如果finally块抛出异常,到底会发生什么?
具体来说,如果在finally块中途抛出异常会发生什么。这个块中的其余语句(之后)是否被调用?
我知道异常会向上传播。
如果finally块抛出异常,到底会发生什么?
具体来说,如果在finally块中途抛出异常会发生什么。这个块中的其余语句(之后)是否被调用?
我知道异常会向上传播。
当前回答
如果有一个异常挂起(当try块有finally但没有catch时),新异常将替换该异常。
如果没有异常挂起,它就像在finally块外抛出异常一样工作。
其他回答
几个月前,我也遇到过这样的事情,
private void RaiseException(String errorMessage)
{
throw new Exception(errorMessage);
}
private void DoTaskForFinally()
{
RaiseException("Error for finally");
}
private void DoTaskForCatch()
{
RaiseException("Error for catch");
}
private void DoTaskForTry()
{
RaiseException("Error for try");
}
try
{
/*lacks the exception*/
DoTaskForTry();
}
catch (Exception exception)
{
/*lacks the exception*/
DoTaskForCatch();
}
finally
{
/*the result exception*/
DoTaskForFinally();
}
为了解决这个问题,我做了一个实用类
class ProcessHandler : Exception
{
private enum ProcessType
{
Try,
Catch,
Finally,
}
private Boolean _hasException;
private Boolean _hasTryException;
private Boolean _hasCatchException;
private Boolean _hasFinnallyException;
public Boolean HasException { get { return _hasException; } }
public Boolean HasTryException { get { return _hasTryException; } }
public Boolean HasCatchException { get { return _hasCatchException; } }
public Boolean HasFinnallyException { get { return _hasFinnallyException; } }
public Dictionary<String, Exception> Exceptions { get; private set; }
public readonly Action TryAction;
public readonly Action CatchAction;
public readonly Action FinallyAction;
public ProcessHandler(Action tryAction = null, Action catchAction = null, Action finallyAction = null)
{
TryAction = tryAction;
CatchAction = catchAction;
FinallyAction = finallyAction;
_hasException = false;
_hasTryException = false;
_hasCatchException = false;
_hasFinnallyException = false;
Exceptions = new Dictionary<string, Exception>();
}
private void Invoke(Action action, ref Boolean isError, ProcessType processType)
{
try
{
action.Invoke();
}
catch (Exception exception)
{
_hasException = true;
isError = true;
Exceptions.Add(processType.ToString(), exception);
}
}
private void InvokeTryAction()
{
if (TryAction == null)
{
return;
}
Invoke(TryAction, ref _hasTryException, ProcessType.Try);
}
private void InvokeCatchAction()
{
if (CatchAction == null)
{
return;
}
Invoke(TryAction, ref _hasCatchException, ProcessType.Catch);
}
private void InvokeFinallyAction()
{
if (FinallyAction == null)
{
return;
}
Invoke(TryAction, ref _hasFinnallyException, ProcessType.Finally);
}
public void InvokeActions()
{
InvokeTryAction();
if (HasTryException)
{
InvokeCatchAction();
}
InvokeFinallyAction();
if (HasException)
{
throw this;
}
}
}
像这样使用
try
{
ProcessHandler handler = new ProcessHandler(DoTaskForTry, DoTaskForCatch, DoTaskForFinally);
handler.InvokeActions();
}
catch (Exception exception)
{
var processError = exception as ProcessHandler;
/*this exception contains all exceptions*/
throw new Exception("Error to Process Actions", exception);
}
但如果你想使用参数并返回类型,那就是另一回事了
如果有一个异常挂起(当try块有finally但没有catch时),新异常将替换该异常。
如果没有异常挂起,它就像在finally块外抛出异常一样工作。
异常向上传播,应该在更高的级别进行处理。如果不在更高的级别处理异常,应用程序将崩溃。“finally”块执行在抛出异常的地方停止。
无论是否存在异常,“finally”块都保证执行。
如果“finally”块在try块中发生异常后被执行, 如果这个异常没有被处理 如果finally块抛出异常
然后,try块中发生的原始异常将丢失。
public class Exception
{
public static void Main()
{
try
{
SomeMethod();
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
public static void SomeMethod()
{
try
{
// This exception will be lost
throw new Exception("Exception in try block");
}
finally
{
throw new Exception("Exception in finally block");
}
}
}
关于细节的好文章
传播异常。
对于这样的问题,我通常在Visual Studio中打开一个空的控制台应用程序项目,并编写一个小示例程序:
using System;
class Program
{
static void Main(string[] args)
{
try
{
try
{
throw new Exception("exception thrown from try block");
}
catch (Exception ex)
{
Console.WriteLine("Inner catch block handling {0}.", ex.Message);
throw;
}
finally
{
Console.WriteLine("Inner finally block");
throw new Exception("exception thrown from finally block");
Console.WriteLine("This line is never reached");
}
}
catch (Exception ex)
{
Console.WriteLine("Outer catch block handling {0}.", ex.Message);
}
finally
{
Console.WriteLine("Outer finally block");
}
}
}
当您运行程序时,您将看到执行catch和finally块的确切顺序。请注意,在抛出异常后,finally块中的代码将不会被执行(事实上,在这个示例程序中,Visual Studio甚至会警告你,它已经检测到不可访问的代码):
Inner catch block handling exception thrown from try block. Inner finally block Outer catch block handling exception thrown from finally block. Outer finally block
额外的评论
正如Michael Damatov指出的,try块中的异常如果不在(内部)catch块中处理,就会被“吃掉”。事实上,在上面的例子中,重新抛出的异常并没有出现在外层catch块中。为了更清楚地说明这一点,请看下面稍作修改的示例:
using System;
class Program
{
static void Main(string[] args)
{
try
{
try
{
throw new Exception("exception thrown from try block");
}
finally
{
Console.WriteLine("Inner finally block");
throw new Exception("exception thrown from finally block");
Console.WriteLine("This line is never reached");
}
}
catch (Exception ex)
{
Console.WriteLine("Outer catch block handling {0}.", ex.Message);
}
finally
{
Console.WriteLine("Outer finally block");
}
}
}
正如你可以从输出中看到的,内部异常被“丢失”(即被忽略):
Inner finally block Outer catch block handling exception thrown from finally block. Outer finally block