我必须递归地重命名一个完整的文件夹树，这样就不会出现大写字母(这是c++源代码，但这无关紧要)。
忽略CVS和Subversion版本控制文件/文件夹的加分项。首选的方法是shell脚本，因为shell应该在任何Linux机器上可用。
关于文件重命名的细节有一些有效的争论。
I think files with the same lowercase names should be overwritten; it's the user's problem. When checked out on a case-ignoring file system, it would overwrite the first one with the latter, too.
I would consider A-Z characters and transform them to a-z, everything else is just calling for problems (at least with source code).
The script would be needed to run a build on a Linux system, so I think changes to CVS or Subversion version control files should be omitted. After all, it's just a scratch checkout. Maybe an "export" is more appropriate.
下面是我的次优解决方案，使用Bash shell脚本:
#!/bin/bash
# First, rename all folders
for f in `find . -depth ! -name CVS -type d`; do
g=`dirname "$f"`/`basename "$f" | tr '[A-Z]' '[a-z]'`
if [ "xxx$f" != "xxx$g" ]; then
echo "Renaming folder $f"
mv -f "$f" "$g"
fi
done
# Now, rename all files
for f in `find . ! -type d`; do
g=`dirname "$f"`/`basename "$f" | tr '[A-Z]' '[a-z]'`
if [ "xxx$f" != "xxx$g" ]; then
echo "Renaming file $f"
mv -f "$f" "$g"
fi
done
文件夹都正确地重命名，mv在权限不匹配时不会询问问题，CVS文件夹也不会重命名(不幸的是，该文件夹内的CVS控制文件仍然会重命名)。
由于“find -depth”和“find | sort -r”都以可用于重命名的顺序返回文件夹列表，我更喜欢使用“-depth”来搜索文件夹。
最初的问题要求忽略SVN和CVS目录，这可以通过在find命令中添加-prune来实现。例如忽略CVS:
find . -name CVS -prune -o -exec mv '{}' `echo {} | tr '[A-Z]' '[a-z]'` \; -print
[编辑]我尝试了一下，在find中嵌入小写翻译并没有起作用，原因我实际上不明白。因此，将其修改为:
$> cat > tolower
#!/bin/bash
mv $1 `echo $1 | tr '[:upper:]' '[:lower:]'`
^D
$> chmod u+x tolower
$> find . -name CVS -prune -o -exec tolower '{}' \;
Ian
在这种情况下，我会使用Python，以避免乐观地假设没有空格或斜杠的路径。我还发现python2往往被安装在更多的地方，而不是重命名。
#!/usr/bin/env python2
import sys, os
def rename_dir(directory):
print('DEBUG: rename('+directory+')')
# Rename current directory if needed
os.rename(directory, directory.lower())
directory = directory.lower()
# Rename children
for fn in os.listdir(directory):
path = os.path.join(directory, fn)
os.rename(path, path.lower())
path = path.lower()
# Rename children within, if this child is a directory
if os.path.isdir(path):
rename_dir(path)
# Run program, using the first argument passed to this Python script as the name of the folder
rename_dir(sys.argv[1])
