我必须递归地重命名一个完整的文件夹树,这样就不会出现大写字母(这是c++源代码,但这无关紧要)。

忽略CVS和Subversion版本控制文件/文件夹的加分项。首选的方法是shell脚本,因为shell应该在任何Linux机器上可用。

关于文件重命名的细节有一些有效的争论。

I think files with the same lowercase names should be overwritten; it's the user's problem. When checked out on a case-ignoring file system, it would overwrite the first one with the latter, too. I would consider A-Z characters and transform them to a-z, everything else is just calling for problems (at least with source code). The script would be needed to run a build on a Linux system, so I think changes to CVS or Subversion version control files should be omitted. After all, it's just a scratch checkout. Maybe an "export" is more appropriate.


当前回答

for f in `find`; do mv -v "$f" "`echo $f | tr '[A-Z]' '[a-z]'`"; done

其他回答

如果你不需要关心效率,就试试下面的方法。

zip -r foo.zip foo/*
unzip -LL foo.zip

使用排版:

typeset -l new        # Always lowercase
find $topPoint |      # Not using xargs to make this more readable
  while read old
  do new="$old"       # $new is a lowercase version of $old
     mv "$old" "$new" # Quotes for those annoying embedded spaces
  done

在Windows上,像Git Bash这样的模拟可能会失败,因为Windows在本质上不区分大小写。对于这些,添加一个步骤,mv的文件首先到另一个名称,如“$old.tmp”,然后到$new。

如果你已经设置了重命名命令(例如,在Mac中通过brew install),这是有效的:

rename --lower-case --force somedir/*

在OS X中,mv -f显示“same file”错误,所以我重命名两次:

for i in `find . -name "*" -type f |grep -e "[A-Z]"`; do j=`echo $i | tr '[A-Z]' '[a-z]' | sed s/\-1$//`; mv $i $i-1; mv $i-1 $j; done

我需要在Windows 7上的Cygwin设置上这样做,并发现我在上面尝试的建议中出现了语法错误(尽管我可能错过了一个工作选项)。然而,这个解决方案直接来自Ubuntu论坛:-)

ls | while read upName; do loName=`echo "${upName}" | tr '[:upper:]' '[:lower:]'`; mv "$upName" "$loName"; done

(注意:我之前用下划线替换了空格:

for f in *\ *; do mv "$f" "${f// /_}"; done

)