按数组中的对象分组最有效的方法是什么?
例如,给定此对象数组:
[
{ Phase: "Phase 1", Step: "Step 1", Task: "Task 1", Value: "5" },
{ Phase: "Phase 1", Step: "Step 1", Task: "Task 2", Value: "10" },
{ Phase: "Phase 1", Step: "Step 2", Task: "Task 1", Value: "15" },
{ Phase: "Phase 1", Step: "Step 2", Task: "Task 2", Value: "20" },
{ Phase: "Phase 2", Step: "Step 1", Task: "Task 1", Value: "25" },
{ Phase: "Phase 2", Step: "Step 1", Task: "Task 2", Value: "30" },
{ Phase: "Phase 2", Step: "Step 2", Task: "Task 1", Value: "35" },
{ Phase: "Phase 2", Step: "Step 2", Task: "Task 2", Value: "40" }
]
我正在表格中显示这些信息。我想通过不同的方法进行分组,但我想对值求和。
我将Undercore.js用于其groupby函数,这很有用,但并不能完成全部任务,因为我不希望它们“拆分”,而是“合并”,更像SQL groupby方法。
我要找的是能够合计特定值(如果需要)。
因此,如果我按阶段分组,我希望收到:
[
{ Phase: "Phase 1", Value: 50 },
{ Phase: "Phase 2", Value: 130 }
]
如果我组了阶段/步骤,我会收到:
[
{ Phase: "Phase 1", Step: "Step 1", Value: 15 },
{ Phase: "Phase 1", Step: "Step 2", Value: 35 },
{ Phase: "Phase 2", Step: "Step 1", Value: 55 },
{ Phase: "Phase 2", Step: "Step 2", Value: 75 }
]
是否有一个有用的脚本,或者我应该坚持使用Undercore.js,然后遍历生成的对象,自己计算总数?
从@mortb、@jmarceli的回答和这篇文章中,
我利用JSON.stringify()作为分组依据的PRIMITIVE VALUE多列的标识。
无第三方
function groupBy(list, keyGetter) {
const map = new Map();
list.forEach((item) => {
const key = keyGetter(item);
if (!map.has(key)) {
map.set(key, [item]);
} else {
map.get(key).push(item);
}
});
return map;
}
const pets = [
{type:"Dog", age: 3, name:"Spot"},
{type:"Cat", age: 3, name:"Tiger"},
{type:"Dog", age: 4, name:"Rover"},
{type:"Cat", age: 3, name:"Leo"}
];
const grouped = groupBy(pets,
pet => JSON.stringify({ type: pet.type, age: pet.age }));
console.log(grouped);
使用Lodash第三方
const pets = [
{type:"Dog", age: 3, name:"Spot"},
{type:"Cat", age: 3, name:"Tiger"},
{type:"Dog", age: 4, name:"Rover"},
{type:"Cat", age: 3, name:"Leo"}
];
let rslt = _.groupBy(pets, pet => JSON.stringify(
{ type: pet.type, age: pet.age }));
console.log(rslt);
此解决方案采用任意函数(而不是键),因此比上述解决方案更灵活,并允许箭头函数,这与LINQ中使用的lambda表达式类似:
Array.prototype.groupBy = function (funcProp) {
return this.reduce(function (acc, val) {
(acc[funcProp(val)] = acc[funcProp(val)] || []).push(val);
return acc;
}, {});
};
注意:是否要扩展Array的原型取决于您。
大多数浏览器支持的示例:
[{a:1,b:"b"},{a:1,c:"c"},{a:2,d:"d"}].groupBy(function(c){return c.a;})
使用箭头函数(ES6)的示例:
[{a:1,b:"b"},{a:1,c:"c"},{a:2,d:"d"}].groupBy(c=>c.a)
以上两个示例都返回:
{
"1": [{"a": 1, "b": "b"}, {"a": 1, "c": "c"}],
"2": [{"a": 2, "d": "d"}]
}