此解决方案返回一个具有修改过的属性的对象。

_.reduce(a, (r, v, k) => { return _.merge(r, _.isEqual(v, b[k]) ? {} : { [k]: v }); }, {});

我需要知道它们的某个嵌套属性是否不同

其他答案为这个问题提供了可能令人满意的解决方案，但它非常困难和常见，似乎有一个非常受欢迎的包来帮助解决这个问题。

要使用这个包，你需要npm i deep-object-diff，然后:

const { diff } = require('deep-object-diff');
var a = {};
var b = {};

a.prop1 = 2;
a.prop2 = { prop3: 2 };

b.prop1 = 2;
b.prop2 = { prop3: 3 };

if (!_.isEqual(a, b)) {
  const abDiff = diff(a, b);
  console.log(abDiff);
  /*
  {
    prop2: {
      prop3: 3
    }
  }
  */
}

// or alternatively
const abDiff = diff(a, b);
if(!_.isEmpty(abDiff)) {
  // if a diff exists then they aren't deeply equal
  // perform needed actions with diff...
}

下面是一个更详细的案例，直接从他们的文档中删除属性:

const lhs = {
  foo: {
    bar: {
      a: ['a', 'b'],
      b: 2,
      c: ['x', 'y'],
      e: 100 // deleted
    }
  },
  buzz: 'world'
};

const rhs = {
  foo: {
    bar: {
      a: ['a'], // index 1 ('b')  deleted
      b: 2, // unchanged
      c: ['x', 'y', 'z'], // 'z' added
      d: 'Hello, world!' // added
    }
  },
  buzz: 'fizz' // updated
};

console.log(diff(lhs, rhs)); // =>
/*
{
  foo: {
    bar: {
      a: {
        '1': undefined
      },
      c: {
        '2': 'z'
      },
      d: 'Hello, world!',
      e: undefined
    }
  },
  buzz: 'fizz'
}
*/

有关实现细节和其他使用信息，请参阅该repo。

下面是一个使用Lodash的简单解决方案:

_.differenceWith(a, b, _.isEqual);

注意，两个输入都需要是数组(可能是一个对象的数组)。

我们需要在两个json更新之间获取delta，以跟踪数据库更新。也许其他人会觉得这很有用。

https://gist.github.com/jp6rt/7fcb6907e159d7851c8d59840b669e3d

const {
  isObject,
  isEqual,
  transform,
  has,
  merge,
} = require('lodash');
const assert = require('assert');

/**
 * Perform a symmetric comparison on JSON object.
 * @param {*} baseObj - The base object to be used for comparison against the withObj.
 * @param {*} withObj - The withObject parameter is used as the comparison on the base object.
 * @param {*} invert  - Because this is a symmetric comparison. Some values in the with object
 *                      that doesn't exist on the base will be lost in translation.
 *                      You can execute again the function again with the parameters interchanged.
 *                      However you will lose the reference if the value is from the base or with
 *                      object if you intended to do an assymetric comparison.
 *                      Setting this to true will do make sure the reference is not lost.
 * @returns           - The returned object will label the result of the comparison with the
 *                      value from base and with object.
 */
const diffSym = (baseObj, withObj, invert = false) => transform(baseObj, (result, value, key) => {
  if (isEqual(value, withObj[key])
    && has(withObj, key)) {
    return;
  }

  if (isObject(value)
    && isObject(withObj[key])
    && !Array.isArray(value)) {
    result[key] = diffSym(value, withObj[key], invert);
    return;
  }

  if (!invert) {
    result[key] = {
      base: value,
      with: withObj[key],
    };
    return;
  }

  if (invert) {
    result[key] = {
      base: withObj[key],
      with: value,
    };
  }
});

