按数组中的对象分组最有效的方法是什么?

例如,给定此对象数组:

[ 
    { Phase: "Phase 1", Step: "Step 1", Task: "Task 1", Value: "5" },
    { Phase: "Phase 1", Step: "Step 1", Task: "Task 2", Value: "10" },
    { Phase: "Phase 1", Step: "Step 2", Task: "Task 1", Value: "15" },
    { Phase: "Phase 1", Step: "Step 2", Task: "Task 2", Value: "20" },
    { Phase: "Phase 2", Step: "Step 1", Task: "Task 1", Value: "25" },
    { Phase: "Phase 2", Step: "Step 1", Task: "Task 2", Value: "30" },
    { Phase: "Phase 2", Step: "Step 2", Task: "Task 1", Value: "35" },
    { Phase: "Phase 2", Step: "Step 2", Task: "Task 2", Value: "40" }
]

我正在表格中显示这些信息。我想通过不同的方法进行分组,但我想对值求和。

我将Undercore.js用于其groupby函数,这很有用,但并不能完成全部任务,因为我不希望它们“拆分”,而是“合并”,更像SQL groupby方法。

我要找的是能够合计特定值(如果需要)。

因此,如果我按阶段分组,我希望收到:

[
    { Phase: "Phase 1", Value: 50 },
    { Phase: "Phase 2", Value: 130 }
]

如果我组了阶段/步骤,我会收到:

[
    { Phase: "Phase 1", Step: "Step 1", Value: 15 },
    { Phase: "Phase 1", Step: "Step 2", Value: 35 },
    { Phase: "Phase 2", Step: "Step 1", Value: 55 },
    { Phase: "Phase 2", Step: "Step 2", Value: 75 }
]

是否有一个有用的脚本,或者我应该坚持使用Undercore.js,然后遍历生成的对象,自己计算总数?


当前回答

常量动物=[{type:'狗',品种:“水坑”},{type:'狗',品种:“拉布拉多”},{类型:'cat',品种:“暹罗”},{type:'狗',品种:“法国斗牛犬”},{类型:'cat',品种:'泥'}];var groupBy=(arr,prop)=>{return arr.reduce((objs,obj)=>{const key=obj[prop];if(键){让fi=objs.findIndex(x=>x.key==key);如果(fi>=0){objs[fi].values=[…objs[fi].values,obj];}其他{对象.推送({key:键,值:[obj]})}}返回对象;}, []);}console.log(groupBy(动物,“类型”))

其他回答

这是一个基于TS的功能,不是性能最好的,但很容易阅读和理解!

function groupBy<T>(array: T[], key: string): Record<string, T[]> {
const groupedObject = {}
for (const item of array) {
  const value = item[key]
    if (groupedObject[value] === undefined) {
  groupedObject[value] = []
  }
  groupedObject[value].push(item)
}
  return groupedObject
}

我们以->

const data = [
{ Phase: "Phase 1", Step: "Step 1", Task: "Task 1", Value: "5" },
{ Phase: "Phase 1", Step: "Step 1", Task: "Task 2", Value: "10" },
{ Phase: "Phase 1", Step: "Step 2", Task: "Task 1", Value: "15" },
{ Phase: "Phase 1", Step: "Step 2", Task: "Task 2", Value: "20" },
];
console.log(groupBy(data, 'Step'))
{
'Step 1': [
    {
      Phase: 'Phase 1',
      Step: 'Step 1',
      Task: 'Task 1',
      Value: '5'
    },
    {
      Phase: 'Phase 1',
      Step: 'Step 1',
      Task: 'Task 2',
      Value: '10'
    }
  ],
  'Step 2': [
    {
      Phase: 'Phase 1',
      Step: 'Step 2',
      Task: 'Task 1',
      Value: '15'
    },
    {
      Phase: 'Phase 1',
      Step: 'Step 2',
      Task: 'Task 2',
      Value: '20'
    }
  ]
}

