我可能有一个像下面这样的数组:

[1, 4, 2, 2, 6, 24, 15, 2, 60, 15, 6]

或者,实际上,任何类似类型的数据部分的序列。我要做的是确保每个相同的元素只有一个。例如,上面的数组将变成:

[1, 4, 2, 6, 24, 15, 60]

请注意,删除了2、6和15的重复项,以确保每个相同的元素中只有一个。Swift是否提供了一种容易做到这一点的方法,还是我必须自己做?


当前回答

下面是使用自定义匹配函数使序列唯一的更灵活的方法。

extension Sequence where Iterator.Element: Hashable {

    func unique(matching: (Iterator.Element, Iterator.Element) -> Bool) -> [Iterator.Element] {

        var uniqueArray: [Iterator.Element] = []
        forEach { element in
            let isUnique = uniqueArray.reduce(true, { (result, item) -> Bool in
                return result && matching(element, item)
            })
            if isUnique {
                uniqueArray.append(element)
            }
        }
        return uniqueArray
    }
}

其他回答

使用Set或NSOrderedSet删除重复项,然后转换回数组:

let uniqueUnordered = Array(Set(array))
let uniqueOrdered = Array(NSOrderedSet(array: array))

如果你想保持秩序,那么就用这个

let fruits = ["apple", "pear", "pear", "banana", "apple"] 
let orderedNoDuplicates = Array(NSOrderedSet(array: fruits).map({ $0 as! String }))

这只是一个非常简单和方便的实现。具有相等元素的数组扩展中的计算属性。

extension Array where Element: Equatable {
    /// Array containing only _unique_ elements.
    var unique: [Element] {
        var result: [Element] = []
        for element in self {
            if !result.contains(element) {
                result.append(element)
            }
        }

        return result
    }
}

如果你把两个扩展都放在你的代码中,更快的Hashable版本将在可能的情况下使用,Equatable版本将用作备用版本。

public extension Sequence where Element: Hashable {
  /// The elements of the sequence, with duplicates removed.
  /// - Note: Has equivalent elements to `Set(self)`.
  @available(
  swift, deprecated: 5.4,
  message: "Doesn't compile without the constant in Swift 5.3."
  )
  var firstUniqueElements: [Element] {
    let getSelf: (Element) -> Element = \.self
    return firstUniqueElements(getSelf)
  }
}

public extension Sequence where Element: Equatable {
  /// The elements of the sequence, with duplicates removed.
  /// - Note: Has equivalent elements to `Set(self)`.
  @available(
  swift, deprecated: 5.4,
  message: "Doesn't compile without the constant in Swift 5.3."
  )
  var firstUniqueElements: [Element] {
    let getSelf: (Element) -> Element = \.self
    return firstUniqueElements(getSelf)
  }
}

public extension Sequence {
  /// The elements of the sequences, with "duplicates" removed
  /// based on a closure.
  func firstUniqueElements<Hashable: Swift.Hashable>(
    _ getHashable: (Element) -> Hashable
  ) -> [Element] {
    var set: Set<Hashable> = []
    return filter { set.insert(getHashable($0)).inserted }
  }

  /// The elements of the sequence, with "duplicates" removed,
  /// based on a closure.
  func firstUniqueElements<Equatable: Swift.Equatable>(
    _ getEquatable: (Element) -> Equatable
  ) -> [Element] {
    reduce(into: []) { uniqueElements, element in
      if zip(
        uniqueElements.lazy.map(getEquatable),
        AnyIterator { [equatable = getEquatable(element)] in equatable }
      ).allSatisfy(!=) {
        uniqueElements.append(element)
      }
    }
  }
}

如果顺序不重要,那么你总是可以使用这个Set初始化式。

这是swift 4.2中最简单的方法,如下所示的代码

let keyarray:NSMutableArray = NSMutableArray()

for  object in dataArr
{
    if !keysArray.contains(object){
        keysArray.add(object)
    }
}

print(keysArray)