更新: 现在你应该使用Swift 2引入的新的可用性检查: 例:要检查iOS 9.0或更高版本的使用，可以这样做:

if #available(iOS 9.0, *) {
  // use UIStackView
} else {
  // show sad face emoji
}

或者可以与整个方法或类一起使用

@available(iOS 9.0, *)
func useStackView() {
    // use UIStackView
}    

或者带着守卫

guard #available(iOS 14, *) else {
    return
}

更多信息请看这个。

更新: 根据Allison的评论，我已经更新了答案，检查仍然是运行时，但编译器可以提前知道&可以显示更好的错误或建议，而你正在处理它。

其他检查方法:

如果你不知道确切的版本，但想检查iOS 9,10或11使用if:

let floatVersion = (UIDevice.current.systemVersion as NSString).floatValue

编辑: 只是找到了另一种实现这一目标的方法:

let iOS8 = floor(NSFoundationVersionNumber) > floor(NSFoundationVersionNumber_iOS_7_1)
let iOS7 = floor(NSFoundationVersionNumber) <= floor(NSFoundationVersionNumber_iOS_7_1)

let osVersion = NSProcessInfo.processInfo().operatingSystemVersion
let versionString = osVersion.majorVersion.description + "." + osVersion.minorVersion.description + "." + osVersion.patchVersion.description
print(versionString)

Swift 3.0+更新

func SYSTEM_VERSION_EQUAL_TO(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: .numeric) == ComparisonResult.orderedSame
}

func SYSTEM_VERSION_GREATER_THAN(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: .numeric) == ComparisonResult.orderedDescending
}

func SYSTEM_VERSION_GREATER_THAN_OR_EQUAL_TO(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: .numeric) != ComparisonResult.orderedAscending
}

func SYSTEM_VERSION_LESS_THAN(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: .numeric) == ComparisonResult.orderedAscending
}

func SYSTEM_VERSION_LESS_THAN_OR_EQUAL_TO(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: .numeric) != ComparisonResult.orderedDescending
}

斯威夫特5

我们不需要创建扩展，因为ProcessInfo给了我们版本信息。你可以在下面看到iOS的示例代码。

let os = ProcessInfo().operatingSystemVersion

switch (os.majorVersion, os.minorVersion, os.patchVersion) {
case (let x, _, _) where x < 8:
    print("iOS < 8.0.0")

case (8, 0, _):
    print("iOS >= 8.0.0, < 8.1.0")

case (8, _, _):
    print("iOS >= 8.1.0, < 9.0")

case (9, _, _):
    print("iOS >= 9.0.0")

default:
    print("iOS >= 10.0.0")
}

参考:http://nshipster.com/swift-system-version-checking/

如果你想查看WatchOS。

斯威夫特

let watchOSVersion = WKInterfaceDevice.currentDevice().systemVersion
print("WatchOS version: \(watchOSVersion)")

objective - c

NSString *watchOSVersion = [[WKInterfaceDevice currentDevice] systemVersion];
NSLog(@"WatchOS version: %@", watchOSVersion);

快4.倍

func iOS_VERSION_EQUAL_TO(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: NSString.CompareOptions.numeric) == ComparisonResult.orderedSame
}

func iOS_VERSION_GREATER_THAN(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: NSString.CompareOptions.numeric) == ComparisonResult.orderedDescending
}

func iOS_VERSION_GREATER_THAN_OR_EQUAL_TO(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: NSString.CompareOptions.numeric) != ComparisonResult.orderedAscending
}

func iOS_VERSION_LESS_THAN(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: NSString.CompareOptions.numeric) == ComparisonResult.orderedAscending
}

func iOS_VERSION_LESS_THAN_OR_EQUAL_TO(version: String) -> Bool {
    return UIDevice.current.systemVersion.compare(version, options: NSString.CompareOptions.numeric) != ComparisonResult.orderedDescending
}

用法:

if iOS_VERSION_GREATER_THAN_OR_EQUAL_TO(version: "11.0") {
    //Do something!
}

附:KVISH回答翻译成Swift 4。x和重命名函数，因为我专门为iOS应用程序使用这个片段。