var RequestQuerystring; (窗口。Onpopstate = function () { var匹配, pl = /\+/g， //用空格替换加法符号的正则表达式 搜索= /([^&=]+)=?([^&]*)/g， decode =函数(s){返回decodeURIComponent(s)。替换(pl， " "));}， Query = window.location.search.substring(1); RequestQuerystring = {}; While (match = search.exec(查询)) RequestQuerystring[decode(match[1])] = decode(match[2]); })（);

RequestQuerystring现在是一个包含所有参数的对象

试试这个工作演示http://jsfiddle.net/xy7cX/

火:

inArray: http://api.jquery.com/jQuery.inArray/

这应该会有帮助:)

code

var url = "http://myurl.com?sent=yes"

var pieces = url.split("?");
alert(pieces[1] + " ===== " + $.inArray("sent=yes", pieces));

使用这个

$.urlParam = function(name) {
  var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
  return results[1] || 0;
}

函数GetRequestParam(参数) ｛ Var res = null; 尝试{ var qs = decodeURIComponent(window.location.search.substring(1));//获取then之后的所有内容'?URI中的' Var ar = q .split('&'); 美元。Each (ar, function(a, b){ Var kv = b.split('='); If (param === kv[0]){ Res = kv[1]; 返回false;//打破循环 ｝ })； }捕捉(e) {} 返回res; ｝

这可能有点过分了，但是现在有一个非常流行的用于解析uri的库，叫做URI.js。

例子

var uri = "http://example.org/foo.html?technology=jquery&technology=css&blog=stackoverflow"; var components = URI.parse(uri); var query = URI.parseQuery(components['query']); document.getElementById("result").innerHTML = "URI = " + uri; document.getElementById("result").innerHTML += "<br>technology = " + query['technology']; // If you look in your console, you will see that this library generates a JS array for multi-valued queries! console.log(query['technology']); console.log(query['blog']); <script src="https://cdnjs.cloudflare.com/ajax/libs/URI.js/1.17.0/URI.min.js"></script> <span id="result"></span>

或者你可以用这个简洁的小函数，因为为什么解这么复杂?

function getQueryParam(param, defaultValue = undefined) {
    location.search.substr(1)
        .split("&")
        .some(function(item) { // returns first occurence and stops
            return item.split("=")[0] == param && (defaultValue = item.split("=")[1], true)
        })
    return defaultValue
}

当简化和联机时看起来更好:

单线解

var queryDict = {};
location.search.substr(1).split("&").forEach(function(item) {queryDict[item.split("=")[0]] = item.split("=")[1]})

result:
queryDict['sent'] // undefined or 'value'

但如果你有编码字符或多值键呢?

你最好看看这个答案:如何在JavaScript中获得查询字符串值?

偷偷高峰

"?a=1&b=2&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> queryDict
a: ["1", "5", "t e x t"]
b: ["2"]
c: ["3"]
d: [undefined]
e: [undefined, "http://w3schools.com/my test.asp?name=ståle&car=saab"]

> queryDict["a"][1] // "5"
> queryDict.a[1] // "5"