/**
 * Perform a assymmetric comparison on JSON object.
 * @param {*} baseObj - The base object to be used for comparison against the withObj.
 * @param {*} withObj - The withObject parameter is used as the comparison on the base object.
 * @returns           - The returned object will label the values with
 *                      reference to the base and with object.
 */
const diffJSON = (baseObj, withObj) => {
  // Deep clone the objects so we don't update the reference objects.
  const baseObjClone = JSON.parse(JSON.stringify(baseObj));
  const withObjClone = JSON.parse(JSON.stringify(withObj));

  const beforeDelta = diffSym(baseObjClone, withObjClone);
  const afterDelta = diffSym(withObjClone, baseObjClone, true);

  return merge(afterDelta, beforeDelta);
};

// By Example:

const beforeDataObj = {
  a: 1,
  c: { d: 2, f: 3 },
  g: 4,
  h: 5,
};
const afterDataObj = {
  a: 2,
  b: 3,
  c: { d: 1, e: 1 },
  h: 5,
};

const delta = diffJSON(beforeDataObj, afterDataObj);

// Assert expected result.
assert(isEqual(delta, {
  a: { base: 1, with: 2 },
  b: { base: undefined, with: 3 },
  c: {
    d: { base: 2, with: 1 },
    e: { base: undefined, with: 1 },
    f: { base: 3, with: undefined },
  },
  g: { base: 4, with: undefined },
}));

我知道这并不能直接回答OP的问题，但我是通过搜索如何删除lodash被引导到这里的。希望这能帮助到和我处境相似的人。

这要归功于@JohanPersson。我在这个答案的基础上实现了对深度嵌套值的比较，并获得对差异的键引用

getObjectDiff = (obj1, obj2) => { const obj1Props = Object.keys(obj1); const obj2Props = Object.keys(obj2); const keysWithDiffValue = obj1Props.reduce((keysWithDiffValueAccumulator, key) => { const propExistsOnObj2 = obj2.hasOwnProperty(key); const hasNestedValue = obj1[key] instanceof Object && obj2[key] instanceof Object; const keyValuePairBetweenBothObjectsIsEqual = obj1[key] === obj2[key]; if (!propExistsOnObj2) { keysWithDiffValueAccumulator.push(key); } else if (hasNestedValue) { const keyIndex = keysWithDiffValueAccumulator.indexOf(key); if (keyIndex >= 0) { keysWithDiffValueAccumulator.splice(keyIndex, 1); } const nestedDiffs = getObjectDiff(obj1[key], obj2[key]); for (let diff of nestedDiffs) { keysWithDiffValueAccumulator.push(`${key}.${diff}`); } } else if (keyValuePairBetweenBothObjectsIsEqual) { const equalValueKeyIndex = keysWithDiffValueAccumulator.indexOf(key); keysWithDiffValueAccumulator.splice(equalValueKeyIndex, 1); } return keysWithDiffValueAccumulator; }, obj2Props); return keysWithDiffValue; } const obj1 = {a0: {a1: {a2: {a3: 'Im here'}}}}; const obj2 = {a0: {a1: {a2: {a3: 'Not here', b3: 'some'}}}}; console.log('final', getObjectDiff(obj1, obj2));

这是一个简单的带有Lodash深度差异检查器的Typescript，它将生成一个新对象，只包含旧对象和新对象之间的差异。

例如，如果我们有:

const oldData = {a: 1, b: 2};
const newData = {a: 1, b: 3};

结果对象将是:

const result: {b: 3};

它还兼容多层深层对象，对于数组，它可能需要一些调整。

import * as _ from "lodash";

export const objectDeepDiff = (data: object | any, oldData: object | any) => {
  const record: any = {};
  Object.keys(data).forEach((key: string) => {
    // Checks that isn't an object and isn't equal
    if (!(typeof data[key] === "object" && _.isEqual(data[key], oldData[key]))) {
      record[key] = data[key];
    }
    // If is an object, and the object isn't equal
    if ((typeof data[key] === "object" && !_.isEqual(data[key], oldData[key]))) {
      record[key] = objectDeepDiff(data[key], oldData[key]);
    }
  });
  return record;
};