简单使用_。isEqual方法，它将适用于所有比较…

注意:此方法支持比较数组、数组缓冲区、 布尔值、 *日期对象，错误对象，地图，数字，对象对象，正则表达式， *集合、字符串、符号和类型化数组。对象对象进行比较 *通过自身的，不可继承的，可枚举的属性。函数和DOM *节点不支持。

所以如果你有以下情况:

 const firstName = {name: "Alireza"};
 const otherName = {name: "Alireza"};

如果是:_。isEqual (firstName, otherName);

它会返回true

如果const fullName = {firstName: "Alireza"， familyName: "Dezfoolian"};

如果是:_。isEqual (firstName, fullName);

将返回false

这段代码返回一个具有不同值的所有属性的对象，以及两个对象的值。对记录差异很有用。

var allkeys = _.union(_.keys(obj1), _.keys(obj2));
var difference = _.reduce(allkeys, function (result, key) {
  if ( !_.isEqual(obj1[key], obj2[key]) ) {
    result[key] = {obj1: obj1[key], obj2: obj2[key]}
  }
  return result;
}, {});

我知道这并不能直接回答OP的问题，但我是通过搜索如何删除lodash被引导到这里的。希望这能帮助到和我处境相似的人。

这要归功于@JohanPersson。我在这个答案的基础上实现了对深度嵌套值的比较，并获得对差异的键引用

getObjectDiff = (obj1, obj2) => { const obj1Props = Object.keys(obj1); const obj2Props = Object.keys(obj2); const keysWithDiffValue = obj1Props.reduce((keysWithDiffValueAccumulator, key) => { const propExistsOnObj2 = obj2.hasOwnProperty(key); const hasNestedValue = obj1[key] instanceof Object && obj2[key] instanceof Object; const keyValuePairBetweenBothObjectsIsEqual = obj1[key] === obj2[key]; if (!propExistsOnObj2) { keysWithDiffValueAccumulator.push(key); } else if (hasNestedValue) { const keyIndex = keysWithDiffValueAccumulator.indexOf(key); if (keyIndex >= 0) { keysWithDiffValueAccumulator.splice(keyIndex, 1); } const nestedDiffs = getObjectDiff(obj1[key], obj2[key]); for (let diff of nestedDiffs) { keysWithDiffValueAccumulator.push(`${key}.${diff}`); } } else if (keyValuePairBetweenBothObjectsIsEqual) { const equalValueKeyIndex = keysWithDiffValueAccumulator.indexOf(key); keysWithDiffValueAccumulator.splice(equalValueKeyIndex, 1); } return keysWithDiffValueAccumulator; }, obj2Props); return keysWithDiffValue; } const obj1 = {a0: {a1: {a2: {a3: 'Im here'}}}}; const obj2 = {a0: {a1: {a2: {a3: 'Not here', b3: 'some'}}}}; console.log('final', getObjectDiff(obj1, obj2));

我们需要在两个json更新之间获取delta，以跟踪数据库更新。也许其他人会觉得这很有用。

https://gist.github.com/jp6rt/7fcb6907e159d7851c8d59840b669e3d

const {
  isObject,
  isEqual,
  transform,
  has,
  merge,
} = require('lodash');
const assert = require('assert');

/**
 * Perform a symmetric comparison on JSON object.
 * @param {*} baseObj - The base object to be used for comparison against the withObj.
 * @param {*} withObj - The withObject parameter is used as the comparison on the base object.
 * @param {*} invert  - Because this is a symmetric comparison. Some values in the with object
 *                      that doesn't exist on the base will be lost in translation.
 *                      You can execute again the function again with the parameters interchanged.
 *                      However you will lose the reference if the value is from the base or with
 *                      object if you intended to do an assymetric comparison.
 *                      Setting this to true will do make sure the reference is not lost.
 * @returns           - The returned object will label the result of the comparison with the
 *                      value from base and with object.
 */
const diffSym = (baseObj, withObj, invert = false) => transform(baseObj, (result, value, key) => {
  if (isEqual(value, withObj[key])
    && has(withObj, key)) {
    return;
  }

  if (isObject(value)
    && isObject(withObj[key])
    && !Array.isArray(value)) {
    result[key] = diffSym(value, withObj[key], invert);
    return;
  }

  if (!invert) {
    result[key] = {
      base: value,
      with: withObj[key],
    };
    return;
  }

  if (invert) {
    result[key] = {
      base: withObj[key],
      with: value,
    };
  }
});

