我想要一种从选定的列名直接生成列标签的通用方法,并且记得python的psycopg2模块支持这一特性。


当前回答

 # You can use this function
 def getColumns(cursorDescription):
     columnList = []
     for tupla in cursorDescription:
         columnList.append(tupla[0])
     return columnList 

其他回答

执行SQL查询后,编写2.7中编写的python脚本

total_fields = len(cursor.description)    
fields_names = [i[0] for i in cursor.description   
    Print fields_names

摘自Mark Lutz的《Programming Python》:

curs.execute("Select * FROM people LIMIT 0")
colnames = [desc[0] for desc in curs.description]

如果你想把你所有的数据放在一个带列名的Pandas数据框架中:

cur.execute("select * from tablename")
datapoints = cur.fetchall()
cols = [desc[0] for desc in cur.description]
df = pd.DataFrame((datapoints) , columns=[cols])
 # You can use this function
 def getColumns(cursorDescription):
     columnList = []
     for tupla in cursorDescription:
         columnList.append(tupla[0])
     return columnList 

如果你想获得一个已经关联列标头的pandas数据帧,试试这个:

import psycopg2, pandas

con=psycopg2.connect(
    dbname=DBNAME, 
    host=HOST, 
    port=PORT, 
    user=USER, 
    password=PASSWORD
)

sql = """
select * from x
"""

d = pandas.read_sql_query(sql,con)

con.close()

print(type(d))

print(pandas.DataFrame.head(d))