假设connectionDetails是一个Python字典,那么像这样重构代码的最佳、最优雅、最“Python”的方式是什么呢?
if "host" in connectionDetails:
host = connectionDetails["host"]
else:
host = someDefaultValue
假设connectionDetails是一个Python字典,那么像这样重构代码的最佳、最优雅、最“Python”的方式是什么呢?
if "host" in connectionDetails:
host = connectionDetails["host"]
else:
host = someDefaultValue
当前回答
是这样的:
host = connectionDetails.get('host', someDefaultValue)
其他回答
虽然.get()是一个很好的习惯用法,但它比if/else慢(并且比try/慢,除非大多数时候字典中会出现键):
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="try:\n a=d[1]\nexcept KeyError:\n a=10")
0.07691968797894333
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="try:\n a=d[2]\nexcept KeyError:\n a=10")
0.4583777282275605
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="a=d.get(1, 10)")
0.17784020746671558
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="a=d.get(2, 10)")
0.17952161730158878
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="if 1 in d:\n a=d[1]\nelse:\n a=10")
0.10071221458065338
>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
... stmt="if 2 in d:\n a=d[2]\nelse:\n a=10")
0.06966537335119938
测试@Tim Pietzcker对Python 3.3.5中PyPy (5.2.0-alpha0)情况的怀疑,我发现.get()和if/else方式确实执行相似。实际上,在if/else情况下,如果条件和赋值涉及相同的键,似乎甚至只有一次查找(与有两次查找的上一种情况相比)。
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="try:\n a=d[1]\nexcept KeyError:\n a=10")
0.011889292989508249
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="try:\n a=d[2]\nexcept KeyError:\n a=10")
0.07310474599944428
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="a=d.get(1, 10)")
0.010391917996457778
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="a=d.get(2, 10)")
0.009348208011942916
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="if 1 in d:\n a=d[1]\nelse:\n a=10")
0.011475925013655797
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="if 2 in d:\n a=d[2]\nelse:\n a=10")
0.009605801998986863
>>>> timeit.timeit(setup="d={1:2, 3:4, 5:6, 7:8, 9:0}",
.... stmt="if 2 in d:\n a=d[2]\nelse:\n a=d[1]")
0.017342638995614834
你也可以像这样使用defaultdict:
from collections import defaultdict
a = defaultdict(lambda: "default", key="some_value")
a["blabla"] => "default"
a["key"] => "some_value"
你可以传递任何普通函数而不是lambda:
from collections import defaultdict
def a():
return 4
b = defaultdict(a, key="some_value")
b['absent'] => 4
b['key'] => "some_value"
对于多个不同的默认值,请尝试以下方法:
connectionDetails = { "host": "www.example.com" }
defaults = { "host": "127.0.0.1", "port": 8080 }
completeDetails = {}
completeDetails.update(defaults)
completeDetails.update(connectionDetails)
completeDetails["host"] # ==> "www.example.com"
completeDetails["port"] # ==> 8080
您可以使用dict.get()作为默认值。
d = {"a" :1, "b" :2}
x = d.get("a",5)
y = d.get("c",6)
# This will give
# x = 1, y = 6
# as the result
由于"a"在键中,x = d.t get("a",5)将返回相关值1。由于"c"不在键中,y = d.t get("c",6)将返回默认值6。