/**
 * Perform a assymmetric comparison on JSON object.
 * @param {*} baseObj - The base object to be used for comparison against the withObj.
 * @param {*} withObj - The withObject parameter is used as the comparison on the base object.
 * @returns           - The returned object will label the values with
 *                      reference to the base and with object.
 */
const diffJSON = (baseObj, withObj) => {
  // Deep clone the objects so we don't update the reference objects.
  const baseObjClone = JSON.parse(JSON.stringify(baseObj));
  const withObjClone = JSON.parse(JSON.stringify(withObj));

  const beforeDelta = diffSym(baseObjClone, withObjClone);
  const afterDelta = diffSym(withObjClone, baseObjClone, true);

  return merge(afterDelta, beforeDelta);
};

// By Example:

const beforeDataObj = {
  a: 1,
  c: { d: 2, f: 3 },
  g: 4,
  h: 5,
};
const afterDataObj = {
  a: 2,
  b: 3,
  c: { d: 1, e: 1 },
  h: 5,
};

const delta = diffJSON(beforeDataObj, afterDataObj);

// Assert expected result.
assert(isEqual(delta, {
  a: { base: 1, with: 2 },
  b: { base: undefined, with: 3 },
  c: {
    d: { base: 2, with: 1 },
    e: { base: undefined, with: 1 },
    f: { base: 3, with: undefined },
  },
  g: { base: 4, with: undefined },
}));

以Sridhar Gudimela的回答为基础，下面以一种使用TypeScript的方式进行了更新:

///  U T I L S

interface LooseObjectInterface {
  [key: string]: any;
};

type inputOptions = LooseObjectInterface | any[];



///  E X P O R T

export const objectCompare = (objectA: inputOptions, objectB: inputOptions): LooseObjectInterface => {
  let diffObj: LooseObjectInterface = {};

  switch(true) {
    case (Array.isArray(objectA)):
      objectA.forEach((elem: any, index: number) => {
        if (!Array.isArray(diffObj))
          diffObj = [];

        diffObj[index] = objectCompare(elem, (objectB || [])[index]);
      });

      break;

    case (objectA !== null && typeof objectA === "object"):
      Object.keys(objectA).forEach((key: any) => {
        if (Array.isArray(objectA[key])) {
          let arr = objectCompare(objectA[key], objectB[key]);

          if (!Array.isArray(arr))
            arr = [];

          arr.forEach((elem: any, index: number) => {
            if (!Array.isArray(diffObj[key]))
              diffObj[key] = [];

            diffObj[key][index] = elem;
          });
        } else if (typeof objectA[key] === "object")
          diffObj[key] = objectCompare(objectA[key], objectB[key]);
        else if (objectA[key] !== (objectB || {})[key])
          diffObj[key] = objectA[key];
        else if (objectA[key] === (objectB || {})[key])
          delete objectA[key];
      });

      break;

    default:
      break;
  }

  Object.keys(diffObj).forEach((key: any) => {
    if (typeof diffObj[key] === "object" && JSON.stringify(diffObj[key]) === "{}")
      delete diffObj[key];
  });

  return diffObj;
};

编辑:我最初的回答使用了Flow，因此被否决了(我猜，或者可能是因为我的回答没有使用Lodash……)然而，有一个类似问题的答案也无妨)。

这是基于@JLavoie，使用lodash

let differences = function (newObj, oldObj) {
      return _.reduce(newObj, function (result, value, key) {
        if (!_.isEqual(value, oldObj[key])) {
          if (_.isArray(value)) {
            result[key] = []
            _.forEach(value, function (innerObjFrom1, index) {
              if (_.isNil(oldObj[key][index])) {
                result[key].push(innerObjFrom1)
              } else {
                let changes = differences(innerObjFrom1, oldObj[key][index])
                if (!_.isEmpty(changes)) {
                  result[key].push(changes)
                }
              }
            })
          } else if (_.isObject(value)) {
            result[key] = differences(value, oldObj[key])
          } else {
            result[key] = value
          }
        }
        return result
      }, {})
    }

https://jsfiddle.net/EmilianoBarboza/0g0sn3b9/8/