我一直在搜索Select和SelectMany之间的区别,但我还没有找到合适的答案。我需要学习使用LINQ to SQL时的差异,但我所找到的都是标准数组示例。
有人能提供一个LINQ到SQL的例子吗?
我一直在搜索Select和SelectMany之间的区别,但我还没有找到合适的答案。我需要学习使用LINQ to SQL时的差异,但我所找到的都是标准数组示例。
有人能提供一个LINQ到SQL的例子吗?
当前回答
var players = db.SoccerTeams.Where(c => c.Country == "Spain")
.SelectMany(c => c.players);
foreach(var player in players)
{
Console.WriteLine(player.LastName);
}
De Gea 阿尔芭 科斯塔 别墅 Busquets
...
其他回答
SelectMany扁平查询,返回列表的列表。例如
public class PhoneNumber
{
public string Number { get; set; }
}
public class Person
{
public IEnumerable<PhoneNumber> PhoneNumbers { get; set; }
public string Name { get; set; }
}
IEnumerable<Person> people = new List<Person>();
// Select gets a list of lists of phone numbers
IEnumerable<IEnumerable<PhoneNumber>> phoneLists = people.Select(p => p.PhoneNumbers);
// SelectMany flattens it to just a list of phone numbers.
IEnumerable<PhoneNumber> phoneNumbers = people.SelectMany(p => p.PhoneNumbers);
// And to include data from the parent in the result:
// pass an expression to the second parameter (resultSelector) in the overload:
var directory = people
.SelectMany(p => p.PhoneNumbers,
(parent, child) => new { parent.Name, child.Number });
Live Demo。net Fiddle
再举一个如何使用SelectMany + Select来累积子数组对象数据的例子。
假设我们有一些带着手机的用户:
class Phone {
public string BasePart = "555-xxx-xxx";
}
class User {
public string Name = "Xxxxx";
public List<Phone> Phones;
}
现在我们需要选择所有用户的所有手机的basepart:
var usersArray = new List<User>(); // array of arrays
List<string> allBaseParts = usersArray.SelectMany(ua => ua.Phones).Select(p => p.BasePart).ToList();
想想这个例子:
var array = new string[2]
{
"I like what I like",
"I like what you like"
};
//query1 returns two elements sth like this:
//fisrt element would be array[5] :[0] = "I" "like" "what" "I" "like"
//second element would be array[5] :[1] = "I" "like" "what" "you" "like"
IEnumerable<string[]> query1 = array.Select(s => s.Split(' ')).Distinct();
//query2 return back flat result sth like this :
// "I" "like" "what" "you"
IEnumerable<string> query2 = array.SelectMany(s => s.Split(' ')).Distinct();
因此,正如你所看到的,像“I”或“like”这样的重复值已从query2中删除,因为“SelectMany”将在多个序列上平坦和投影。 但是query1返回字符串数组序列。由于query1中有两个不同的数组(第一个和第二个元素),因此不会删除任何东西。
select操作符用于从集合中选择值,SelectMany操作符用于从集合的集合(即嵌套集合)中选择值。
SelectMany()方法用于抚平序列,其中序列的每个元素都是独立的。
我的类用户是这样的
class User
{
public string UserName { get; set; }
public List<string> Roles { get; set; }
}
主要:
var users = new List<User>
{
new User { UserName = "Reza" , Roles = new List<string>{"Superadmin" } },
new User { UserName = "Amin" , Roles = new List<string>{"Guest","Reseption" } },
new User { UserName = "Nima" , Roles = new List<string>{"Nurse","Guest" } },
};
var query = users.SelectMany(user => user.Roles, (user, role) => new { user.UserName, role });
foreach (var obj in query)
{
Console.WriteLine(obj);
}
//output
//{ UserName = Reza, role = Superadmin }
//{ UserName = Amin, role = Guest }
//{ UserName = Amin, role = Reseption }
//{ UserName = Nima, role = Nurse }
//{ UserName = Nima, role = Guest }
您可以对序列的任何项使用操作
int[][] numbers = {
new[] {1, 2, 3},
new[] {4},
new[] {5, 6 , 6 , 2 , 7, 8},
new[] {12, 14}
};
IEnumerable<int> result = numbers
.SelectMany(array => array.Distinct())
.OrderBy(x => x);
//output
//{ 1, 2 , 2 , 3, 4, 5, 6, 7, 8, 12, 14 }
List<List<int>> numbers = new List<List<int>> {
new List<int> {1, 2, 3},
new List<int> {12},
new List<int> {5, 6, 5, 7},
new List<int> {10, 10, 10, 12}
};
IEnumerable<int> result = numbers
.SelectMany(list => list)
.Distinct()
.OrderBy(x=>x);
//output
// { 1, 2, 3, 5, 6, 7, 10, 12 }