我不明白为什么当我使用setTimeout函数时,我的react组件开始到infinite console.log。一切都在工作,但PC开始滞后的地狱。 有人说这个函数在超时时改变我的状态还有那个重新渲染组件,设置新定时器等等。现在我需要知道如何证明它是正确的。

export default function Loading() {
  // if data fetching is slow, after 1 sec i will show some loading animation
  const [showLoading, setShowLoading] = useState(true)
  let timer1 = setTimeout(() => setShowLoading(true), 1000)

  console.log('this message will render  every second')
  return 1
}

明确在不同版本的代码中没有帮助:

const [showLoading, setShowLoading] = useState(true)
  let timer1 = setTimeout(() => setShowLoading(true), 1000)
  useEffect(
    () => {
      return () => {
        clearTimeout(timer1)
      }
    },
    [showLoading]
  )

当前回答

const[seconds, setSeconds] = useState(300);

function TimeOut() {
useEffect(() => {
    let interval = setInterval(() => {
        setSeconds(seconds => seconds -1);
    }, 1000);

    return() => clearInterval(interval);
}, [])

function reset() {
  setSeconds(300); 
} 

return (
    <div>
        Count Down: {seconds} left
        <button className="button" onClick={reset}>
           Reset
        </button>
    </div>
)
}

确保导入useState和useEffect。另外,添加在0处停止计时器的逻辑。

其他回答

如果在其他人给出的例子中使用useEffect钩子来避免连续地将setInterval方法附加(挂载)和分离(卸载)到事件循环,您可能会转而使用useReducer。

想象这样一个场景:给定的秒和分,你要开始倒数…… 下面我们得到了一个减速器函数,它执行倒计时逻辑。

const reducer = (state, action) => {
  switch (action.type) {
    case "cycle":
      if (state.seconds > 0) {
        return { ...state, seconds: state.seconds - 1 };
      }
      if (state.minutes > 0) {
        return { ...state, minutes: state.minutes - 1, seconds: 60 };
      }
    case "newState":
      return action.payload;
    default:
      throw new Error();
  }
}

现在我们要做的就是在每个间隔中分派循环动作:

  const [time, dispatch] = useReducer(reducer, { minutes: 0, seconds: 0 });
  const { minutes, seconds } = time;

  const interval = useRef(null);
  
  //Notice the [] provided, we are setting the interval only once (during mount) here.
  useEffect(() => {
    interval.current = setInterval(() => {
      dispatch({ type: "cycle" });
    }, 1000);
    // Just in case, clear interval on component un-mount, to be safe.
    return () => clearInterval(interval.current);
  }, []);

  //Now as soon as the time in given two states is zero, remove the interval.
  useEffect(() => {
    if (!minutes && !seconds) {
      clearInterval(interval.current);
    }
  }, [minutes, seconds]);
  // We could have avoided the above state check too, providing the `clearInterval()`
  // inside our reducer function, but that would delay it until the next interval.

您的计算机延迟是因为您可能忘记将空数组作为useEffect的第二个参数传递,并在回调中触发了setState。这将导致一个无限循环,因为useEffect在呈现时被触发。

下面是一个在挂载时设置定时器并在卸载时清空定时器的工作方法:

function App() { React.useEffect(() => { const timer = window.setInterval(() => { console.log('1 second has passed'); }, 1000); return () => { // Return callback to run on unmount. window.clearInterval(timer); }; }, []); // Pass in empty array to run useEffect only on mount. return ( <div> Timer Example </div> ); } ReactDOM.render( <div> <App /> </div>, document.querySelector("#app") ); <script src="https://unpkg.com/react@16.7.0-alpha.0/umd/react.development.js"></script> <script src="https://unpkg.com/react-dom@16.7.0-alpha.0/umd/react-dom.development.js"></script> <div id="app"></div>

export const useTimeout = () => {
    const timeout = useRef();
    useEffect(
        () => () => {
            if (timeout.current) {
                clearTimeout(timeout.current);
                timeout.current = null;
            }
        },
        [],
    );
    return timeout;
};