虽然linq的回答很有趣,但它也很重。我的方法有些不同:

var DataGrouper = (function() {
    var has = function(obj, target) {
        return _.any(obj, function(value) {
            return _.isEqual(value, target);
        });
    };

    var keys = function(data, names) {
        return _.reduce(data, function(memo, item) {
            var key = _.pick(item, names);
            if (!has(memo, key)) {
                memo.push(key);
            }
            return memo;
        }, []);
    };

    var group = function(data, names) {
        var stems = keys(data, names);
        return _.map(stems, function(stem) {
            return {
                key: stem,
                vals:_.map(_.where(data, stem), function(item) {
                    return _.omit(item, names);
                })
            };
        });
    };

    group.register = function(name, converter) {
        return group[name] = function(data, names) {
            return _.map(group(data, names), converter);
        };
    };

    return group;
}());

DataGrouper.register("sum", function(item) {
    return _.extend({}, item.key, {Value: _.reduce(item.vals, function(memo, node) {
        return memo + Number(node.Value);
    }, 0)});
});

您可以在JSBin上看到它的作用。

我在Undercore中没有看到任何东西可以做已经做的事情,尽管我可能会错过它。它与_.incontains非常相似,但使用_.isEqual而不是==进行比较。除此之外,其余部分都是针对具体问题的,尽管只是试图通用。

现在DataGrouper.sum(data,[“Phase”])返回

[
    {Phase: "Phase 1", Value: 50},
    {Phase: "Phase 2", Value: 130}
]

DataGrouper.sum(data,[“Phase”,“Step”])返回

[
    {Phase: "Phase 1", Step: "Step 1", Value: 15},
    {Phase: "Phase 1", Step: "Step 2", Value: 35},
    {Phase: "Phase 2", Step: "Step 1", Value: 55},
    {Phase: "Phase 2", Step: "Step 2", Value: 75}
]

但和在这里只是一个势函数。您可以根据需要注册其他人:

DataGrouper.register("max", function(item) {
    return _.extend({}, item.key, {Max: _.reduce(item.vals, function(memo, node) {
        return Math.max(memo, Number(node.Value));
    }, Number.NEGATIVE_INFINITY)});
});

现在DataGrouper.max(data,[“Phase”,“Step”])将返回

[
    {Phase: "Phase 1", Step: "Step 1", Max: 10},
    {Phase: "Phase 1", Step: "Step 2", Max: 20},
    {Phase: "Phase 2", Step: "Step 1", Max: 30},
    {Phase: "Phase 2", Step: "Step 2", Max: 40}
]

或者如果您注册了:

DataGrouper.register("tasks", function(item) {
    return _.extend({}, item.key, {Tasks: _.map(item.vals, function(item) {
      return item.Task + " (" + item.Value + ")";
    }).join(", ")});
});

然后调用DataGrouper.tasks(data,[“Phase”,“Step”])将得到

[
    {Phase: "Phase 1", Step: "Step 1", Tasks: "Task 1 (5), Task 2 (10)"},
    {Phase: "Phase 1", Step: "Step 2", Tasks: "Task 1 (15), Task 2 (20)"},
    {Phase: "Phase 2", Step: "Step 1", Tasks: "Task 1 (25), Task 2 (30)"},
    {Phase: "Phase 2", Step: "Step 2", Tasks: "Task 1 (35), Task 2 (40)"}
]

DataGrouper本身是一个函数。可以用数据和要分组的财产列表来调用它。它返回一个数组,该数组的元素是具有两个财产的对象:key是分组财产的集合,vals是包含不在key中的其余财产的对象数组。例如,DataGrouper(data,[“Phase”,“Step”])将产生:

