对于阿洛克·辛格尔的回答，这是一个更好的小变化

fp = open("file")
for i, line in enumerate(fp,1):
    if i == 26:
        # 26th line
    elif i == 30:
        # 30th line
    elif i > 30:
        break
fp.close()

我更喜欢这种方法，因为它更通用，即你可以在文件上使用它，在f.r edlines()的结果上，在StringIO对象上，无论什么:

def read_specific_lines(file, lines_to_read):
   """file is any iterable; lines_to_read is an iterable containing int values"""
   lines = set(lines_to_read)
   last = max(lines)
   for n, line in enumerate(file):
      if n + 1 in lines:
          yield line
      if n + 1 > last:
          return

>>> with open(r'c:\temp\words.txt') as f:
        [s for s in read_specific_lines(f, [1, 2, 3, 1000])]
['A\n', 'a\n', 'aa\n', 'accordant\n']

我认为这行得通

 open_file1 = open("E:\\test.txt",'r')
 read_it1 = open_file1.read()
 myline1 = []
 for line1 in read_it1.splitlines():
 myline1.append(line1)
 print myline1[0]

其中一些很可爱，但可以做得更简单:

start = 0 # some starting index
end = 5000 # some ending index
filename = 'test.txt' # some file we want to use

with open(filename) as fh:
    data = fin.readlines()[start:end]

print(data)

这将使用简单的列表切片，它加载整个文件，但大多数系统将适当地最小化内存使用，它比上面给出的大多数方法都快，并且适用于我的10G+数据文件。好运！

f = open(filename, 'r')
totalLines = len(f.readlines())
f.close()
f = open(filename, 'r')

lineno = 1
while lineno < totalLines:
    line = f.readline()

    if lineno == 26:
        doLine26Commmand(line)

    elif lineno == 30:
        doLine30Commmand(line)

    lineno += 1
f.close()

def getitems(iterable, items):
  items = list(items) # get a list from any iterable and make our own copy
                      # since we modify it
  if items:
    items.sort()
    for n, v in enumerate(iterable):
      if n == items[0]:
        yield v
        items.pop(0)
        if not items:
          break

print list(getitems(open("/usr/share/dict/words"), [25, 29]))
# ['Abelson\n', 'Abernathy\n']
# note that index 25 is the 26th item