你已经回答了你自己的问题!：）

function getRealIpAddr() {
    if(!empty($_SERVER['HTTP_CLIENT_IP']))   //Check IP address from shared Internet
    {
        $IPaddress = $_SERVER['HTTP_CLIENT_IP'];
    }
    elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR']))   //To check IP address is passed from the proxy
    {
        $IPaddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
    }
    else
    {
        $IPaddress = $_SERVER['REMOTE_ADDR'];
    }
    return $IPaddress;
}

源

如果你使用CloudFlare缓存层服务，下面是修改后的版本

function getIP()
{
    $fields = array('HTTP_X_FORWARDED_FOR',
                    'REMOTE_ADDR',
                    'HTTP_CF_CONNECTING_IP',
                    'HTTP_X_CLUSTER_CLIENT_IP');

    foreach($fields as $f)
    {
        $tries = $_SERVER[$f];
        if (empty($tries))
            continue;
        $tries = explode(',',$tries);
        foreach($tries as $try)
        {
            $r = filter_var($try,
                            FILTER_VALIDATE_IP, FILTER_FLAG_IPV4 |
                            FILTER_FLAG_NO_PRIV_RANGE |
                            FILTER_FLAG_NO_RES_RANGE);

            if ($r !== false)
            {
                return $try;
            }
        }
    }
    return false;
}

我想知道也许你应该在爆炸的HTTP_X_FORWARDED_FOR以相反的顺序迭代，因为我的经验是，用户的IP地址结束在逗号分隔的列表的末尾，所以从头的开始，你更有可能得到一个返回的代理的IP地址，这可能仍然允许会话劫持，因为许多用户可能通过该代理。

你已经回答了你自己的问题!：）

function getRealIpAddr() {
    if(!empty($_SERVER['HTTP_CLIENT_IP']))   //Check IP address from shared Internet
    {
        $IPaddress = $_SERVER['HTTP_CLIENT_IP'];
    }
    elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR']))   //To check IP address is passed from the proxy
    {
        $IPaddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
    }
    else
    {
        $IPaddress = $_SERVER['REMOTE_ADDR'];
    }
    return $IPaddress;
}

源

最大的问题是目的是什么?

你的代码几乎是全面的，因为它可以-但我看到，如果你发现什么看起来像一个代理添加头，你使用它而不是CLIENT_IP，然而，如果你想要这个信息的审计目的，然后警告-它很容易伪造。

当然，您绝不应该使用IP地址进行任何形式的身份验证——即使这些地址也可能被欺骗。

您可以通过推出一个flash或java applet来更好地测量客户端ip地址，它通过非http端口连接回服务器(因此会显示透明代理或代理注入的报头为假的情况下)，但请记住，当客户端只能通过web代理连接或传出端口被阻塞时，将不会有来自applet的连接。

我想出了这个函数，它不简单地返回IP地址，而是一个具有IP信息的数组。

// Example usage:
$info = ip_info();
if ( $info->proxy ) {
    echo 'Your IP is ' . $info->ip;
} else {
    echo 'Your IP is ' . $info->ip . ' and your proxy is ' . $info->proxy_ip;
}

函数如下:

/**
 * Retrieves the best guess of the client's actual IP address.
 * Takes into account numerous HTTP proxy headers due to variations
 * in how different ISPs handle IP addresses in headers between hops.
 *
 * @since 1.1.3
 *
 * @return object {
 *         IP Address details
 *
 *         string $ip The users IP address (might be spoofed, if $proxy is true)
 *         bool $proxy True, if a proxy was detected
 *         string $proxy_id The proxy-server IP address
 * }
 */
function ip_info() {
    $result = (object) array(
        'ip' => $_SERVER['REMOTE_ADDR'],
        'proxy' => false,
        'proxy_ip' => '',
    );

    /*
     * This code tries to bypass a proxy and get the actual IP address of
     * the visitor behind the proxy.
     * Warning: These values might be spoofed!
     */
    $ip_fields = array(
        'HTTP_CLIENT_IP',
        'HTTP_X_FORWARDED_FOR',
        'HTTP_X_FORWARDED',
        'HTTP_X_CLUSTER_CLIENT_IP',
        'HTTP_FORWARDED_FOR',
        'HTTP_FORWARDED',
        'REMOTE_ADDR',
    );
    foreach ( $ip_fields as $key ) {
        if ( array_key_exists( $key, $_SERVER ) === true ) {
            foreach ( explode( ',', $_SERVER[$key] ) as $ip ) {
                $ip = trim( $ip );

                if ( filter_var( $ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE ) !== false ) {
                    $forwarded = $ip;
                    break 2;
                }
            }
        }
    }

    // If we found a different IP address then REMOTE_ADDR then it's a proxy!
    if ( $forwarded != $result->ip ) {
        $result->proxy = true;
        $result->proxy_ip = $result->ip;
        $result->ip = $forwarded;
    }

    return $result;
}