我想测量执行一个函数所花费的时间。我没时间工作:

import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)

当前回答

在python3上:

from time import sleep, perf_counter as pc
t0 = pc()
sleep(1)
print(pc()-t0)

优雅而短小。

其他回答

还有一种使用timeit的方法:

from timeit import timeit

def func():
    return 1 + 1

time = timeit(func, number=1)
print(time)

测量时间(秒):

from timeit import default_timer as timer
from datetime import timedelta

start = timer()

# ....
# (your code runs here)
# ...

end = timer()
print(timedelta(seconds=end-start))

输出:

0:00:01.946339

timeit模块适合对一小段Python代码进行计时。它至少可以三种形式使用:

1-作为命令行模块

python2 -m timeit 'for i in xrange(10): oct(i)' 

2-对于短代码,将其作为参数传递。

import timeit
timeit.Timer('for i in xrange(10): oct(i)').timeit()

3-对于较长的代码,如:

import timeit
code_to_test = """
a = range(100000)
b = []
for i in a:
    b.append(i*2)
"""
elapsed_time = timeit.timeit(code_to_test, number=100)/100
print(elapsed_time)

这种独特的基于类的方法提供了可打印的字符串表示、可自定义的舍入,以及以字符串或浮点形式方便地访问经过的时间。它是用Python 3.7开发的。

import datetime
import timeit


class Timer:
    """Measure time used."""
    # Ref: https://stackoverflow.com/a/57931660/

    def __init__(self, round_ndigits: int = 0):
        self._round_ndigits = round_ndigits
        self._start_time = timeit.default_timer()

    def __call__(self) -> float:
        return timeit.default_timer() - self._start_time

    def __str__(self) -> str:
        return str(datetime.timedelta(seconds=round(self(), self._round_ndigits)))

用法:

# Setup timer
>>> timer = Timer()

# Access as a string
>>> print(f'Time elapsed is {timer}.')
Time elapsed is 0:00:03.
>>> print(f'Time elapsed is {timer}.')
Time elapsed is 0:00:04.

# Access as a float
>>> timer()
6.841332235
>>> timer()
7.970274425
import time

def getElapsedTime(startTime, units):
    elapsedInSeconds = time.time() - startTime
    if units == 'sec':
        return elapsedInSeconds
    if units == 'min':
        return elapsedInSeconds/60
    if units == 'hour':
        return elapsedInSeconds/(60*60)