刚开始使用Xcode 4.5，我在控制台得到了这个错误:
警告:试图在< ViewController: 0x1ec3e000>上显示< finishViewController: 0x1e56e0a0 >，其视图不在窗口层次结构中!
视图仍在显示，应用程序中的一切都在正常工作。这是iOS 6的新功能吗?
这是我用来在视图之间更改的代码:
UIStoryboard *storyboard = self.storyboard;
finishViewController *finished =
[storyboard instantiateViewControllerWithIdentifier:@"finishViewController"];
[self presentViewController:finished animated:NO completion:NULL];
当前回答
我也有同样的问题。我必须嵌入一个导航控制器，并通过它呈现控制器。下面是示例代码。
- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
UIImagePickerController *cameraView = [[UIImagePickerController alloc]init];
[cameraView setSourceType:UIImagePickerControllerSourceTypeCamera];
[cameraView setShowsCameraControls:NO];
UIView *cameraOverlay = [[UIView alloc]initWithFrame:CGRectMake(0, 0, 768, 1024)];
UIImageView *imageView = [[UIImageView alloc]initWithImage:[UIImage imageNamed:@"someImage"]];
[imageView setFrame:CGRectMake(0, 0, 768, 1024)];
[cameraOverlay addSubview:imageView];
[cameraView setCameraOverlayView:imageView];
[self.navigationController presentViewController:cameraView animated:NO completion:nil];
// [self presentViewController:cameraView animated:NO completion:nil]; //this will cause view is not in the window hierarchy error
}
其他回答
它工作得很好，试试这个。链接
UIViewController *top = [UIApplication sharedApplication].keyWindow.rootViewController;
[top presentViewController:secondView animated:YES completion: nil];
你可以调用你的segue或present, push代码在这个块中:
override func viewDidLoad() {
super.viewDidLoad()
OperationQueue.main.addOperation {
// push or present the page inside this block
}
}
我也有同样的问题。我必须嵌入一个导航控制器，并通过它呈现控制器。下面是示例代码。
- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
UIImagePickerController *cameraView = [[UIImagePickerController alloc]init];
[cameraView setSourceType:UIImagePickerControllerSourceTypeCamera];
[cameraView setShowsCameraControls:NO];
UIView *cameraOverlay = [[UIView alloc]initWithFrame:CGRectMake(0, 0, 768, 1024)];
UIImageView *imageView = [[UIImageView alloc]initWithImage:[UIImage imageNamed:@"someImage"]];
[imageView setFrame:CGRectMake(0, 0, 768, 1024)];
[cameraOverlay addSubview:imageView];
[cameraView setCameraOverlayView:imageView];
[self.navigationController presentViewController:cameraView animated:NO completion:nil];
// [self presentViewController:cameraView animated:NO completion:nil]; //this will cause view is not in the window hierarchy error
}
斯威夫特5
我在viewDidLayoutSubviews中调用present，因为在viewDidAppear中呈现会在模态加载之前导致视图控制器的瞬间显示，这看起来像一个丑陋的故障
确保检查窗口是否存在并只执行一次代码
var alreadyPresentedVCOnDisplay = false
override func viewDidLayoutSubviews() {
super.viewDidLayoutSubviews()
// we call present in viewDidLayoutSubviews as
// presenting in viewDidAppear causes a split second showing
// of the view controller before the modal is loaded
guard let _ = view?.window else {
// window must be assigned
return
}
if !alreadyPresentedVCOnDisplay {
alreadyPresentedVCOnDisplay = true
present(...)
}
}
遗憾的是，这个公认的解决方案并不适用于我的案例。我试图在从另一个视图控制器unwind后导航到一个新的视图控制器。
我找到了一个解决方案，使用一个标志来指示哪个unwind segue被调用。
@IBAction func unwindFromAuthenticationWithSegue(segue: UIStoryboardSegue) {
self.shouldSegueToMainTabBar = true
}
@IBAction func unwindFromForgetPasswordWithSegue(segue: UIStoryboardSegue) {
self.shouldSegueToLogin = true
}
然后用present(_ viewcontrollertoppresent: UIViewController)来呈现想要的VC
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
let storyboard = UIStoryboard(name: "Main", bundle: nil)
if self.shouldSegueToMainTabBar {
let mainTabBarController = storyboard.instantiateViewController(withIdentifier: "mainTabBarVC") as! MainTabBarController
self.present(mainTabBarController, animated: true)
self.shouldSegueToMainTabBar = false
}
if self.shouldSegueToLogin {
let loginController = storyboard.instantiateViewController(withIdentifier: "loginVC") as! LogInViewController
self.present(loginController, animated: true)
self.shouldSegueToLogin = false
}
}
基本上，上面的代码将让我从login/SignUp VC捕获unwind并导航到仪表板，或者从forget password VC捕获unwind操作并导航到登录页面。