[
    {
        "key": {Phase: "Phase 1", Step: "Step 1"},
        "vals": [
            {Task: "Task 1", Value: "5"},
            {Task: "Task 2", Value: "10"}
        ]
    },
    {
        "key": {Phase: "Phase 1", Step: "Step 2"},
        "vals": [
            {Task: "Task 1", Value: "15"}, 
            {Task: "Task 2", Value: "20"}
        ]
    },
    {
        "key": {Phase: "Phase 2", Step: "Step 1"},
        "vals": [
            {Task: "Task 1", Value: "25"},
            {Task: "Task 2", Value: "30"}
        ]
    },
    {
        "key": {Phase: "Phase 2", Step: "Step 2"},
        "vals": [
            {Task: "Task 1", Value: "35"}, 
            {Task: "Task 2", Value: "40"}
        ]
    }
]

DataGrouper.register接受一个函数并创建一个新函数,该函数接受初始数据和分组依据的财产。然后,这个新函数采用上述输出格式,并依次对每个输出格式运行函数,返回一个新数组。生成的函数根据您提供的名称存储为DataGrouper的属性,如果您只需要本地引用,也会返回。

这是很多解释。我希望代码相当简单!

基于@Ceasar Bautista的原始想法,我修改了代码并使用typescript创建了一个groupBy函数。

static groupBy(data: any[], comparator: (v1: any, v2: any) => boolean, onDublicate: (uniqueRow: any, dublicateRow: any) => void) {
    return data.reduce(function (reducedRows, currentlyReducedRow) {
      let processedRow = reducedRows.find(searchedRow => comparator(searchedRow, currentlyReducedRow));

      if (processedRow) {
        // currentlyReducedRow is a dublicateRow when processedRow is not null.
        onDublicate(processedRow, currentlyReducedRow)
      } else {
        // currentlyReducedRow is unique and must be pushed in the reducedRows collection.
        reducedRows.push(currentlyReducedRow);
      }

      return reducedRows;
    }, []);
  };

此函数接受一个回调(比较器)和一个第二个回调(onDuplicate),该回调比较行并查找副本。

用法示例:

data = [
    { name: 'a', value: 10 },
    { name: 'a', value: 11 },
    { name: 'a', value: 12 },
    { name: 'b', value: 20 },
    { name: 'b', value: 1 }
  ]

  private static demoComparator = (v1: any, v2: any) => {
    return v1['name'] === v2['name'];
  }

  private static demoOnDublicate = (uniqueRow, dublicateRow) => {
    uniqueRow['value'] += dublicateRow['value'];    
  };

使命感

groupBy(data, demoComparator, demoOnDublicate) 

将执行计算值和的分组。

{name: "a", value: 33}
{name: "b", value: 21}

我们可以根据项目的需要创建任意多个回调函数,并根据需要聚合这些值。在一个例子中,我需要合并两个数组,而不是求和数据。

使用linq.js可能更容易做到这一点,它是linq在JavaScript(DEMO)中的真正实现:

var linq = Enumerable.From(data);
var result =
    linq.GroupBy(function(x){ return x.Phase; })
        .Select(function(x){
          return {
            Phase: x.Key(),
            Value: x.Sum(function(y){ return y.Value|0; })
          };
        }).ToArray();

结果:

[
    { Phase: "Phase 1", Value: 50 },
    { Phase: "Phase 2", Value: 130 }
]

或者,更简单地使用基于字符串的选择器(DEMO):

linq.GroupBy("$.Phase", "",
    "k,e => { Phase:k, Value:e.Sum('$.Value|0') }").ToArray();

现在有点晚了,但也许有人喜欢这个。

ES6:

常量用户=[{name:“Jim”,颜色:“蓝色”},{name:“Sam”,颜色:“蓝色”},{name:“Eddie”,颜色:“绿色”},{姓名:“Robert”,颜色:“绿色”},];常量groupBy=(arr,key)=>{const initialValue={};返回arr.reduce((acc,cval)=>{const myAttribute=cval[key];acc[myAttribute]=[…(acc[myAattribute]| |[]),cval]返回acc;},initialValue);};const res=groupBy(用户,“颜色”);console.log(“分组依据:”,res);