我们使用:

/**
 * Get the customer's IP address.
 *
 * @return string
 */
public function getIpAddress() {
    if (!empty($_SERVER['HTTP_CLIENT_IP'])) {
        return $_SERVER['HTTP_CLIENT_IP'];
    } else if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
        $ips = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
        return trim($ips[count($ips) - 1]);
    } else {
        return $_SERVER['REMOTE_ADDR'];
    }
}

在HTTP_X_FORWARDED_FOR上的爆炸是因为我们在使用Squid时检测IP地址的奇怪问题。

我想知道也许你应该在爆炸的HTTP_X_FORWARDED_FOR以相反的顺序迭代，因为我的经验是，用户的IP地址结束在逗号分隔的列表的末尾，所以从头的开始，你更有可能得到一个返回的代理的IP地址，这可能仍然允许会话劫持，因为许多用户可能通过该代理。

我知道现在回答已经太晚了。但是你可以试试这些方法:

选项1:(使用curl)

$ch = curl_init();

// set URL and other appropriate options
curl_setopt($ch, CURLOPT_URL, "https://ifconfig.me/");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

// grab URL and pass it to the browser
$ip = curl_exec($ch);

// close cURL resource, and free up system resources
curl_close($ch);

return $ip;

选项2:(适用于mac)

return trim(shell_exec("dig +short myip.opendns.com @resolver1.opendns.com"));

选项3:(只是使用了一个技巧)

return str_replace('Current IP CheckCurrent IP Address: ', '', strip_tags(file_get_contents('http://checkip.dyndns.com')));

可以作为参考: https://www.tecmint.com/find-linux-server-public-ip-address/

我想出了这个函数，它不简单地返回IP地址，而是一个具有IP信息的数组。

// Example usage:
$info = ip_info();
if ( $info->proxy ) {
    echo 'Your IP is ' . $info->ip;
} else {
    echo 'Your IP is ' . $info->ip . ' and your proxy is ' . $info->proxy_ip;
}

函数如下:

/**
 * Retrieves the best guess of the client's actual IP address.
 * Takes into account numerous HTTP proxy headers due to variations
 * in how different ISPs handle IP addresses in headers between hops.
 *
 * @since 1.1.3
 *
 * @return object {
 *         IP Address details
 *
 *         string $ip The users IP address (might be spoofed, if $proxy is true)
 *         bool $proxy True, if a proxy was detected
 *         string $proxy_id The proxy-server IP address
 * }
 */
function ip_info() {
    $result = (object) array(
        'ip' => $_SERVER['REMOTE_ADDR'],
        'proxy' => false,
        'proxy_ip' => '',
    );

    /*
     * This code tries to bypass a proxy and get the actual IP address of
     * the visitor behind the proxy.
     * Warning: These values might be spoofed!
     */
    $ip_fields = array(
        'HTTP_CLIENT_IP',
        'HTTP_X_FORWARDED_FOR',
        'HTTP_X_FORWARDED',
        'HTTP_X_CLUSTER_CLIENT_IP',
        'HTTP_FORWARDED_FOR',
        'HTTP_FORWARDED',
        'REMOTE_ADDR',
    );
    foreach ( $ip_fields as $key ) {
        if ( array_key_exists( $key, $_SERVER ) === true ) {
            foreach ( explode( ',', $_SERVER[$key] ) as $ip ) {
                $ip = trim( $ip );

                if ( filter_var( $ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE ) !== false ) {
                    $forwarded = $ip;
                    break 2;
                }
            }
        }
    }

    // If we found a different IP address then REMOTE_ADDR then it's a proxy!
    if ( $forwarded != $result->ip ) {
        $result->proxy = true;
        $result->proxy_ip = $result->ip;
        $result->ip = $forwarded;
    }

    return $result;
}

我们使用:

/**
 * Get the customer's IP address.
 *
 * @return string
 */
public function getIpAddress() {
    if (!empty($_SERVER['HTTP_CLIENT_IP'])) {
        return $_SERVER['HTTP_CLIENT_IP'];
    } else if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
        $ips = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
        return trim($ips[count($ips) - 1]);
    } else {
        return $_SERVER['REMOTE_ADDR'];
    }
}

在HTTP_X_FORWARDED_FOR上的爆炸是因为我们在使用Squid时检测IP地址的奇怪问题。

i realize there are much better and more concise answers above, and this isnt a function nor the most graceful script around. In our case we needed to output both the spoofable x_forwarded_for and the more reliable remote_addr in a simplistic switch per-say. It needed to allow blanks for injecting into other functions if-none or if-singular (rather than just returning the preformatted function). It needed an "on or off" var with a per-switch customized label(s) for platform settings. It also needed a way for $ip to be dynamic depending on request so that it would take form of forwarded_for.

我也没有看到任何人地址isset() vs !empty()——它可能没有为x_forwarded_for输入任何内容，但仍然触发isset()真理导致空白var，一种解决方法是使用&&并结合两者作为条件。请记住，您可以欺骗像“PWNED”这样的单词为x_forwarded_for，因此，如果您的输出在某个受保护的地方或到DB中，请确保您将其杀菌为真实ip语法。

此外，如果您需要一个多代理来查看x_forwarder_for中的数组，则可以使用谷歌translate进行测试。如果你想欺骗头部测试，检查这个Chrome客户端头部欺骗扩展。这将默认只是标准的remote_addr，而后面的一个代理。

我不知道任何情况下，remote_addr可以是空的，但它在那里，以防万一。

// proxybuster - attempts to un-hide originating IP if [reverse]proxy provides methods to do so
  $enableProxyBust = true;

if (($enableProxyBust == true) && (isset($_SERVER['REMOTE_ADDR'])) && (isset($_SERVER['HTTP_X_FORWARDED_FOR'])) && (!empty($_SERVER['HTTP_X_FORWARDED_FOR']))) {
    $ip = end(array_values(array_filter(explode(',',$_SERVER['HTTP_X_FORWARDED_FOR']))));
    $ipProxy = $_SERVER['REMOTE_ADDR'];
    $ipProxy_label = ' behind proxy ';
} elseif (($enableProxyBust == true) && (isset($_SERVER['REMOTE_ADDR']))) {
    $ip = $_SERVER['REMOTE_ADDR'];
    $ipProxy = '';
    $ipProxy_label = ' no proxy ';
} elseif (($enableProxyBust == false) && (isset($_SERVER['REMOTE_ADDR']))) {
    $ip = $_SERVER['REMOTE_ADDR'];
    $ipProxy = '';
    $ipProxy_label = '';
} else {
    $ip = '';
    $ipProxy = '';
    $ipProxy_label = '';
}

为了使这些动态用于下面的函数或查询/回显/视图，比如日志生成或错误报告，使用全局变量或在任何你想要的地方回显em，而不需要创建大量其他条件或静态模式输出函数。

function fooNow() {
    global $ip, $ipProxy, $ipProxy_label;
    // begin this actions such as log, error, query, or report
}

谢谢你的好想法。请让我知道如果这可以更好，仍然有点新的这些头:)