给定一个数字列表,例如:

[1, 2, 3, 4, 5, ...]

我如何计算它们的总和:

1 + 2 + 3 + 4 + 5 + ...

我如何计算他们的两两平均值:

[(1+2)/2, (2+3)/2, (3+4)/2, (4+5)/2, ...]

当前回答

问题2: 对一组整数求和:

a = [2, 3, 5, 8]
sum(a)
# 18
# or you can do:
sum(i for i in a)
# 18

如果列表中包含整数作为字符串:

a = ['5', '6']
# import Decimal: from decimal import Decimal
sum(Decimal(i) for i in a)

其他回答

试试以下方法:

mylist = [1, 2, 3, 4]   

def add(mylist):
    total = 0
    for i in mylist:
        total += i
    return total

result = add(mylist)
print("sum = ", result)

保持简单:

def cool_sum(list: numbers):
    b = 0;
    for i in numbers:
        b += i
    return b;


a = [1, 2, 4]
print(cool_sum(a))

尝试使用列表理解。喜欢的东西:

new_list = [(old_list[i] + old_list[i+1])/2 for i in range(len(old_list-1))]

我只使用带有map()的

a = [1,2,3,4,5,6,7,8,9,10]
b = map(lambda x, y: (x+y)/2.0, fib[:-1], fib[1:])
print b
n = int(input("Enter the length of array: "))
list1 = []
for i in range(n):
    list1.append(int(input("Enter numbers: ")))
print("User inputs are", list1)

list2 = []
for j in range(0, n-1):
    list2.append((list1[j]+list1[j+1])/2)
print("result = ", list2)