s[6],port:s[7],path:s[8],folders:s[9],file:s[10],filename:s[11],fileext:s[12],search:s[13],hash:s[14]}; } var sample='http://user:password@my.site.com:8080/onefolder/folder.name/file.min.js?query=http://my.site.com:8080/file.exe#hash-root:/file/1.txt'; console.log (URIinfo(sample)); /* { "origin": "http://user:password@my.site.com:8080", "protocol": "http:", "host": "user:password@my.site.com:8080", "username": "user", "password": "password", "hostname": "my.site.com", "port": ":8080", "path": "/onefolder/folder.name/file.min.js", "folders": "/onefolder/folder.name/", "file": "file.min.js", "filename": "file.min", "fileext": ".js", "search": "?query=http://my.site.com:8080/file.exe", "hash": "#hash-root:/file/1.txt" } */

使用正则表达式

任何形式的

绝对/相对路径 IPv4 / IPv6 网络协议/本地文件 查询/散列

返回所有URL选项,但不返回searchParams

(+)也将返回文件信息,如PHP pathInfo

var loc = window.location;  // => "http://example.com:3000/pathname/?search=test#hash"

返回当前turl。

如果你想传递你自己的字符串作为url(在IE11中不工作):

var loc = new URL("http://example.com:3000/pathname/?search=test#hash")

然后你可以这样解析它:

loc.protocol; // => "http:"
loc.host;     // => "example.com:3000"
loc.hostname; // => "example.com"
loc.port;     // => "3000"
loc.pathname; // => "/pathname/"
loc.hash;     // => "#hash"
loc.search;   // => "?search=test"

js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:

var some_uri = new URI("http://www.example.com/foo/bar");

alert(some_uri.authority); // www.example.com
alert(some_uri);           // http://www.example.com/foo/bar

var blah      = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full);         // http://www.example.com/foo/blah