我收到一个数字类型= 3,必须检查它是否存在于这个enum:

export const MESSAGE_TYPE = {
    INFO: 1,
    SUCCESS: 2,
    WARNING: 3,
    ERROR: 4,
};

我发现最好的方法是将所有Enum值作为一个数组,并在其上使用indexOf。但结果代码不是很容易读懂:

if( -1 < _.values( MESSAGE_TYPE ).indexOf( _.toInteger( type ) ) ) {
    // do stuff ...
}

有更简单的方法吗?


当前回答

对于任何来这里验证字符串是否是enum值之一并对其进行类型转换的人来说,我写了这个函数,它返回正确的类型,如果字符串不在enum中则返回undefined。

function keepIfInEnum<T>(
  value: string,
  enumObject: { [key: string]: T }
) {
  if (Object.values(enumObject).includes((value as unknown) as T)) {
    return (value as unknown) as T;
  } else {
    return undefined;
  }
}

举个例子:

enum StringEnum {
  value1 = 'FirstValue',
  value2 = 'SecondValue',
}
keepIfInEnum<StringEnum>('FirstValue', StringEnum)  // 'FirstValue'
keepIfInEnum<StringEnum>('OtherValue', StringEnum)  // undefined

其他回答

export enum YourEnum {
   enum1 = 'enum1',
   enum2 = 'enum2',
   enum3 = 'enum3',
}

const status = 'enumnumnum';

if (!Object.values(YourEnum)?.includes(status)) {
     throw new UnprocessableEntityResponse('Invalid enum val');
}
enum ServicePlatform {
    UPLAY = "uplay",
    PSN = "psn",
    XBL = "xbl"
}

就变成:

{ UPLAY: 'uplay', PSN: 'psn', XBL: 'xbl' }

so

ServicePlatform.UPLAY in ServicePlatform // false

解决方案:

ServicePlatform.UPLAY.toUpperCase() in ServicePlatform // true
export enum UserLevel {
  Staff = 0,
  Leader,
  Manager,
}

export enum Gender {
  None = "none",
  Male = "male",
  Female = "female",
}

log中的差异结果:

log(Object.keys(Gender))
=>
[ 'None', 'Male', 'Female' ]

log(Object.keys(UserLevel))
=>
[ '0', '1', '2', 'Staff', 'Leader', 'Manager' ]

解决方案,我们需要删除键作为一个数字。

export class Util {
  static existValueInEnum(type: any, value: any): boolean {
    return Object.keys(type).filter(k => isNaN(Number(k))).filter(k => type[k] === value).length > 0;
  }
}

使用

// For string value
if (!Util.existValueInEnum(Gender, "XYZ")) {
  //todo
}

//For number value, remember cast to Number using Number(val)
if (!Util.existValueInEnum(UserLevel, 0)) {
  //todo
}

对于任何来这里验证字符串是否是enum值之一并对其进行类型转换的人来说,我写了这个函数,它返回正确的类型,如果字符串不在enum中则返回undefined。

function keepIfInEnum<T>(
  value: string,
  enumObject: { [key: string]: T }
) {
  if (Object.values(enumObject).includes((value as unknown) as T)) {
    return (value as unknown) as T;
  } else {
    return undefined;
  }
}

举个例子:

enum StringEnum {
  value1 = 'FirstValue',
  value2 = 'SecondValue',
}
keepIfInEnum<StringEnum>('FirstValue', StringEnum)  // 'FirstValue'
keepIfInEnum<StringEnum>('OtherValue', StringEnum)  // undefined

如果你在那里找不到如何检查联合包含的具体值,有解决方案:

// source enum type
export const EMessagaType = {
   Info,
   Success,
   Warning,
   Error,
};

//check helper
const isUnionHasValue = <T extends number>(union: T, value: T) =>
   (union & value) === value;


//tests
console.log(
 isUnionHasValue(EMessagaType.Info | EMessagaType.Success), 
 EMessagaType.Success);

//output: true


console.log(
 isUnionHasValue(EMessagaType.Info | EMessagaType.Success), 
 EMessagaType.Error); 

//output: false