我知道我可以单独发出一个alter表,将表存储从MyISAM更改为InnoDB。

我想知道是否有一种方法可以快速将它们全部更改为InnoDB?


当前回答

对于转换MySql表存储引擎有许多方法:

使用MySql命令如下,转换为innodb (ALTER TABLE t1 ENGINE = innodb)或(ALTER TABLE t1 ENGINE = MyISAM)为MyISAM(你应该为每个单独的表这样做,t1是表名。) 编写一个在所有表上循环的脚本,并运行alter命令 使用一个已经可用的脚本来处理这个问题:https://github.com/rafihaidari/convert-mysql-tables-storage-engine

其他回答

当表很大时,最好从控制台进行操作

convert-to-innodb.sh

#!/usr/bin/env bash

# Usage: ./convert-to-innodb.sh 'db' 'user' 'password' | mysql 'db' -u  user -p password


set -eu

db="$1"
user="$2"
pass="$3"


sql="SET @DATABASE_NAME = '${db}';"

sql+="SELECT  CONCAT('ALTER TABLE \`', table_name, '\` ENGINE=InnoDB;') AS sql_statements
FROM    information_schema.tables AS tb
WHERE   table_schema = @DATABASE_NAME
AND     \`ENGINE\` = 'MyISAM'
AND     \`TABLE_TYPE\` = 'BASE TABLE'
ORDER BY table_name DESC;"

echo $sql | mysql -u${user} -p${pass} | tail -n +2 

在phpMyAdmin中使用此sql查询

SELECT CONCAT('ALTER TABLE ',table_schema,'.',table_name,' engine=InnoDB;') 
FROM information_schema.tables 
WHERE engine = 'MyISAM';

这是一个简单的php脚本。

<?php
    @error_reporting(E_ALL | E_STRICT);
    @ini_set('display_errors', '1');


    $con = mysql_connect('server', 'user', 'pass');
    $dbName = 'moodle2014';

    $sql = "SELECT table_name FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = '".$dbName."';";
    $rs = mysql_query($sql, $con);

    $count = 0;
    $ok = 0;
    while($row = mysql_fetch_array($rs)){
            $count ++;
            $tbl = $row[0];
            $sql = "ALTER TABLE ".$dbName.".".$tbl." ENGINE=INNODB;";
            $resultado = mysql_query($sql);
            if ($resultado){
                    $ok ++;
                    echo $sql."<hr/>";
            }
    }
    if ($count == $ok){
            echo '<div style="color: green"><b>ALL OK</b></div>';
    }else{
            echo '<div style="color: red"><b>ERRORS</b>Total tables: '.$count.', updated tables:'.$ok.'</div>';
    }

要为所有非系统模式中的所有表生成ALTER语句,按这些模式/表排序,运行以下命令:

SELECT  CONCAT('ALTER TABLE ',TABLE_SCHEMA,'.', table_name, ' ENGINE=InnoDB;') AS sql_statements
FROM    information_schema.tables
WHERE   TABLE_SCHEMA NOT IN ('mysql', 'information_schema', 'performance_schema', 'innodb', 'sys', 'tmp')
AND     `ENGINE` = 'MyISAM'
AND     `TABLE_TYPE` = 'BASE TABLE'
ORDER BY TABLE_SCHEMA, table_name DESC;

之后,通过客户端运行这些查询来执行修改。

答案基于上述答案,但改进了模式处理。

mysqli连接;

<?php

$host       = "host";
$user       = "user";
$pass       = "pss";
$database   = "db_name";


$connect = new mysqli($host, $user, $pass, $database);  

// Actual code starts here Dont forget to change db_name !!
$sql = "SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES
    WHERE TABLE_SCHEMA = 'db_name' 
    AND ENGINE = 'MyISAM'";

$rs = $connect->query($sql);

while($row = $rs->fetch_array())
{
    $tbl = $row[0];
    $sql = "ALTER TABLE `$tbl` ENGINE=INNODB";
    $connect->query($sql);
} ?>