您可以使用简单的钩子来共享超时逻辑。

const timeout = useTimeout();
timeout.current = setTimeout(your conditions) 

我写了一个react钩子,再也不用处理超时。 就像React.useState():

新回答

const [showLoading, setShowLoading] = useTimeoutState(false)

// sets loading to true for 1000ms, then back to false
setShowLoading(true, { timeout: 1000})
export const useTimeoutState = <T>(
  defaultState: T
): [T, (action: SetStateAction<T>, opts?: { timeout: number }) => void] => {
  const [state, _setState] = useState<T>(defaultState);
  const [currentTimeoutId, setCurrentTimeoutId] = useState<
    NodeJS.Timeout | undefined
  >();

  const setState = useCallback(
    (action: SetStateAction<T>, opts?: { timeout: number }) => {
      if (currentTimeoutId != null) {
        clearTimeout(currentTimeoutId);
      }

      _setState(action);

      const id = setTimeout(() => _setState(defaultState), opts?.timeout);
      setCurrentTimeoutId(id);
    },
    [currentTimeoutId, defaultState]
  );
  return [state, setState];
};

旧的答案

const [showLoading, setShowLoading] = useTimeoutState(false, {timeout: 5000})

// will set show loading after 5000ms
setShowLoading(true)
// overriding and timeouts after 1000ms
setShowLoading(true, { timeout: 1000})

设置多个状态将刷新超时,并且它将在上次setState设置的相同ms后超时。

香草js(未测试,typescript版本是):

import React from "react"

// sets itself automatically to default state after timeout MS. good for setting timeouted states for risky requests etc.
export const useTimeoutState = (defaultState, opts) => {
  const [state, _setState] = React.useState(defaultState)
  const [currentTimeoutId, setCurrentTimeoutId] = React.useState()

  const setState = React.useCallback(
    (newState: React.SetStateAction, setStateOpts) => {
      clearTimeout(currentTimeoutId) // removes old timeouts
      newState !== state && _setState(newState)
      if (newState === defaultState) return // if already default state, no need to set timeout to set state to default
      const id = setTimeout(
        () => _setState(defaultState),
        setStateOpts?.timeout || opts?.timeout
      ) 
      setCurrentTimeoutId(id)
    },
    [currentTimeoutId, state, opts, defaultState]
  )
  return [state, setState]
}

打字稿:

import React from "react"
interface IUseTimeoutStateOptions {
  timeout?: number
}
// sets itself automatically to default state after timeout MS. good for setting timeouted states for risky requests etc.
export const useTimeoutState = <T>(defaultState: T, opts?: IUseTimeoutStateOptions) => {
  const [state, _setState] = React.useState<T>(defaultState)
  const [currentTimeoutId, setCurrentTimeoutId] = React.useState<number | undefined>()
  // todo: change any to React.setStateAction with T
  const setState = React.useCallback(
    (newState: React.SetStateAction<any>, setStateOpts?: { timeout?: number }) => {
      clearTimeout(currentTimeoutId) // removes old timeouts
      newState !== state && _setState(newState)
      if (newState === defaultState) return // if already default state, no need to set timeout to set state to default
      const id = setTimeout(
        () => _setState(defaultState),
        setStateOpts?.timeout || opts?.timeout
      ) as number
      setCurrentTimeoutId(id)
    },
    [currentTimeoutId, state, opts, defaultState]
  )
  return [state, setState] as [
    T,
    (newState: React.SetStateAction<T>, setStateOpts?: { timeout?: number }) => void
  ]
}```

如果你想创建一个类似“start”的按钮,那么使用“useInterval”钩子可能不合适,因为react不允许你调用组件顶部以外的钩子。

export default function Loading() {
  // if data fetching is slow, after 1 sec i will show some loading animation
  const [showLoading, setShowLoading] = useState(true)
  const interval = useRef();

  useEffect(() => {
      interval.current = () => setShowLoading(true);
  }, [showLoading]);

  // make a function like "Start"
  // const start = setInterval(interval.current(), 1000)

  setInterval(() => interval.current(), 1000);

  console.log('this message will render  every second')
  return 1
}