我想向表中插入数据,但只插入数据库中不存在的数据。

这是我的代码:

ALTER PROCEDURE [dbo].[EmailsRecebidosInsert]
  (@_DE nvarchar(50),
   @_ASSUNTO nvarchar(50),
   @_DATA nvarchar(30) )
AS
BEGIN
   INSERT INTO EmailsRecebidos (De, Assunto, Data)
   VALUES (@_DE, @_ASSUNTO, @_DATA)
   WHERE NOT EXISTS ( SELECT * FROM EmailsRecebidos 
                   WHERE De = @_DE
                   AND Assunto = @_ASSUNTO
                   AND Data = @_DATA);
END

错误是:

Msg 156,级别15,状态1,程序EmailsRecebidosInsert,第11行 关键字WHERE附近的语法不正确。


当前回答

而不是以下代码

BEGIN
   INSERT INTO EmailsRecebidos (De, Assunto, Data)
   VALUES (@_DE, @_ASSUNTO, @_DATA)
   WHERE NOT EXISTS ( SELECT * FROM EmailsRecebidos 
                   WHERE De = @_DE
                   AND Assunto = @_ASSUNTO
                   AND Data = @_DATA);
END

替换为

BEGIN
   IF NOT EXISTS (SELECT * FROM EmailsRecebidos 
                   WHERE De = @_DE
                   AND Assunto = @_ASSUNTO
                   AND Data = @_DATA)
   BEGIN
       INSERT INTO EmailsRecebidos (De, Assunto, Data)
       VALUES (@_DE, @_ASSUNTO, @_DATA)
   END
END

更新:(感谢@Marc Durdin指出)

请注意,在高负载下,这有时仍然会失败,因为第二个连接可以在第一个连接执行INSERT之前通过IF NOT EXISTS测试,即竞争条件。关于为什么即使在事务中包装也不能解决这个问题,请参阅stackoverflow.com/a/3791506/1836776。

其他回答

如果你想检查一个键是否存在,你可以使用:

INSERT INTO tableName (...) VALUES (...) 
ON DUPLICATE KEY 
UPDATE ...

使用这个,如果已经有一个特定键的条目,那么它将更新,否则,它将插入。

INSERT命令没有WHERE子句——你必须这样写:

ALTER PROCEDURE [dbo].[EmailsRecebidosInsert]
  (@_DE nvarchar(50),
   @_ASSUNTO nvarchar(50),
   @_DATA nvarchar(30) )
AS
BEGIN
   IF NOT EXISTS (SELECT * FROM EmailsRecebidos 
                   WHERE De = @_DE
                   AND Assunto = @_ASSUNTO
                   AND Data = @_DATA)
   BEGIN
       INSERT INTO EmailsRecebidos (De, Assunto, Data)
       VALUES (@_DE, @_ASSUNTO, @_DATA)
   END
END

而不是以下代码

BEGIN
   INSERT INTO EmailsRecebidos (De, Assunto, Data)
   VALUES (@_DE, @_ASSUNTO, @_DATA)
   WHERE NOT EXISTS ( SELECT * FROM EmailsRecebidos 
                   WHERE De = @_DE
                   AND Assunto = @_ASSUNTO
                   AND Data = @_DATA);
END

替换为

BEGIN
   IF NOT EXISTS (SELECT * FROM EmailsRecebidos 
                   WHERE De = @_DE
                   AND Assunto = @_ASSUNTO
                   AND Data = @_DATA)
   BEGIN
       INSERT INTO EmailsRecebidos (De, Assunto, Data)
       VALUES (@_DE, @_ASSUNTO, @_DATA)
   END
END

更新:(感谢@Marc Durdin指出)

请注意,在高负载下,这有时仍然会失败,因为第二个连接可以在第一个连接执行INSERT之前通过IF NOT EXISTS测试,即竞争条件。关于为什么即使在事务中包装也不能解决这个问题,请参阅stackoverflow.com/a/3791506/1836776。

如果你的聚集索引只包含这些字段,那么简单、快速和可靠的选择是使用IGNORE_DUP_KEY

如果您使用IGNORE_DUP_KEY ON创建群集索引

然后你可以使用:

INSERT INTO EmailsRecebidos (De, Assunto, Data) VALUES (@_DE, @_ASSUNTO, @_DATA)

这在任何情况下都是安全的!

如下面的代码所解释:执行以下查询并自行验证。

CREATE TABLE `table_name` (
  `id` int(11) NOT NULL auto_increment,
  `name` varchar(255) NOT NULL,
  `address` varchar(255) NOT NULL,
  `tele` varchar(255) NOT NULL,
  PRIMARY KEY  (`id`)
) ENGINE=InnoDB;

插入一个记录:

INSERT INTO table_name (name, address, tele)
SELECT * FROM (SELECT 'Nazir', 'Kolkata', '033') AS tmp
WHERE NOT EXISTS (
    SELECT name FROM table_name WHERE name = 'Nazir'
) LIMIT 1;
Query OK, 1 row affected (0.00 sec)
Records: 1 Duplicates: 0 Warnings: 0

SELECT * FROM `table_name`;

+----+--------+-----------+------+
| id | name   | address   | tele |
+----+--------+-----------+------+
|  1 | Nazir  | Kolkata   | 033  |
+----+--------+-----------+------+

现在,尝试再次插入相同的记录:

INSERT INTO table_name (name, address, tele)
SELECT * FROM (SELECT 'Nazir', 'Kolkata', '033') AS tmp
WHERE NOT EXISTS (
    SELECT name FROM table_name WHERE name = 'Nazir'
) LIMIT 1;

Query OK, 0 rows affected (0.00 sec)
Records: 0  Duplicates: 0  Warnings: 0

+----+--------+-----------+------+
| id | name   | address   | tele |
+----+--------+-----------+------+
|  1 | Nazir  | Kolkata   | 033  |
+----+--------+-----------+------+

插入一条不同的记录:

INSERT INTO table_name (name, address, tele)
SELECT * FROM (SELECT 'Santosh', 'Kestopur', '044') AS tmp
WHERE NOT EXISTS (
    SELECT name FROM table_name WHERE name = 'Santosh'
) LIMIT 1;

Query OK, 1 row affected (0.00 sec)
Records: 1 Duplicates: 0 Warnings: 0

SELECT * FROM `table_name`;

+----+--------+-----------+------+
| id | name   | address   | tele |
+----+--------+-----------+------+
|  1 | Nazir  | Kolkata   | 033  |
|  2 | Santosh| Kestopur  | 044  |
+----+--------+-----------+------+