我不明白为什么当我使用setTimeout函数时,我的react组件开始到infinite console.log。一切都在工作,但PC开始滞后的地狱。 有人说这个函数在超时时改变我的状态还有那个重新渲染组件,设置新定时器等等。现在我需要知道如何证明它是正确的。

export default function Loading() {
  // if data fetching is slow, after 1 sec i will show some loading animation
  const [showLoading, setShowLoading] = useState(true)
  let timer1 = setTimeout(() => setShowLoading(true), 1000)

  console.log('this message will render  every second')
  return 1
}

明确在不同版本的代码中没有帮助:

const [showLoading, setShowLoading] = useState(true)
  let timer1 = setTimeout(() => setShowLoading(true), 1000)
  useEffect(
    () => {
      return () => {
        clearTimeout(timer1)
      }
    },
    [showLoading]
  )

当前回答

在useEffect内部定义return () => {/*code/*}函数,每次useEffect运行时(除了第一次呈现组件挂载时)和卸载组件时(如果你不再显示组件)都会运行。

这是一种使用和清除超时或间隔的工作方式:

沙箱的例子。

import { useState, useEffect } from "react";

const delay = 5;

export default function App() {
  const [show, setShow] = useState(false);

  useEffect(
    () => {
      let timer1 = setTimeout(() => setShow(true), delay * 1000);

      // this will clear Timeout
      // when component unmount like in willComponentUnmount
      // and show will not change to true
      return () => {
        clearTimeout(timer1);
      };
    },
    // useEffect will run only one time with empty []
    // if you pass a value to array,
    // like this - [data]
    // than clearTimeout will run every time
    // this value changes (useEffect re-run)
    []
  );

  return show ? (
    <div>show is true, {delay}seconds passed</div>
  ) : (
    <div>show is false, wait {delay}seconds</div>
  );
}

如果您需要清除其他组件中的超时或间隔:

沙箱的例子。

import { useState, useEffect, useRef } from "react";

const delay = 1;

export default function App() {
  const [counter, setCounter] = useState(0);
  const timer = useRef(null); // we can save timer in useRef and pass it to child

  useEffect(() => {
    // useRef value stored in .current property
    timer.current = setInterval(() => setCounter((v) => v + 1), delay * 1000);

    // clear on component unmount
    return () => {
      clearInterval(timer.current);
    };
  }, []);

  return (
    <div>
      <div>Interval is working, counter is: {counter}</div>
      <Child counter={counter} currentTimer={timer.current} />
    </div>
  );
}

function Child({ counter, currentTimer }) {
  // this will clearInterval in parent component after counter gets to 5
  useEffect(() => {
    if (counter < 5) return;

    clearInterval(currentTimer);
  }, [counter, currentTimer]);

  return null;
}

来自和Abramov的文章。

其他回答

如果你的超时是在If结构中,试试这个:

useEffect(() => {
    let timeout;

    if (yourCondition) {
      timeout = setTimeout(() => {
        // your code
      }, 1000);
    } else {
      // your code
    }

    return () => {
      clearTimeout(timeout);
    };
  }, [yourDeps]);

在useEffect内部定义return () => {/*code/*}函数,每次useEffect运行时(除了第一次呈现组件挂载时)和卸载组件时(如果你不再显示组件)都会运行。

这是一种使用和清除超时或间隔的工作方式:

沙箱的例子。

import { useState, useEffect } from "react";

const delay = 5;

export default function App() {
  const [show, setShow] = useState(false);

  useEffect(
    () => {
      let timer1 = setTimeout(() => setShow(true), delay * 1000);

      // this will clear Timeout
      // when component unmount like in willComponentUnmount
      // and show will not change to true
      return () => {
        clearTimeout(timer1);
      };
    },
    // useEffect will run only one time with empty []
    // if you pass a value to array,
    // like this - [data]
    // than clearTimeout will run every time
    // this value changes (useEffect re-run)
    []
  );

  return show ? (
    <div>show is true, {delay}seconds passed</div>
  ) : (
    <div>show is false, wait {delay}seconds</div>
  );
}

如果您需要清除其他组件中的超时或间隔:

沙箱的例子。

import { useState, useEffect, useRef } from "react";

const delay = 1;

export default function App() {
  const [counter, setCounter] = useState(0);
  const timer = useRef(null); // we can save timer in useRef and pass it to child

  useEffect(() => {
    // useRef value stored in .current property
    timer.current = setInterval(() => setCounter((v) => v + 1), delay * 1000);

    // clear on component unmount
    return () => {
      clearInterval(timer.current);
    };
  }, []);

  return (
    <div>
      <div>Interval is working, counter is: {counter}</div>
      <Child counter={counter} currentTimer={timer.current} />
    </div>
  );
}

function Child({ counter, currentTimer }) {
  // this will clearInterval in parent component after counter gets to 5
  useEffect(() => {
    if (counter < 5) return;

    clearInterval(currentTimer);
  }, [counter, currentTimer]);

  return null;
}

来自和Abramov的文章。

const[seconds, setSeconds] = useState(300);

function TimeOut() {
useEffect(() => {
    let interval = setInterval(() => {
        setSeconds(seconds => seconds -1);
    }, 1000);

    return() => clearInterval(interval);
}, [])

function reset() {
  setSeconds(300); 
} 

return (
    <div>
        Count Down: {seconds} left
        <button className="button" onClick={reset}>
           Reset
        </button>
    </div>
)
}

确保导入useState和useEffect。另外,添加在0处停止计时器的逻辑。

export const useTimeout = () => {
    const timeout = useRef();
    useEffect(
        () => () => {
            if (timeout.current) {
                clearTimeout(timeout.current);
                timeout.current = null;
            }
        },
        [],
    );
    return timeout;
};

您可以使用简单的钩子来共享超时逻辑。

const timeout = useTimeout();
timeout.current = setTimeout(your conditions) 

如果你想创建一个类似“start”的按钮,那么使用“useInterval”钩子可能不合适,因为react不允许你调用组件顶部以外的钩子。

export default function Loading() {
  // if data fetching is slow, after 1 sec i will show some loading animation
  const [showLoading, setShowLoading] = useState(true)
  const interval = useRef();

  useEffect(() => {
      interval.current = () => setShowLoading(true);
  }, [showLoading]);

  // make a function like "Start"
  // const start = setInterval(interval.current(), 1000)

  setInterval(() => interval.current(), 1000);

  console.log('this message will render  every second')
  return 1
}